Find the pile capacity.

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Chapter 12, Problem 12.25P

To determine

Find the pile capacity.

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A driven closed-ended pile, circular in cross section, is show in below figure P10. Calculate the following: 1). the ultimate point load Qp, using Meyehof's equations (9.15) and (9.16); 2). The ultimate frictional resistance Q, with equations (9.40) through (9.44); 3). Calculate allowable load-carrying capacity for the pile with FS of 3. (K = 1.4; 8' = 0.80') 15.7 kN/m d' = 32° c' =0 3 m Groundwater table = 18.2 kN/m Ysat d' = 32° 3 m c = 0 Yat = 19.2 kN/m³ 4' = 40" c = 0 15 m 381 mm

A steel H-pile (section HP13 × 100) is driven by a hammer. The maximum rated hammer energy is 40 kip-ft, the weight of the ram is 12 kip, and the length of the pile is 90 ft. Also, we have coefficient of restitution pile cap = 2.4 kip, hammer efficiency = 0.85, number of blows for the last inch of penetration = 10, and E, = 30 × 10° lb/in.?. Estimate the pile capacity using Eq. (9.114). Take FS = 6. 0.35, weight of the %3D

P-2 A driven closed-ended pile, circular in cross section, is shown in the Figure. Calculate the following: Layer I Groundwater 3 m táble a. The ultimate point load using Meyerhof's procedure. 3 m Layer II b. The ultimate frictional resistance Qs. [Take K = 1.4 and ô'= 0.6º'] c. The allowable load of the pile (use FS = 3 15 m Layer II d. Calculate the (a), (b) and (c) if the layer III was a Clay soil with C,=80 kPa (use ca-method by Terzaghi and FS = 3) %3D Layer I Y = 15.7 kN/m³ 4' = 32° Layer II = 18.2 kN/m3 Ysat = 19.2 kN/m³ Layer III 381 mm Ysat 4' = 32° c' = 0 = 40° c' = 0 c' = 0