Chapter 11.6, Problem 5GP

To determine

To find: The hypothesis at 1% significance.

Answer to Problem 5GP

The alternate hypothesis is $\mu <20$ as it is the complement of the $\mu \ge 20$ .

Explanation of Solution

Given:

There are 12 ounces of juice in every can.

The sample of 68 cans is selected.

The mean of 11.95 ounces with the mean deviation of 0.15 ounce.

Calculation:

From the given data the null hypothesis $H_0$ and alternate hypothesis $H_a$ is given below as,

  $\begin{array}{l}{H}_0:\mu \ge 20\\ H_a:\mu <20\end{array}$

Thus, the claim is $\mu \ge 20$ as it is null hypothesis because of the equality. Thus, the alternate hypothesis is $\mu <20$ as it is the complement of the $\mu \ge 20$ .