Chapter 11.5, Problem 40WE

To determine

To solve: $a^2=154$ .

Answer to Problem 40WE

  $a=\pm 12.4$

Explanation of Solution

By using the property of square root as $x^2=\sqrt{a^2}$ implies $x=\pm a$ the given equation $a^2=154$ can be simplified as

  $\begin{array}{l}{a}^2=154\\ a=\pm \sqrt{154}\\ a=\pm 12.4\end{array}$