Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN: 9781680331141
Author: HOUGHTON MIFFLIN HARCOURT
Publisher: Houghton Mifflin Harcourt
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Chapter 11.2, Problem 21E

(a)

To determine

To identify the shape of each distribution.

(a)

Expert Solution
Check Mark

Answer to Problem 21E

Both the brands are skewed right.

Explanation of Solution

Given information: Box-and-whisker plot.

Calculation:

Both the brands are skewed right.

Fewer data plots are found to the right of the graph. The "tail" of the graph is pulled toward higher positive numbers, or to the right. The mean typically gets pulled toward the tail, and is greater than the median.

(b)

To determine

To find the range of upper 75% data.

(b)

Expert Solution
Check Mark

Answer to Problem 21E

Range of upper 75% of brand A= 3.5

Range of upper 75% of brand B= 2.5

Explanation of Solution

Given information: Box-and-whisker plot.

Formula Used: Range of the data= max.Q1

Calculation:

  Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015, Chapter 11.2, Problem 21E , additional homework tip  1

As the range of the data: max.Q1

  • Brand A

Range of upper 75% of brand A= max.Q1

So,

Range of upper 75% of brand A= 73.5

Hence,

Range of upper 75% of brand A= 3.5

  • Brand B

Range of upper 75% of brand B= max.Q1

So,

Range of upper 75% of brand B= 5.753.25

Hence,

Range of upper 75% of brand B= 2.50

(c)

To determine

To find the interquartile range of data.

(c)

Expert Solution
Check Mark

Answer to Problem 21E

Interquartile Range of brand A= 1.25

Interquartile Range of brand B= 1

Explanation of Solution

Given information: Box-and-whisker plot.

Formula Used: Interquartile Range of the data= Q3Q1

Calculation:

  Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015, Chapter 11.2, Problem 21E , additional homework tip  2

As the range of the data: max.Q1

  • Brand A

Interquartile Range of brand A= Q3Q1

So,

Interquartile Range of brand A= 4.753.5

Hence,

Interquartile Range of brand A= 1.25

  • Brand B

Interquartile Range of brand B= Q3Q1

So,

Interquartile Range of brand B= 4.253.25

Hence,

Interquartile Range of brand B= 1

(d)

To determine

To find the greater standard deviation.

(d)

Expert Solution
Check Mark

Answer to Problem 21E

Brand A has greater standard deviation

Explanation of Solution

Given information: Box-and-whisker plot.

Formula Used: Standard deviation = range4

Calculation:

The standard deviation is approximately equal to the  range4

Also,

The standard deviation is approximately equal to 34×IQR

Both estimates work best for normal distribution, i.e. distributions that are not skewed, and the first approximation works best if they are no outliers. They will later determine additional relations between the standard deviation for normally distributed data. That reminds another useful application for the IQR is to define outliers:

Outliers are data points that fall below Q11.5×IQR  or above Q3+1.5×IQR

  • Range A:

Range of brand A= 72

Now,

Range of brand A= 5

So,

Standard deviation = range4

Hence,

Standard deviation of brand A= 54=1.25

  • Range B:

Range of brand B = 5.752.25

Now,

Range of brand B = 3.50

So,

Standard deviation = range4

Hence,

Standard deviation of brand B = 3.504=0.87

(e)

To determine

To identify the brand with more battery life.

(e)

Expert Solution
Check Mark

Answer to Problem 21E

Brand A

Explanation of Solution

Given information: Box-and-whisker plot.

Calculation:

Range of brand A= 5

and

Range of brand B = 3.50

Hence,

Brand A will be choose because it has greater range than brand B.

Chapter 11 Solutions

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

Ch. 11.1 - Prob. 11ECh. 11.1 - Prob. 12ECh. 11.1 - Prob. 13ECh. 11.1 - Prob. 14ECh. 11.1 - Prob. 15ECh. 11.1 - Prob. 16ECh. 11.1 - Prob. 17ECh. 11.1 - Prob. 18ECh. 11.1 - Prob. 19ECh. 11.1 - Prob. 20ECh. 11.1 - Prob. 21ECh. 11.1 - Prob. 22ECh. 11.1 - Prob. 23ECh. 11.1 - Prob. 24ECh. 11.1 - Prob. 25ECh. 11.1 - Prob. 26ECh. 11.1 - Prob. 27ECh. 11.1 - Prob. 28ECh. 11.1 - Prob. 29ECh. 11.1 - Prob. 30ECh. 11.1 - Prob. 31ECh. 11.1 - Prob. 32ECh. 11.1 - Prob. 33ECh. 11.1 - Prob. 34ECh. 11.1 - Prob. 35ECh. 11.1 - Prob. 36ECh. 11.1 - Prob. 37ECh. 11.1 - Prob. 38ECh. 11.1 - Prob. 39ECh. 11.1 - Prob. 40ECh. 11.1 - Prob. 41ECh. 11.1 - Prob. 42ECh. 11.1 - Prob. 43ECh. 11.1 - Prob. 44ECh. 11.1 - Prob. 45ECh. 11.1 - Prob. 46ECh. 11.1 - Prob. 47ECh. 11.2 - Prob. 1ECh. 11.2 - Prob. 2ECh. 11.2 - Prob. 3ECh. 11.2 - Prob. 4ECh. 11.2 - Prob. 5ECh. 11.2 - Prob. 6ECh. 11.2 - Prob. 7ECh. 11.2 - Prob. 8ECh. 11.2 - Prob. 9ECh. 11.2 - Prob. 10ECh. 11.2 - Prob. 11ECh. 11.2 - Prob. 12ECh. 11.2 - Prob. 13ECh. 11.2 - Prob. 14ECh. 11.2 - Prob. 15ECh. 11.2 - Prob. 16ECh. 11.2 - Prob. 17ECh. 11.2 - Prob. 18ECh. 11.2 - Prob. 19ECh. 11.2 - Prob. 20ECh. 11.2 - Prob. 21ECh. 11.2 - Prob. 22ECh. 11.2 - Prob. 23ECh. 11.2 - Prob. 24ECh. 11.2 - Prob. 25ECh. 11.2 - Prob. 26ECh. 11.2 - Prob. 27ECh. 11.3 - Prob. 1ECh. 11.3 - Prob. 2ECh. 11.3 - Prob. 3ECh. 11.3 - Prob. 4ECh. 11.3 - Prob. 5ECh. 11.3 - Prob. 6ECh. 11.3 - Prob. 7ECh. 11.3 - Prob. 8ECh. 11.3 - Prob. 9ECh. 11.3 - Prob. 10ECh. 11.3 - Prob. 11ECh. 11.3 - Prob. 12ECh. 11.3 - Prob. 13ECh. 11.3 - Prob. 14ECh. 11.3 - Prob. 15ECh. 11.3 - Prob. 16ECh. 11.3 - Prob. 17ECh. 11.3 - Prob. 18ECh. 11.3 - Prob. 19ECh. 11.3 - Prob. 20ECh. 11.3 - Prob. 21ECh. 11.3 - Prob. 22ECh. 11.3 - Prob. 23ECh. 11.3 - Prob. 24ECh. 11.3 - Prob. 25ECh. 11.3 - Prob. 26ECh. 11.3 - Prob. 27ECh. 11.3 - Prob. 1QCh. 11.3 - Prob. 2QCh. 11.3 - Prob. 3QCh. 11.3 - Prob. 4QCh. 11.3 - Prob. 5QCh. 11.3 - Prob. 6QCh. 11.3 - Prob. 7QCh. 11.3 - Prob. 8QCh. 11.3 - Prob. 9QCh. 11.4 - Prob. 1ECh. 11.4 - Prob. 2ECh. 11.4 - Prob. 3ECh. 11.4 - Prob. 4ECh. 11.4 - Prob. 5ECh. 11.4 - Prob. 6ECh. 11.4 - Prob. 7ECh. 11.4 - Prob. 8ECh. 11.4 - Prob. 9ECh. 11.4 - Prob. 10ECh. 11.4 - Prob. 11ECh. 11.4 - Prob. 12ECh. 11.4 - Prob. 13ECh. 11.4 - Prob. 14ECh. 11.4 - Prob. 15ECh. 11.4 - Prob. 16ECh. 11.4 - Prob. 17ECh. 11.4 - Prob. 18ECh. 11.4 - Prob. 19ECh. 11.4 - Prob. 20ECh. 11.4 - Prob. 21ECh. 11.4 - Prob. 22ECh. 11.4 - Prob. 23ECh. 11.4 - Prob. 24ECh. 11.4 - Prob. 25ECh. 11.4 - Prob. 26ECh. 11.4 - Prob. 27ECh. 11.4 - Prob. 28ECh. 11.4 - Prob. 29ECh. 11.4 - Prob. 30ECh. 11.4 - Prob. 31ECh. 11.4 - Prob. 32ECh. 11.4 - Prob. 33ECh. 11.4 - Prob. 34ECh. 11.5 - Prob. 1ECh. 11.5 - Prob. 2ECh. 11.5 - Prob. 3ECh. 11.5 - Prob. 4ECh. 11.5 - Prob. 5ECh. 11.5 - Prob. 6ECh. 11.5 - Prob. 7ECh. 11.5 - Prob. 8ECh. 11.5 - Prob. 9ECh. 11.5 - Prob. 10ECh. 11.5 - Prob. 11ECh. 11.5 - Prob. 12ECh. 11.5 - Prob. 13ECh. 11.5 - Prob. 14ECh. 11.5 - Prob. 15ECh. 11.5 - Prob. 16ECh. 11.5 - Prob. 17ECh. 11.5 - Prob. 18ECh. 11.5 - Prob. 19ECh. 11.5 - Prob. 20ECh. 11.5 - Prob. 21ECh. 11.5 - Prob. 22ECh. 11.5 - Prob. 23ECh. 11.5 - Prob. 24ECh. 11.5 - Prob. 25ECh. 11.5 - Prob. 26ECh. 11.5 - Prob. 27ECh. 11.5 - Prob. 28ECh. 11.5 - Prob. 29ECh. 11.5 - Prob. 30ECh. 11.5 - Prob. 31ECh. 11.5 - Prob. 32ECh. 11.5 - Prob. 33ECh. 11 - Prob. 1CRCh. 11 - Prob. 2CRCh. 11 - Prob. 3CRCh. 11 - Prob. 4CRCh. 11 - Prob. 5CRCh. 11 - Prob. 6CRCh. 11 - Prob. 7CRCh. 11 - Prob. 8CRCh. 11 - Prob. 9CRCh. 11 - Prob. 10CRCh. 11 - Prob. 11CRCh. 11 - Prob. 12CRCh. 11 - Prob. 13CRCh. 11 - Prob. 14CRCh. 11 - Prob. 15CRCh. 11 - Prob. 1CTCh. 11 - Prob. 2CTCh. 11 - Prob. 3CTCh. 11 - Prob. 4CTCh. 11 - Prob. 5CTCh. 11 - Prob. 6CTCh. 11 - Prob. 7CTCh. 11 - Prob. 8CTCh. 11 - Prob. 9CTCh. 11 - Prob. 10CTCh. 11 - Prob. 1CACh. 11 - Prob. 2CACh. 11 - Prob. 3CACh. 11 - Prob. 4CACh. 11 - Prob. 5CACh. 11 - Prob. 6CACh. 11 - Prob. 7CACh. 11 - Prob. 8CACh. 11 - Prob. 9CA
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