(a)
To find: the equation of tangent to the circle given below at a given point.
(a)
Answer to Problem 64E
The equation of blue line is
Explanation of Solution
Given:
The equation is;
Concept used:
Some formula for straight line:
If two Slopes are perpendicular to each other:
Calculation:
First find the slope of the line segment with endpoints
By using the formula:
As any line tangent to a circle at point
So, the blue line is the picture is perpendicular to the line segment with the slope
Hence the equation of blue line is
(b)
To find:the other point on circle where tangent line is parallel to another tangent line.
(b)
Answer to Problem 64E
The point is
Explanation of Solution
Given:
The equation is;
Concept used:
The point slope form of linear equations.
If two line is parallel to each other.
Calculation:
Finally find the equation of the line that passes through the point
User the point slope form of linear equations.
The tangent will be parallel to the line found above at the point A that is symmetrical to
That is the point
Chapter 1 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning