Python Programming: An Introduction to Computer Science, 3rd Ed.
3rd Edition
ISBN: 9781590282755
Author: John Zelle
Publisher: Franklin, Beedle & Associates
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Chapter 11, Problem 6MC
Program Description Answer
The expression “x % 2 == 0” used to check if the given number is even or not.
Therefore, the correct option is “A”.
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The following statement should determine if x is not greater than 20. What is wrong with it?
Determine whether the following argument is valid or invalid.
type a truth table and a few words explaining why the truth table shows validity or invalidity.
If 12 divides 709,438 then 3 divides 709,438.
If the sum of the digits of 709,438 is divisible by 9 then 3 divides 709,438.
The sum of the digits of 709,438 is not divisible by 9.
Therefore, 12 does not divide 709,438.
Given four positive integers a, b, c, and d, compute the sum of those among them that are odd.
Because you have not yet learned how to make decisions, use the fact that for a positive integer n, the expression n % 2 is either 0 or 1. (not allowed to use an if statement or conditonal)
Chapter 11 Solutions
Python Programming: An Introduction to Computer Science, 3rd Ed.
Ch. 11 - Prob. 1TFCh. 11 - Prob. 2TFCh. 11 - Prob. 3TFCh. 11 - Prob. 4TFCh. 11 - Prob. 5TFCh. 11 - Prob. 6TFCh. 11 - Prob. 7TFCh. 11 - Prob. 8TFCh. 11 - Prob. 9TFCh. 11 - Prob. 1MC
Ch. 11 - Prob. 2MCCh. 11 - Prob. 3MCCh. 11 - Prob. 4MCCh. 11 - Prob. 5MCCh. 11 - Prob. 6MCCh. 11 - Prob. 7MCCh. 11 - Prob. 8MCCh. 11 - Prob. 9MCCh. 11 - Prob. 10MCCh. 11 - Prob. 1DCh. 11 - Prob. 2DCh. 11 - Prob. 1PECh. 11 - Prob. 2PECh. 11 - Prob. 3PECh. 11 - Prob. 5PECh. 11 - Prob. 6PECh. 11 - Prob. 7PECh. 11 - Prob. 8PECh. 11 - Prob. 9PECh. 11 - Prob. 10PECh. 11 - Prob. 11PECh. 11 - Prob. 12PECh. 11 - Prob. 15PECh. 11 - Prob. 16PECh. 11 - Prob. 18PECh. 11 - Prob. 19PE
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- Question: 1A perfect number is an integer that is the sum of its positive proper divisors (all divisors except itself). For example, 6 is a perfect number. The divisors of 6 except itself are 1,2 and 3. The sum of the proper divisors of 6 is 6. Thus 6 is a perfect number. You have to take integers as input and continue taking input until the word “STOP” is given as input. After taking the inputs you have to classify the integers as Perfect and Imperfect and store it in a dictionary(Please see the output for better understanding).[Note: You CANNOT use any built in functions EXCEPT input(),range(),print()]Sample Input :61082528100496530STOPSample Output:(No need to follow the output format. Just print the resultant dictionary.){Perfect: [6,28,496],Imperfect: [10,8,25,100,530]}arrow_forward%. Q21 Choice the correct answer from the following Used Cramer's Rule to find the value of the variables (X,Y,Z) in the following equations x + 2y + 3z = 17 3x + 2y + z = 11 X - 5y + z = -5 5 3 2 1 Y ( X 4 Z ۲:۱۷arrow_forwardCorrect answer only. Code and output screenshot. Nastia has 2 positive integers An and B. She characterizes that: The integer is acceptable in case it is detachable by A⋅B; In any case, the integer is almost acceptable, in case it is detachable by A. For instance, if A=6 and B=4, the integers 24 and 72 are acceptable, the integers 6, 660 and 12 are almost acceptable, the integers 16, 7 are neither acceptable nor almost great. Discover 3 unique positive integers x, y, and z to such an extent that precisely one of them is acceptable and the other 2 are almost acceptable, and x+y=z. Input The main line contains a solitary integer t (1≤t≤10000) — the number of experiments. The primary line of each experiment contains two integers An and B (1≤A≤106, 1≤B≤106) — numbers that Nastia has. Output For each experiment print: "Indeed" and 3 distinct positive integers x, y, and z (1≤x,y,z≤1018) to such an extent that precisely one of them is acceptable and the other 2…arrow_forward
- Question 4 Rewrite the following statement without using variables. Then, give an exam- ple that shows the statement is true. There exist two real numbers a and b such that ab > a + b. Question 5 Rewrite the following statement without using variables. Then, give an exam- ple that shows the statement is false. For any positive integer n, n³ > n².arrow_forwarddetermine if each following statement is True or Falsearrow_forwardIndicate whether the argument is valid or invalid. For valid arguments, prove that the argument is valid using a truth table. For invalid arguments, give truth values for the variables showing that the argument is not valid.arrow_forward
- Th e following sta tement should determine if x has a value other than 1 or 2.What is wrong with it?if (x ! = 1 11 x ! = 2)arrow_forwardWhat will be the outcome of '=if(A1>35,"Very high")' if cell A1 contain the numeric value 35? a. Very high b. Error c. FALSE d. 30arrow_forwardcan you help me with 1 to 3arrow_forward
- Given four positive integers a, b, c, and d, compute the sum of those among them that are odd. Because you have not yet learned how to make decisions, use the fact that for a positive integer n, the expression n % 2 is either 0 or 1. (not allowed to use an if statement)arrow_forwardDetermine whether the following argument is valid or invalid. Include a truth table and a few words explaining why the truth table shows validity or invalidity. If Hugo is a physics major or if Hugo is a math major, then he needs to take calculus. Hugo needs to take calculus or Hugo is a math major. Therefore, Hugo is a physics major or Hugo is a math major.arrow_forwardWrite an expression that returns a random integer between 34 and 55, inclusively.arrow_forward
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