The rate law has to be written for the given elementary reaction. Concept Introduction: For elementary reactions, rate law can be written using stoichiometry. The order of unimolecular reaction is one and bimolecular reaction is two. In a bimolecular reaction if the reactants are different then order with respect to each reactant will be one in order to make the overall order two.

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Answer 1

Question

Chapter 11, Problem 59QRT

(a)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

For elementary reactions, rate law can be written using stoichiometry. The order of unimolecular reaction is one and bimolecular reaction is two. In a bimolecular reaction if the reactants are different then order with respect to each reactant will be one in order to make the overall order two.

(b)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

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Consider the following reaction: 2 NO(g) + 2 H2(g) N2(g) + 2 H2O(g) (a) The rate law for this reaction is second order in NO(g) and first-order in H2(g). What is the rate law for this reaction? (b) If the rate constant for this reaction at a certain temperature is 9.70e+04, what is the reaction rate when [NO(g)] = 0.0560 M and [H2(g)] = 0.119 M?Rate = M/s.(c) What is the reaction rate when the concentration of NO(g) is doubled, to 0.112 M while the concentration of H2(g) is 0.119 M?Rate = M/s

Consider the following reaction: 4 HBr(g) + O2(g) 2 H2O(g) + 2 Br2(g)(a) The rate law for this reaction is first order in HBr(g) and first order in O2(g). What is the rate law for this reaction?(b) If the rate constant for this reaction at a certain temperature is 8.80e+03, what is the reaction rate when [HBr(g)] = 0.00429 M and [O2(g)] = 0.00758 M?Rate = _______ M/s.(c) What is the reaction rate when the concentration of HBr(g) is doubled, to 0.00858 M while the concentration of O2(g) is 0.00758 M?Rate = _______ M/s

Consider the following reaction: 2 NO(g) + 2 H2(g) N2(g) + 2 H2O(g) (a) The rate law for this reaction is second order in NO(g) and first order in H2(g). What is the rate law for this reaction?(b) If the rate constant for this reaction at a certain temperature is 79200, what is the reaction rate when [NO(g)] = 0.0852 M and [H2(g)] = 0.137 M?Rate =____ M/s.(c) What is the reaction rate when the concentration of NO(g) is doubled, to 0.170 M while the concentration of H2(g) is 0.137 M?Rate = ____ M/s

Answer 2

Question

Chapter 11, Problem 59QRT

(a)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

For elementary reactions, rate law can be written using stoichiometry. The order of unimolecular reaction is one and bimolecular reaction is two. In a bimolecular reaction if the reactants are different then order with respect to each reactant will be one in order to make the overall order two.

(b)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

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Answer 3

Question

Chapter 11, Problem 59QRT

(a)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

For elementary reactions, rate law can be written using stoichiometry. The order of unimolecular reaction is one and bimolecular reaction is two. In a bimolecular reaction if the reactants are different then order with respect to each reactant will be one in order to make the overall order two.

(b)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

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Answer 4

Question

Chapter 11, Problem 59QRT

(a)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

For elementary reactions, rate law can be written using stoichiometry. The order of unimolecular reaction is one and bimolecular reaction is two. In a bimolecular reaction if the reactants are different then order with respect to each reactant will be one in order to make the overall order two.

(b)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

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Answer 5

Chapter 11, Problem 59QRT

(a)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

For elementary reactions, rate law can be written using stoichiometry. The order of unimolecular reaction is one and bimolecular reaction is two. In a bimolecular reaction if the reactants are different then order with respect to each reactant will be one in order to make the overall order two.

(b)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

Answer 6

Chapter 11, Problem 59QRT

(a)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

For elementary reactions, rate law can be written using stoichiometry. The order of unimolecular reaction is one and bimolecular reaction is two. In a bimolecular reaction if the reactants are different then order with respect to each reactant will be one in order to make the overall order two.

Answer 7

Chapter 11, Problem 59QRT

(a)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

For elementary reactions, rate law can be written using stoichiometry. The order of unimolecular reaction is one and bimolecular reaction is two. In a bimolecular reaction if the reactants are different then order with respect to each reactant will be one in order to make the overall order two.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

Answer 9

(b)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

Answer 10

(c)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

Answer 11

(c)

Interpretation Introduction

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 11.1 - For the reaction of crystal violet with NaOH(aq),...Ch. 11.1 - (a) From data in Table 11.1, calculate the rate of...Ch. 11.1 - For the reaction 4NO2(g)+O2(g)2N2O5(g) (a) express...Ch. 11.1 - Instantaneous rates for the reaction of hydroxide...Ch. 11.1 - Prob. 11.3CE Ch. 11.2 - Prob. 11.4E Ch. 11.2 - Prob. 11.3PSP Ch. 11.2 - Prob. 11.5E Ch. 11.3 - Prob. 11.4PSP Ch. 11.3 - Prob. 11.5PSP

Solution Summary: The author explains how the rate law can be written using stoichiometry for elementary reactions.

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Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

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Chapter 11 Solutions

Solution Summary: The author explains how the rate law can be written using stoichiometry for elementary reactions.

Videos

Interpretation: The rate law has to be written for the given elementary reaction. Concept Introduction: Refer to part (a).

Interpretation: The rate law has to be written for the given elementary reaction. Concept Introduction: Refer to part (a).

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Chapter 11 Solutions

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).

Interpretation:

The rate law has to be written for the given elementary reaction.

Concept Introduction:

Refer to part (a).