a.
To calculate: The area ratio of region ⏸ and region ⏸.
a.

Answer to Problem 32RP
The area ratio is 5:4 .
Explanation of Solution
Given information:
Side AC = 9,
Side BC = 6.
Formula used:
The below similar figures theorem is used:
If two
Calculation:
Triangle in region ⏸ is similar to triangle in region ⏸. These two triangles are similar to triangle in region ⏸ and ⏸.
AⅠAⅡ=(s1s2)2AⅡAⅠ+AⅡ=(BCAC)2=(69)2=(23)2=49−−−−Equation1AⅠAⅠ+AⅡ=99−49=59−−−−Equation2
Dividing Equation 1 by Equation 2, we get
AⅠAⅡ=(5949)=54
b.
To find: The area ratio of region ⏸ and region ⏸.
b.

Answer to Problem 32RP
The area ratio is 25:39 .
Explanation of Solution
Given information:
Side QS = 10,
Side SP = 6.
Formula used:
The below similar figures theorem is used:
If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of ratio of their corresponding sides. This proves that the ratio of the area of two similar triangles is proportional to the squares of the corresponding sides of both the triangles.
Calculation:
Triangle in region ⏸ is similar to triangle in region ⏸. These two triangles are similar to triangle in region ⏸ and ⏸.
AⅠAⅠ+AⅡ=(QSQP)2=(58)2=2564−−−−Equation1AⅡAⅠ+AⅡ=6464−2564=3964−−−−Equation2
Dividing Equation 1 by Equation 2, we get
AⅠAⅡ=(25643964)=2539=25:39
Chapter 11 Solutions
Geometry For Enjoyment And Challenge
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