(a)
To find:the number ofstudents in the two way table and the percent of thesmoking students
(a)
Answer to Problem 20E
Table describes total 5375 students.18.7% of students smoke.
Explanation of Solution
Given:
Calculation:
Table describes total 5375 students. 18.7% of students smoke.
Parent’s Smoking Behaviour | ||||||
Neither Parent Smoke | One Parent Smoke | Both Parents Smoke | Total | Percent | ||
Student does not smoke | 1168 | 1823 | 1380 | 4371 | ||
Students smoke | 188 | 416 | 400 | 1004 | ||
Total | 1356 | 2239 | 1780 | 5375 | ||
Percent | 25.2% | 41.7% | 33.1% |
Conclusion:
Hence,table describes total 5375 students. 18.7% of students smoke.
(b)
To explain: the marginal distribution of parents smoking behaviour.
(b)
Answer to Problem 20E
Marginal Distribution Table | |||||||
Parents Smoking Behaviour | Student Does not Smoke | Student Smokes | Row Total (count) | Percentage | |||
Neither Parent Smoke | 1168 | 188 | 1356 | 0.2523 | 36.8% | ||
One Parent Smoke | 1823 | 416 | 2239 | 0.4166 | 24.1% | ||
Both Parents Smoke | 1380 | 400 | 1780 | 0.3312 | 39.1% | ||
Total | 4371 | 1004 | 5375 | 1 | 100 |
Explanation of Solution
Formula Used:
Marginal Distribution Percentage:
Calculation:
The marginal distribution of parents smoking habit is shown in table below:
Marginal Distribution Percentage:
Table Total=5375
Marginal Distribution Table | |||||||
Parents Smoking Behaviour | Student Does not Smoke | Student Smokes | Row Total (count) | Percentage | |||
Neither Parent Smoke | 1168 | 188 | 1356 | 0.2523 | 36.8% | ||
One Parent Smoke | 1823 | 416 | 2239 | 0.4166 | 24.1% | ||
Both Parents Smoke | 1380 | 400 | 1780 | 0.3312 | 39.1% | ||
Total | 4371 | 1004 | 5375 | 1 | 100 |
Conclusion:
Hence,the marginal distribution of parents smoking behaviour is shown.
Chapter 1 Solutions
The Practice of Statistics for AP - 4th Edition
Additional Math Textbook Solutions
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