The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
Question
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Chapter 1, Problem 15PT
To determine

To state: Comparison of the distribution of home runs for American league and national league graphical method and elaborate it.

Expert Solution & Answer
Check Mark

Answer to Problem 15PT

Graphical representation of the distribution of home runs:

  The Practice of Statistics for AP - 4th Edition, Chapter 1, Problem 15PT , additional homework tip 1

Explanation of Solution

Given information:

American league: 3540434951545758586468687577

National league: 2931424647484853555555636367

Calculation:

Graphical representation of the distribution of home runs for the two leaugues is as below:

  The Practice of Statistics for AP - 4th Edition, Chapter 1, Problem 15PT , additional homework tip 2

The American League teams hit more home runs than National League teams in the year 1994 . For illustrating this, the median for American league was 57.5 while the median for national league was only 50.5 .

Additionally, the low value for the NL is much lower than in the AL ( 29 versus 35 ) and the high value in the AL is much higher than that in the NL ( 77 versus 67 ).

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Chapter 1, Problem 14PT
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Chapter 2.1, Problem 1.1CYU

Chapter 1 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 1.1 - Prob. 1.1CYUCh. 1.1 - Prob. 1.2CYUCh. 1.1 - Prob. 2.2CYUCh. 1.1 - Prob. 9ECh. 1.1 - Prob. 10ECh. 1.1 - Prob. 11ECh. 1.1 - Prob. 12ECh. 1.1 - Prob. 13ECh. 1.1 - Prob. 14ECh. 1.1 - Prob. 15E
Ch. 1.1 - Prob. 16ECh. 1.1 - Prob. 17ECh. 1.1 - Prob. 18ECh. 1.1 - Prob. 19ECh. 1.1 - Prob. 20ECh. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.2 - Prob. 1.1CYUCh. 1.2 - Prob. 1.2CYUCh. 1.2 - Prob. 1.3CYUCh. 1.2 - Prob. 1.4CYUCh. 1.2 - Prob. 2.1CYUCh. 1.2 - Prob. 2.2CYUCh. 1.2 - Prob. 2.3CYUCh. 1.2 - Prob. 2.4CYUCh. 1.2 - Prob. 3.1CYUCh. 1.2 - Prob. 3.2CYUCh. 1.2 - Prob. 4.1CYUCh. 1.2 - Prob. 4.2CYUCh. 1.2 - Prob. 4.3CYUCh. 1.2 - Prob. 4.4CYUCh. 1.2 - Prob. 37ECh. 1.2 - Prob. 38ECh. 1.2 - Prob. 39ECh. 1.2 - Prob. 40ECh. 1.2 - Prob. 41ECh. 1.2 - Prob. 42ECh. 1.2 - Prob. 43ECh. 1.2 - Prob. 44ECh. 1.2 - Prob. 45ECh. 1.2 - Prob. 46ECh. 1.2 - Prob. 47ECh. 1.2 - Prob. 48ECh. 1.2 - Prob. 49ECh. 1.2 - Prob. 50ECh. 1.2 - Prob. 51ECh. 1.2 - Prob. 52ECh. 1.2 - Prob. 53ECh. 1.2 - Prob. 54ECh. 1.2 - Prob. 55ECh. 1.2 - Prob. 56ECh. 1.2 - Prob. 57ECh. 1.2 - Prob. 58ECh. 1.2 - Prob. 59ECh. 1.2 - Prob. 60ECh. 1.2 - Prob. 61ECh. 1.2 - Prob. 62ECh. 1.2 - Prob. 63ECh. 1.2 - Prob. 64ECh. 1.2 - Prob. 65ECh. 1.2 - Prob. 66ECh. 1.2 - Prob. 67ECh. 1.2 - Prob. 68ECh. 1.2 - Prob. 69ECh. 1.2 - Prob. 70ECh. 1.2 - Prob. 71ECh. 1.2 - Prob. 72ECh. 1.2 - Prob. 73ECh. 1.2 - Prob. 74ECh. 1.2 - Prob. 75ECh. 1.2 - Prob. 76ECh. 1.2 - Prob. 77ECh. 1.2 - Prob. 78ECh. 1.3 - Prob. 1.1CYUCh. 1.3 - Prob. 1.2CYUCh. 1.3 - Prob. 1.3CYUCh. 1.3 - Prob. 1.4CYUCh. 1.3 - Prob. 2.1CYUCh. 1.3 - Prob. 2.2CYUCh. 1.3 - Prob. 2.3CYUCh. 1.3 - Prob. 2.4CYUCh. 1.3 - Prob. 3.1CYUCh. 1.3 - Prob. 3.2CYUCh. 1.3 - Prob. 3.3CYUCh. 1.3 - Prob. 3.4CYUCh. 1.3 - Prob. 79ECh. 1.3 - Prob. 80ECh. 1.3 - Prob. 81ECh. 1.3 - Prob. 82ECh. 1.3 - Prob. 83ECh. 1.3 - Prob. 84ECh. 1.3 - Prob. 85ECh. 1.3 - Prob. 86ECh. 1.3 - Prob. 87ECh. 1.3 - Prob. 88ECh. 1.3 - Prob. 89ECh. 1.3 - Prob. 90ECh. 1.3 - Prob. 91ECh. 1.3 - Prob. 92ECh. 1.3 - Prob. 93ECh. 1.3 - Prob. 94ECh. 1.3 - Prob. 95ECh. 1.3 - Prob. 96ECh. 1.3 - Prob. 97ECh. 1.3 - Prob. 98ECh. 1.3 - Prob. 99ECh. 1.3 - Prob. 100ECh. 1.3 - Prob. 101ECh. 1.3 - Prob. 102ECh. 1.3 - Prob. 103ECh. 1.3 - Prob. 104ECh. 1.3 - Prob. 105ECh. 1.3 - Prob. 106ECh. 1.3 - Prob. 107ECh. 1.3 - Prob. 108ECh. 1.3 - Prob. 109ECh. 1.3 - Prob. 110ECh. 1.3 - Prob. 111ECh. 1.3 - Prob. 112ECh. 1.3 - Prob. 113ECh. 1 - Prob. 1CYUCh. 1 - Prob. 2CYUCh. 1 - Prob. 1ECh. 1 - Prob. 2ECh. 1 - Prob. 3ECh. 1 - Prob. 4ECh. 1 - Prob. 5ECh. 1 - Prob. 6ECh. 1 - Prob. 7ECh. 1 - Prob. 8ECh. 1 - Prob. 1CRECh. 1 - Prob. 2CRECh. 1 - Prob. 3CRECh. 1 - Prob. 4CRECh. 1 - Prob. 5CRECh. 1 - Prob. 6CRECh. 1 - Prob. 7CRECh. 1 - Prob. 8CRECh. 1 - Prob. 9CRECh. 1 - Prob. 10CRECh. 1 - Prob. 1PTCh. 1 - Prob. 2PTCh. 1 - Prob. 3PTCh. 1 - Prob. 4PTCh. 1 - Prob. 5PTCh. 1 - Prob. 6PTCh. 1 - Prob. 7PTCh. 1 - Prob. 8PTCh. 1 - Prob. 9PTCh. 1 - Prob. 10PTCh. 1 - Prob. 11PTCh. 1 - Prob. 12PTCh. 1 - Prob. 13PTCh. 1 - Prob. 14PTCh. 1 - Prob. 15PT

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