Chapter 11, Problem 11.58SP

(a)

Interpretation Introduction

Interpretation:

The molality of prepared solution has to be calculated.

Concept introduction:

Molality of a solution also called as molal concentration can be defined as the mass of solute in grams to the mass of the solvent in kilograms. It can be given by the equation,

$\text{Molality}\text{(mol}{\text{kg}}^{\text{-1}}\text{)}\text{= }\frac{\text{Mass}\text{of}\text{solute}\text{(in}\text{g)}}{\text{Mass}\text{of}\text{solvent}\text{(in}\text{kg)}}$

(b)

Interpretation Introduction

Interpretation:

The mole fraction of prepared solution has to be calculated.

Concept introduction:

Mole fraction of a compound can be defined as the number of moles of a substance to the total number of moles present in them. The mole fraction can be calculated by,

$\text{Mole}\text{fraction}\text{of}\text{compound}\text{=}\frac{\text{Number}\text{of}\text{moles(in}\text{mol)}}{\text{Total}\text{number}\text{of}\text{moles(in}\text{mol)}}$