(a)
To find the parametric equations for the given projectile.
(a)
Answer to Problem 94E
The parametric equations are-
Explanation of Solution
Consider an arrow being released by an archer from a bow at a point 5 feet above the ground.
Now, the motion of the arrow will be that of a horizontal projectile.
The initial velocity is 225 feet persecond and it makes an angle of 15 degree with the horizontal.
Therefore,
Therefore, the horizontal displacement is
and vertical displacement is
Therefore, the parametric equations are
Therefore, the orientation is downwards or from left to right.
Now, eliminate the parameter.
Substitute the value of from the first equation into second equation.
Therefore, the rectangular equation is
To find out the distance travelled.
Explanation of Solution
Now, assume the ground to be level. Therefore, the arrow hits the ground after covering horizontal range. Therefore, distance travelled
feet.
To find out how the maximum height.
Explanation of Solution
The graph of the path of the arrow is shown below.
From the graph, the highest height
Also, at the maximum height
To find out the time for which arrow is in the air during the time of flight.
Explanation of Solution
The arrow is in the air during the time of flight
seconds.
Chapter 10 Solutions
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