EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
4th Edition
ISBN: 9781337516853
Author: Larson
Publisher: CENGAGE CO
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Concept explainers

Rate of Change
The relation between two quantities which displays how much greater one quantity is than another is called ratio.
Slope
The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as:
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Question
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Chapter 10.4, Problem 52E

  (a)

To determine

To calculate: The coordinates of the explosion if station A detects the explosion 4 seconds before station B.

  (a)

Expert Solution
Check Mark

Answer to Problem 52E

The coordinates of the explosion are (3300,−2750) .

Explanation of Solution

Given information:

Two listening stations A and Bare located at (3300,0) and (−3300,0) respectively and station A detects the explosion 4 seconds before station B.

Formula used:

The equation of horizontal hyperbola is (x−h)2a2−(y−k)2b2=1 , here (h,k) is the center, vertices are a units from center and foci are c units from center and c2=a2+b2 .

Calculation:

Consider two listening stations A and B are located at (3300,0) and (−3300,0) respectively and station A detects the explosion 4 seconds before station B.

Observe that it is in shape of hyperbola whose transverse axis is horizontal.

Since, station A detects the explosion first let A be the foci of the hyperbola and hyperbola is centered at origin.

Now station B is located 1100 feet away from station A, so explosion occurs on the line x=3300 .

Recall that the equation of horizontal hyperbola is (x−h)2a2−(y−k)2b2=1 , here (h,k) is the center, vertices are a units from center and foci are c units from center and c2=a2+b2 .

Here center is origin so (h,k)=(0,0) and c=3300 .

Since, it took 4 seconds for sound to travel from A to B, so,

  4(1100)=2aa=2200

Use the c2=a2+b2 to compute the value of b,

  33002=22002+b2b2=6050000

Now, substitute a2=4840000,b2=6050000,h=0 and k=0 in the equation (x−h)2a2−(y−k)2b2=1 .

  x24840000−y26050000=1

Now, the explosion occurs on the line x=3300 . Substitute x=3300 in the above equations,

  330024840000−y26050000=1y2=7562500y=±2750

Now, the explosion must be away from the station B than the station A, so explosion must occur in fourth quadrant. Therefore, y=−2750 .

Thus, the coordinates of the explosion are (3300,−2750) .

  (b)

To determine

To calculate: The coordinates of the explosion if station A detects the explosion 1 second before station C.

  (b)

Expert Solution
Check Mark

Answer to Problem 52E

The coordinates of the explosion are (3300,−2750) .

Explanation of Solution

Given information:

Two listening stations A and C are located at (3300,0) and (3300,1100) respectively and station A detects the explosion 1 second before station C.

Formula used:

The equation of horizontal hyperbola is (x−h)2a2−(y−k)2b2=1 , here (h,k) is the center, vertices are a units from center and foci are c units from center and c2=a2+b2 .

Calculation:

Consider two listening stations A and B are located at (3300,0) and (3300,1100) respectively and station A detects the explosion 1 second before station C.

Observe that it is in shape of hyperbola whose transverse axis is horizontal.

Since, station A detects the explosion first let A be the foci of the hyperbola and hyperbola is centered at origin.

Now station B is located 1100 feet away from station A, so explosion occurs on the line x=3300 .

Recall that the equation of horizontal hyperbola is (x−h)2a2−(y−k)2b2=1 , here (h,k) is the center, vertices are a units from center and foci are c units from center and c2=a2+b2 .

Here center is origin so (h,k)=(0,0) and c=3300 .

Since, it took 4 seconds for sound to travel from A to B, so,

  4(1100)=2aa=2200

Use the c2=a2+b2 to compute the value of b,

  33002=22002+b2b2=6050000

Now, substitute a2=4840000,b2=6050000,h=0 and k=0 in the equation (x−h)2a2−(y−k)2b2=1 .

  x24840000−y26050000=1

Now, the explosion occurs on the line x=3300 . Substitute x=3300 in the above equations,

  330024840000−y26050000=1y2=7562500y=±2750

Now, the explosion must be away from the station B than the station A, so explosion must occur in fourth quadrant. Therefore, y=−2750 .

Thus, the coordinates of the explosion are (3300,−2750) .

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Chapter 10.4, Problem 51E
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Chapter 10.4, Problem 53E

Chapter 10 Solutions

EBK PRECALCULUS W/LIMITS

Ch. 10.1 - Prob. 1ECh. 10.1 - Prob. 2ECh. 10.1 - Prob. 3ECh. 10.1 - Prob. 4ECh. 10.1 - Prob. 5ECh. 10.1 - Prob. 6ECh. 10.1 - Prob. 7ECh. 10.1 - Prob. 8ECh. 10.1 - Prob. 9ECh. 10.1 - Prob. 10E
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Prob. 65ECh. 10.7 - Prob. 66ECh. 10.7 - Prob. 67ECh. 10.7 - Prob. 68ECh. 10.7 - Prob. 69ECh. 10.7 - Prob. 70ECh. 10.7 - Prob. 71ECh. 10.7 - Prob. 72ECh. 10.7 - Prob. 73ECh. 10.7 - Prob. 74ECh. 10.7 - Prob. 75ECh. 10.7 - Prob. 76ECh. 10.7 - Prob. 77ECh. 10.7 - Prob. 78ECh. 10.7 - Prob. 79ECh. 10.7 - Prob. 80ECh. 10.7 - Prob. 81ECh. 10.7 - Prob. 82ECh. 10.7 - Prob. 83ECh. 10.7 - Prob. 84ECh. 10.7 - Prob. 85ECh. 10.7 - Prob. 86ECh. 10.7 - Prob. 87ECh. 10.7 - Prob. 88ECh. 10.7 - Prob. 89ECh. 10.7 - Prob. 90ECh. 10.7 - Prob. 91ECh. 10.7 - Prob. 92ECh. 10.7 - Prob. 93ECh. 10.7 - Prob. 94ECh. 10.7 - Prob. 95ECh. 10.7 - Prob. 96ECh. 10.7 - Prob. 97ECh. 10.7 - Prob. 98ECh. 10.7 - Prob. 99ECh. 10.7 - Prob. 100ECh. 10.7 - Prob. 101ECh. 10.7 - Prob. 102ECh. 10.7 - Prob. 103ECh. 10.7 - Prob. 104ECh. 10.7 - Prob. 105ECh. 10.7 - Prob. 106ECh. 10.7 - Prob. 107ECh. 10.7 - Prob. 108ECh. 10.7 - Prob. 109ECh. 10.7 - Prob. 110ECh. 10.7 - Prob. 111ECh. 10.7 - Prob. 112ECh. 10.7 - Prob. 113ECh. 10.7 - Prob. 114ECh. 10.7 - Prob. 115ECh. 10.8 - Prob. 1ECh. 10.8 - Prob. 2ECh. 10.8 - Prob. 3ECh. 10.8 - Prob. 4ECh. 10.8 - Prob. 5ECh. 10.8 - Prob. 6ECh. 10.8 - Prob. 7ECh. 10.8 - Prob. 8ECh. 10.8 - Prob. 9ECh. 10.8 - Prob. 10ECh. 10.8 - Prob. 11ECh. 10.8 - Prob. 12ECh. 10.8 - Prob. 13ECh. 10.8 - Prob. 14ECh. 10.8 - Prob. 15ECh. 10.8 - Prob. 16ECh. 10.8 - Prob. 17ECh. 10.8 - Prob. 18ECh. 10.8 - Prob. 19ECh. 10.8 - Prob. 20ECh. 10.8 - Prob. 21ECh. 10.8 - Prob. 22ECh. 10.8 - Prob. 23ECh. 10.8 - Prob. 24ECh. 10.8 - Prob. 25ECh. 10.8 - Prob. 26ECh. 10.8 - Prob. 27ECh. 10.8 - Prob. 28ECh. 10.8 - Prob. 29ECh. 10.8 - Prob. 30ECh. 10.8 - Prob. 31ECh. 10.8 - Prob. 32ECh. 10.8 - Prob. 33ECh. 10.8 - Prob. 34ECh. 10.8 - Prob. 35ECh. 10.8 - Prob. 36ECh. 10.8 - Prob. 37ECh. 10.8 - Prob. 38ECh. 10.8 - Prob. 39ECh. 10.8 - Prob. 40ECh. 10.8 - Prob. 41ECh. 10.8 - Prob. 42ECh. 10.8 - Prob. 43ECh. 10.8 - Prob. 44ECh. 10.8 - Prob. 45ECh. 10.8 - Prob. 46ECh. 10.8 - Prob. 47ECh. 10.8 - Prob. 48ECh. 10.8 - Prob. 49ECh. 10.8 - Prob. 50ECh. 10.8 - Prob. 51ECh. 10.8 - Prob. 52ECh. 10.8 - Prob. 53ECh. 10.8 - Prob. 54ECh. 10.8 - Prob. 55ECh. 10.8 - Prob. 56ECh. 10.8 - Prob. 57ECh. 10.8 - Prob. 58ECh. 10.8 - Prob. 59ECh. 10.8 - Prob. 60ECh. 10.8 - Prob. 61ECh. 10.8 - Prob. 62ECh. 10.8 - Prob. 63ECh. 10.8 - Prob. 64ECh. 10.8 - Prob. 65ECh. 10.8 - Prob. 66ECh. 10.8 - Prob. 67ECh. 10.8 - Prob. 68ECh. 10.8 - Prob. 69ECh. 10.8 - Prob. 70ECh. 10.8 - Prob. 71ECh. 10.8 - Prob. 72ECh. 10.8 - Prob. 73ECh. 10.8 - Prob. 74ECh. 10.8 - Prob. 75ECh. 10.8 - Prob. 76ECh. 10.8 - Prob. 77ECh. 10.8 - Prob. 78ECh. 10.8 - Prob. 79ECh. 10.8 - Prob. 80ECh. 10.9 - Prob. 1ECh. 10.9 - Prob. 2ECh. 10.9 - Prob. 3ECh. 10.9 - Prob. 4ECh. 10.9 - Prob. 5ECh. 10.9 - Prob. 6ECh. 10.9 - Prob. 7ECh. 10.9 - Prob. 8ECh. 10.9 - Prob. 9ECh. 10.9 - Prob. 10ECh. 10.9 - Prob. 11ECh. 10.9 - Prob. 12ECh. 10.9 - Prob. 13ECh. 10.9 - Prob. 14ECh. 10.9 - Prob. 15ECh. 10.9 - Prob. 16ECh. 10.9 - Prob. 17ECh. 10.9 - Prob. 18ECh. 10.9 - Prob. 19ECh. 10.9 - Prob. 20ECh. 10.9 - Prob. 21ECh. 10.9 - Prob. 22ECh. 10.9 - Prob. 23ECh. 10.9 - Prob. 24ECh. 10.9 - Prob. 25ECh. 10.9 - Prob. 26ECh. 10.9 - Prob. 27ECh. 10.9 - Prob. 28ECh. 10.9 - Prob. 29ECh. 10.9 - Prob. 30ECh. 10.9 - Prob. 31ECh. 10.9 - Prob. 32ECh. 10.9 - Prob. 33ECh. 10.9 - Prob. 34ECh. 10.9 - Prob. 35ECh. 10.9 - Prob. 36ECh. 10.9 - Prob. 37ECh. 10.9 - Prob. 38ECh. 10.9 - Prob. 39ECh. 10.9 - Prob. 40ECh. 10.9 - Prob. 41ECh. 10.9 - Prob. 42ECh. 10.9 - Prob. 43ECh. 10.9 - Prob. 44ECh. 10.9 - Prob. 45ECh. 10.9 - Prob. 46ECh. 10.9 - Prob. 47ECh. 10.9 - Prob. 48ECh. 10.9 - Prob. 49ECh. 10.9 - Prob. 50ECh. 10.9 - Prob. 51ECh. 10.9 - Prob. 52ECh. 10.9 - Prob. 53ECh. 10.9 - Prob. 54ECh. 10.9 - Prob. 55ECh. 10.9 - Prob. 56ECh. 10.9 - Prob. 57ECh. 10.9 - Prob. 58ECh. 10.9 - Prob. 59ECh. 10.9 - Prob. 60ECh. 10.9 - Prob. 61ECh. 10.9 - Prob. 62ECh. 10.9 - Prob. 63ECh. 10.9 - Prob. 64ECh. 10.9 - Prob. 65ECh. 10.9 - Prob. 66ECh. 10.9 - Prob. 67ECh. 10.9 - Prob. 68ECh. 10.9 - Prob. 69ECh. 10.9 - Prob. 70ECh. 10.9 - Prob. 71ECh. 10.9 - Prob. 72ECh. 10.9 - Prob. 73ECh. 10.9 - Prob. 74ECh. 10.9 - Prob. 75ECh. 10.9 - Prob. 76ECh. 10.9 - Prob. 77ECh. 10.9 - Prob. 78ECh. 10 - Prob. 1RECh. 10 - Prob. 2RECh. 10 - Prob. 3RECh. 10 - Prob. 4RECh. 10 - Prob. 5RECh. 10 - Prob. 6RECh. 10 - Prob. 7RECh. 10 - Prob. 8RECh. 10 - Prob. 9RECh. 10 - Prob. 10RECh. 10 - Prob. 11RECh. 10 - Prob. 12RECh. 10 - Prob. 13RECh. 10 - Prob. 14RECh. 10 - Prob. 15RECh. 10 - Prob. 16RECh. 10 - Prob. 17RECh. 10 - Prob. 18RECh. 10 - Prob. 19RECh. 10 - Prob. 20RECh. 10 - Prob. 21RECh. 10 - Prob. 22RECh. 10 - Prob. 23RECh. 10 - Prob. 24RECh. 10 - Prob. 25RECh. 10 - Prob. 26RECh. 10 - Prob. 27RECh. 10 - Prob. 28RECh. 10 - Prob. 29RECh. 10 - Prob. 30RECh. 10 - Prob. 31RECh. 10 - Prob. 32RECh. 10 - Prob. 33RECh. 10 - Prob. 34RECh. 10 - Prob. 35RECh. 10 - Prob. 36RECh. 10 - Prob. 37RECh. 10 - Prob. 38RECh. 10 - Prob. 39RECh. 10 - Prob. 40RECh. 10 - Prob. 41RECh. 10 - Prob. 42RECh. 10 - Prob. 43RECh. 10 - Prob. 44RECh. 10 - Prob. 45RECh. 10 - Prob. 46RECh. 10 - Prob. 47RECh. 10 - Prob. 48RECh. 10 - Prob. 49RECh. 10 - Prob. 50RECh. 10 - Prob. 51RECh. 10 - Prob. 52RECh. 10 - Prob. 53RECh. 10 - Prob. 54RECh. 10 - Prob. 55RECh. 10 - Prob. 56RECh. 10 - Prob. 57RECh. 10 - Prob. 58RECh. 10 - Prob. 59RECh. 10 - Prob. 60RECh. 10 - Prob. 61RECh. 10 - Prob. 62RECh. 10 - Prob. 63RECh. 10 - Prob. 64RECh. 10 - Prob. 65RECh. 10 - Prob. 66RECh. 10 - Prob. 67RECh. 10 - Prob. 68RECh. 10 - Prob. 69RECh. 10 - Prob. 70RECh. 10 - Prob. 71RECh. 10 - Prob. 72RECh. 10 - Prob. 73RECh. 10 - Prob. 74RECh. 10 - Prob. 75RECh. 10 - Prob. 76RECh. 10 - Prob. 77RECh. 10 - Prob. 78RECh. 10 - Prob. 79RECh. 10 - Prob. 80RECh. 10 - Prob. 81RECh. 10 - Prob. 82RECh. 10 - Prob. 83RECh. 10 - Prob. 84RECh. 10 - Prob. 85RECh. 10 - Prob. 86RECh. 10 - Prob. 87RECh. 10 - Prob. 88RECh. 10 - Prob. 89RECh. 10 - Prob. 90RECh. 10 - Prob. 91RECh. 10 - Prob. 92RECh. 10 - Prob. 93RECh. 10 - Prob. 94RECh. 10 - Prob. 95RECh. 10 - Prob. 96RECh. 10 - Prob. 97RECh. 10 - Prob. 98RECh. 10 - Prob. 99RECh. 10 - Prob. 100RECh. 10 - Prob. 101RECh. 10 - Prob. 102RECh. 10 - Prob. 103RECh. 10 - Prob. 104RECh. 10 - Prob. 105RECh. 10 - Prob. 106RECh. 10 - Prob. 107RECh. 10 - Prob. 108RECh. 10 - Prob. 109RECh. 10 - Prob. 110RECh. 10 - Prob. 111RECh. 10 - Prob. 112RECh. 10 - Prob. 113RECh. 10 - Prob. 114RECh. 10 - Prob. 115RECh. 10 - Prob. 116RECh. 10 - Prob. 117RECh. 10 - Prob. 118RECh. 10 - Prob. 119RECh. 10 - Prob. 1CTCh. 10 - Prob. 2CTCh. 10 - Prob. 3CTCh. 10 - Prob. 4CTCh. 10 - Prob. 5CTCh. 10 - Prob. 6CTCh. 10 - Prob. 7CTCh. 10 - Prob. 8CTCh. 10 - Prob. 9CTCh. 10 - Prob. 10CTCh. 10 - Prob. 11CTCh. 10 - Prob. 12CTCh. 10 - Prob. 13CTCh. 10 - Prob. 14CTCh. 10 - Prob. 15CTCh. 10 - Prob. 16CTCh. 10 - Prob. 17CTCh. 10 - Prob. 18CTCh. 10 - Prob. 19CTCh. 10 - Prob. 20CTCh. 10 - Prob. 21CTCh. 10 - Prob. 22CTCh. 10 - Prob. 1PSCh. 10 - Prob. 2PSCh. 10 - Prob. 3PSCh. 10 - Prob. 4PSCh. 10 - Prob. 5PSCh. 10 - Prob. 6PSCh. 10 - Prob. 7PSCh. 10 - Prob. 8PSCh. 10 - Prob. 9PSCh. 10 - Prob. 10PSCh. 10 - Prob. 11PSCh. 10 - Prob. 12PSCh. 10 - Prob. 13PSCh. 10 - Prob. 14PSCh. 10 - Prob. 15PSCh. 10 - Prob. 16PSCh. 10 - Prob. 17PS
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Differential Equation | MIT 18.01SC Single Variable Calculus, Fall 2010; Author: MIT OpenCourseWare;https://www.youtube.com/watch?v=HaOHUfymsuk;License: Standard YouTube License, CC-BY