Chapter 10.6, Problem 34IP

a.

To determine

To find: The reason that Aaron more likely to choose a blue marbles or a green marbles.

Answer to Problem 34IP

Aaron is more likely to choose a green marble.

Explanation of Solution

Given information: A bag contains $4$ green marbles, $3$ blue marbles, $2$ red marbles and $1$ yellow marble is given.

Calculation: A bag contains $4$ green marbles $3$ blue marbles, $2$ red marbles and $1$ yellow marble is given.

Total outcomes $=10$ .

There are $4$ green marbles and $3$ blue marbles so the probabilities are:

  $\begin{array}{l}P(\text{green})=\frac{4}{10}\\ \mathrm{In}\mathrm{percent}=\frac{4}{10}\times 100\%=4\times 10\%=40\%\\ P(\mathrm{blue})=\frac{3}{10}\\ \mathrm{In}\mathrm{percent}=\frac{3}{10}\times 100\%=3\times 10\%=30\%\end{array}$

Thus, Aaron is more likely to choose a green marble.

b.

To determine

To find: The probability Aaron chooses a red marble or a yellow marble.

Answer to Problem 34IP

The probability Aaron chooses a red marble or a yellow marble is $\frac{3}{10}\mathrm{or}30\%$ .

Explanation of Solution

Given information: A bag contains $4$ green marbles, $3$ blue marbles, $2$ red marbles and $1$ yellow marble is given.

Calculation: A bag contains $4$ green marbles $3$ blue marbles, $2$ red marbles and $1$ yellow marble is given.

Total outcomes $=10$ .

  $\begin{array}{l}P(\mathrm{red}\mathrm{or}\mathrm{yellow})=\frac{3}{10}\\ \mathrm{In}\mathrm{percent}=\frac{3}{10}\times 100\%=3\times 10\%=30\%\end{array}$

Thus, the probability Aaron chooses a red marble or a yellow marble is $\frac{3}{10}\mathrm{or}30\%$ .

c.

To determine

To find: The probability Aaron does not choose a green marble.

Answer to Problem 34IP

The probability Aaron does not choose a green marble is $\frac{6}{10}\mathrm{or}60\%$ .

Explanation of Solution

Given information: A bag contains $4$ green marbles, $3$ blue marbles, $2$ red marbles and $1$ yellow marble is given.

Calculation: A bag contains $4$ green marbles $3$ blue marbles, $2$ red marbles and $1$ yellow marble is given.

Total outcomes $=10$ .

  $\begin{array}{l}P(\mathrm{not}\mathrm{green})=\frac{6}{10}\\ \mathrm{In}\mathrm{percent}=\frac{6}{10}\times 100\%=6\times 10\%=60\%\end{array}$

Thus, the probability Aaron does not choose a green marble is $\frac{6}{10}\mathrm{or}60\%$ .