EBK FOUNDATIONS OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781118930144
Author: Willard
Publisher: JOHN WILEY+SONS INC.
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 10.2, Problem 10.2P
Interpretation Introduction
Interpretation:
The definition of photon has to be given.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A sample of 3.73 mol of argon is confined at low pressure in a volume at a temperature of 61 C. Describe
quantitatively the effects of each of the following changes on the pressure, the average kinetic energy per
molecule in the gas, and the root-mean-square speed.
(a) The temperature is increased to 177 °C.
(b) The volume is tripled.
(c) The amount of argon is decreased to 1.96 mol.
Give each answer as a decimal factor of the form: new value = factor old value. A factor of 1 means no
change.
Change
KEavg
Urms
(а)
(b)
(c)
A flask contains a mixture of neon (Ne), krypton (Kr), and radon (Rn) gases. Compare (a) the average kinetic energies of the three types of atoms and (b) the root-mean-square speeds. (Hint: Appendix D shows the molar mass (in g>mol) of each element under the chemical symbol for that element.)
A sample of 3.42 mol of xenon is confined at low pressure in a volume at a temperature of 86 °C. Describe quantitatively the effects of each of the following changes
on the pressure, the average kinetic energy per molecule in the gas, and the root-mean-square speed.
(a) The temperature is increased to 199 °C
(b) The volume is tripled.
(c) The amount of xenon is decreased to 1.87 mol
Give each answer as a decimal factor of the form: new value factor old value. A factor of 1 means no change.
ChangeP
KEavgms
Chapter 10 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
Ch. 10.1 - Prob. 10.1PCh. 10.2 - Prob. 10.2PCh. 10.3 - Prob. 10.3PCh. 10.4 - Prob. 10.4PCh. 10.5 - Prob. 10.5PCh. 10.5 - Prob. 10.6PCh. 10.5 - Prob. 10.7PCh. 10 - Prob. 1RQCh. 10 - Prob. 2RQCh. 10 - Prob. 3RQ
Ch. 10 - Prob. 4RQCh. 10 - Prob. 5RQCh. 10 - Prob. 6RQCh. 10 - Prob. 7RQCh. 10 - Prob. 8RQCh. 10 - Prob. 9RQCh. 10 - Prob. 10RQCh. 10 - Prob. 11RQCh. 10 - Prob. 12RQCh. 10 - Prob. 13RQCh. 10 - Prob. 14RQCh. 10 - Prob. 15RQCh. 10 - Prob. 16RQCh. 10 - Prob. 17RQCh. 10 - Prob. 18RQCh. 10 - Prob. 19RQCh. 10 - Prob. 20RQCh. 10 - Prob. 21RQCh. 10 - Prob. 22RQCh. 10 - Prob. 23RQCh. 10 - Prob. 24RQCh. 10 - Prob. 25RQCh. 10 - Prob. 1PECh. 10 - Prob. 2PECh. 10 - Prob. 3PECh. 10 - Prob. 4PECh. 10 - Prob. 5PECh. 10 - Prob. 6PECh. 10 - Prob. 7PECh. 10 - Prob. 8PECh. 10 - Prob. 9PECh. 10 - Prob. 10PECh. 10 - Prob. 11PECh. 10 - Prob. 12PECh. 10 - Prob. 13PECh. 10 - Prob. 14PECh. 10 - Prob. 15PECh. 10 - Prob. 16PECh. 10 - Prob. 17PECh. 10 - Prob. 18PECh. 10 - Prob. 19PECh. 10 - Prob. 20PECh. 10 - Prob. 21PECh. 10 - Prob. 22PECh. 10 - Prob. 23PECh. 10 - Prob. 24PECh. 10 - Prob. 25PECh. 10 - Prob. 26PECh. 10 - Prob. 27PECh. 10 - Prob. 28PECh. 10 - Prob. 29PECh. 10 - Prob. 30PECh. 10 - Prob. 31PECh. 10 - Prob. 32PECh. 10 - Prob. 33PECh. 10 - Prob. 34PECh. 10 - Prob. 35PECh. 10 - Prob. 36PECh. 10 - Prob. 37PECh. 10 - Prob. 38PECh. 10 - Prob. 39PECh. 10 - Prob. 40PECh. 10 - Prob. 41PECh. 10 - Prob. 42PECh. 10 - Prob. 43PECh. 10 - Prob. 44PECh. 10 - Prob. 45PECh. 10 - Prob. 46PECh. 10 - Prob. 47PECh. 10 - Prob. 48PECh. 10 - Prob. 49PECh. 10 - Prob. 50PECh. 10 - Prob. 51AECh. 10 - Prob. 52AECh. 10 - Prob. 53AECh. 10 - Prob. 54AECh. 10 - Prob. 57AECh. 10 - Prob. 58AECh. 10 - Prob. 59AECh. 10 - Prob. 60AECh. 10 - Prob. 61AECh. 10 - Prob. 62AECh. 10 - Prob. 63AECh. 10 - Prob. 64AECh. 10 - Prob. 65AECh. 10 - Prob. 66AECh. 10 - Prob. 67AECh. 10 - Prob. 68AECh. 10 - Prob. 69AECh. 10 - Prob. 70AECh. 10 - Prob. 71AECh. 10 - Prob. 72AECh. 10 - Prob. 73AECh. 10 - Prob. 74AECh. 10 - Prob. 75AECh. 10 - Prob. 76AECh. 10 - Prob. 77AECh. 10 - Prob. 78CECh. 10 - Prob. 79CECh. 10 - Prob. 80CECh. 10 - Prob. 81CECh. 10 - Prob. 82CE
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- In the discussion on the composition of air, mention is made of the fact that water vapor may have a concentration as high as 40,000 ppm. Calculate the partial pressure exerted by water vapor at this concentration. Assume that this represents a situation with 100% humidity. What temperature would be needed to achieve this value? (See Appendix G.)arrow_forwardThe density of air at 20C and 1.00 atm is 1.205 g/L. If this air were compressed at the same temperature to equal the pressure at 50.0 m below sea level, what would be its density? Assume the barometric pressure is constant at 1.00 atm. The density of seawater is 1.025 g/cm3.arrow_forwardA student collected 26.86 mL of H2 over water at 20.00 °C. The water level inside the collection apparatus was 7.2 cm higher than the water level outside. The barometric pressure was 707 torr. How many grams of zinc had to react with HCI(aq) to produce the H2 that was collected? You may need the data in the table to solve this problem. mass = i g Zn 6.0arrow_forward
- A sample of 4.72 mol of krypton is confined at low pressure in a volume at a temperature of 68 °C. Describe quantitatively the effects of each of the following changes on the pressure, the average kinetic energy per molecule in the gas, and the root-mean-square speed. (a) The temperature is decreased to -49 °C.(b) The volume is doubled.(c) The amount of krypton is increased to 6.47 mol. Give each answer as a decimal factor of the form: new value = factor old value. A factor of 1 means no change.arrow_forwardA student, following the procedure described to evaluate the Gas Law Constant, collected the following data in an exercise: mass Mg, g 0.0243 final gas volume, mL 25.0 barometric pressure, torr 754 vapor pressure of H2O at 25 °C 23.76 temperature, K 298 a) The gas collected in the eudiometer is a mixture of hydrogen and water vapor. Calculate the gas law constant. b) What would be the volume of hydrogen gas produced by the reaction of 0.243 g of magnesium metal and collected at 750 torr (corrected pressure) and 298 K? Use the value of R found in question A. 2. The results of this experiment are greatly affected by the care with which each of the steps is completed. a) Describe the error that would occur if the magnesium were to slide into the HCl(aq) in the beaker before the eudiometer is sealed off. b) What would be the effect on the results of a rise in the room temperature from 21.5℃, when determination #1 was done, to 25.8℃, when determination #2 was…arrow_forwardA flask at room temperature contains equal numbers of di-nitrogen molecules and krypton atoms. (a) Which of the two gases exerts the higher partial pressure? (b) Which gas has a higher kinetic energy per molecule/atom? (c) Which gas has molecules with a higher velocity? Explain your answers.arrow_forward
- 1. An evaluation of R was performed, following the procedure described in this module. The barometric pressure was 736 torr, the temperature was 295 k, and the volume of hydrogen gas collected was 35.6 mL. The calculated value of R was 82.1 mL atm K^-1 mol^-1. (a) How many grams of magnesium metal were used? (b) If the vapor pressure of water had not been taken into account, what would have been the calculated value of R? (c) If the syringe volume had been incorrectly read, giving a calculated system volume of 25.6 mL, what would have been the percent error in the calculated value of R?arrow_forwardThe gravitational force exerted by an object is given by F=mg,where F is the force in newtons, mis the mass in kilo-grams, and gis the acceleration due to gravity (9.81 m/s²).(a) Use the definition of the pascal to calculate the mass (in kg)of the atmosphere above 1 m² of ocean.(b) Osmium (Z=76) is a transition metal in Group 8B(8) andhas the highest density of any element (22.6 g/mL). If an os-mium column is 1 m² in area, how high must it be for its pressureto equal atmospheric pressure?arrow_forwardWhat is the experimental molar mass (that is, calculated from the data given and not taken from the periodic table) of magnesium if 0.0208 grams of magnesium generates 21.25 mL of hydrogen at 19.1 °C with a hydrogen partial pressure of 735.4 torr? Note that the partial pressure of water vapor has already been subtracted from the total pressure.arrow_forward
- Q1 (a) 3.2 g of sulphur was produced in a reaction between 6.0 L of hydrogen sulfide gas with excess an amount of sulphur dioxide. With the aid of Table Q1 (a)(i) and Table Q1 (a)(ii), predict the temperature (in °C) of the reaction if it was conducted at 750 torr. Element Actinium Aluminum Americium Antimony Argon Arsenic Astatine Barium Berkelium Beryllium Bismuth Boron Bromine Cadmium Calcium Californium Carbon Cerium Cesium Chlorine Chromium Cobalt Copper Curiam CY с Ce Cs a Cr Co Ca Cm Dysprosium Dy Einsteinium Es Er Eu Fm F Fr Gd Ga Ge Erbium Europium Fermium Fluorine Francium Gadoliniam Gallium Germaniam Gold Hafnium Helium Holmium Hydrogen Indium Iodine Iridium Iron Krypton Lanthanam Lawrencium Lead Lithiam Lutetium Table Q1 (a)(i): Atomic Number and Atomic Mass of Elements Magnesium Manganese Symbol Ac Al Am Sb As Al Ba Bk Be Bi B Br Ca Hr He Ho H In I Ir Fe Kr La Lr Ph Li Lu Mg Mn Atomic number (2) 89 13 95 51 18 33 85 56 97 4 83 5 35 48 20 98 6 58 55 17 24 27 29 96 66 99 68…arrow_forwardAn ideal gas occupies a volume of 5.00 L at STP. (a) What is its pressure (in kPa) if the volume is halved and its absolute pressure is doubled? (b) What is its temperature if its volume is doubled and its pressure is tripled?arrow_forwardOn our campus, there are approximately 30.000 students who use 2.5 x 10° kJ of energy per day. Suppose all of that energy comes from the combustion of a carbon- hydrogen-oxygen compound in the presence of excess O2(g). 2.647 g sample of this gaseous carbon-hydrogen-oxygen compound that occupies a volume of 580 mL at 918,6 Torr and 24.00 °C. The products of the combustion of the given amount are 5.059 g CO2(g), 3.106 g H2O(1), and enough heat to raise the temperature of the calorimeter assembly from 24.00 to 38.33 °C. What is the molecular formula of this unknown compound and how many kilograms of this compound are needed to provide enough daily energy to all students on campus? (The heat capacity of the calorimeter is 4.915 kJ/°C.)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Quantum Mechanics - Part 1: Crash Course Physics #43; Author: CrashCourse;https://www.youtube.com/watch?v=7kb1VT0J3DE;License: Standard YouTube License, CC-BY