VECTOR MECH...,STAT.+DYNA.(LL)-W/ACCESS
11th Edition
ISBN: 9781259633133
Author: BEER
Publisher: MCG
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Chapter 10.1, Problem 10.50P
To determine
Derive the expression for the
Show that if the jack is to be self-locking, the mechanical efficiency cannot exceed 1/2.
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2. The power transmitted between two shafts
3.5 meters apart by a cross belt drive round
the two pulleys 600 mm and 300 mm in
diameters, is 6 kW. The speed of the larger
pulley (driver) is 220 r.p.m. The permissible
load on the belt is 25 N/mm width of the
belt which is 5 mm thick. The coefficient of
friction between the smaller pulley surface
and the belt is 0.35. Determine: 1.
necessary length of the belt; 2. width of the
belt, and 3. necessary initial tension in the
belt. Answer. 8.472 m; 53 mm ; 888 N
1
Please solce accurate i will rate it up if accurate
Chapter 10 Solutions
VECTOR MECH...,STAT.+DYNA.(LL)-W/ACCESS
Ch. 10.1 - Determine the vertical force P that must be...Ch. 10.1 - Determine the horizontal force P that must be...Ch. 10.1 - Prob. 10.3PCh. 10.1 - Prob. 10.4PCh. 10.1 - Prob. 10.5PCh. 10.1 - A spring of constant 15 kN/m connects points C and...Ch. 10.1 - The two-bar linkage shown is supported by a pin...Ch. 10.1 - Prob. 10.8PCh. 10.1 - Prob. 10.9PCh. 10.1 - Prob. 10.10P
Ch. 10.1 - Prob. 10.11PCh. 10.1 - Prob. 10.12PCh. 10.1 - Prob. 10.13PCh. 10.1 - Prob. 10.14PCh. 10.1 - Prob. 10.15PCh. 10.1 - Prob. 10.16PCh. 10.1 - Prob. 10.17PCh. 10.1 - Prob. 10.18PCh. 10.1 - Prob. 10.19PCh. 10.1 - Prob. 10.20PCh. 10.1 - Prob. 10.21PCh. 10.1 - A couple M with a magnitude of 100 Nm isapplied as...Ch. 10.1 - Rod AB is attached to a block at A that can...Ch. 10.1 - Solve Prob. 10.23, assuming that the 800-N force...Ch. 10.1 - Prob. 10.25PCh. 10.1 - Prob. 10.26PCh. 10.1 - Prob. 10.27PCh. 10.1 - Prob. 10.28PCh. 10.1 - Prob. 10.29PCh. 10.1 - Two rods AC and CE are connected by a pin at Cand...Ch. 10.1 - Solve Prob. 10.30 assuming that force P is movedto...Ch. 10.1 - Prob. 10.32PCh. 10.1 - Prob. 10.33PCh. 10.1 - Prob. 10.34PCh. 10.1 - Prob. 10.35PCh. 10.1 - Prob. 10.36PCh. 10.1 - Prob. 10.37PCh. 10.1 - Prob. 10.38PCh. 10.1 - Prob. 10.39PCh. 10.1 - Prob. 10.40PCh. 10.1 - Prob. 10.41PCh. 10.1 - The position of boom ABC is controlled by...Ch. 10.1 - Prob. 10.43PCh. 10.1 - Prob. 10.44PCh. 10.1 - Prob. 10.45PCh. 10.1 - Prob. 10.46PCh. 10.1 - Denoting the coefficient of static friction...Ch. 10.1 - Prob. 10.48PCh. 10.1 - Prob. 10.49PCh. 10.1 - Prob. 10.50PCh. 10.1 - Prob. 10.51PCh. 10.1 - Prob. 10.52PCh. 10.1 - Prob. 10.53PCh. 10.1 - Prob. 10.54PCh. 10.1 - Prob. 10.55PCh. 10.1 - Prob. 10.56PCh. 10.1 - Prob. 10.57PCh. 10.1 - Prob. 10.58PCh. 10.2 - Using the method of Sec. 10.2C, solve Prob. 10.29....Ch. 10.2 - Prob. 10.60PCh. 10.2 - Prob. 10.61PCh. 10.2 - Prob. 10.62PCh. 10.2 - Prob. 10.63PCh. 10.2 - Prob. 10.64PCh. 10.2 - Prob. 10.65PCh. 10.2 - Using the method of Sec. 10.2C, solve Prob. 10.38....Ch. 10.2 - Prob. 10.67PCh. 10.2 - Prob. 10.68PCh. 10.2 - Prob. 10.69PCh. 10.2 - Prob. 10.70PCh. 10.2 - Prob. 10.71PCh. 10.2 - Prob. 10.72PCh. 10.2 - Prob. 10.73PCh. 10.2 - Prob. 10.74PCh. 10.2 - Prob. 10.75PCh. 10.2 - Prob. 10.76PCh. 10.2 - Prob. 10.77PCh. 10.2 - Prob. 10.78PCh. 10.2 - Prob. 10.79PCh. 10.2 - Prob. 10.80PCh. 10.2 - Prob. 10.81PCh. 10.2 - A spring AB of constant k is attached to two...Ch. 10.2 - Prob. 10.83PCh. 10.2 - Prob. 10.84PCh. 10.2 - Prob. 10.85PCh. 10.2 - Prob. 10.86PCh. 10.2 - Prob. 10.87PCh. 10.2 - Prob. 10.88PCh. 10.2 - Prob. 10.89PCh. 10.2 - Prob. 10.90PCh. 10.2 - Prob. 10.91PCh. 10.2 - Prob. 10.92PCh. 10.2 - Prob. 10.93PCh. 10.2 - Prob. 10.94PCh. 10.2 - Prob. 10.95PCh. 10.2 - Prob. 10.96PCh. 10.2 - Bars AB and BC, each with a length l and of...Ch. 10.2 - Prob. 10.98PCh. 10.2 - Prob. 10.99PCh. 10.2 - Prob. 10.100PCh. 10 - Determine the vertical force P that must be...Ch. 10 - Determine the couple M that must be applied...Ch. 10 - Prob. 10.103RPCh. 10 - Prob. 10.104RPCh. 10 - Prob. 10.105RPCh. 10 - Prob. 10.106RPCh. 10 - Prob. 10.107RPCh. 10 - Prob. 10.108RPCh. 10 - Prob. 10.109RPCh. 10 - Prob. 10.110RPCh. 10 - Prob. 10.111RPCh. 10 - Prob. 10.112RP
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- Derive the following formulas relating the load W and the force P exerted on the handle of the jack discussed in Sec. 8.2B. (a) P= (Wr/a) tan (0+φs) to raise the load; (b) P= (Wr/a) tan (φs-0) to lower the load if the screw is self-locking; (c) P= (Wr/a) tan (0-φs) to hold the load if the screw is not self-locking.arrow_forwardA belt drive is required to transmit 10 kW from a motor running at "600 rpm. The belt is 12 mm thick -and -has a mass density of 0.001 g/mm3. Safe stress in the belt is not to exceed 2.5 N/mm2. Diameter of the driving pulley is 250 mm, whereas the speed of the driven pulley is 220 rpm. The two shafts are 1.25 m apart. The coefficient of friction is 0.25. Determine the width of the belt.arrow_forwardA 150lb man stands on a 60lb bar to which a cable is fixed at B. The cable passes over two fixed pegs with coefficients of friction indicated. Assume that the arrangement of the pegs permits the cable to contact each peg over a total angle of 90-degrees (90-degrees per peg). Assume that the normal force exerted by the man on the bar acts downward through A. Find the largest force the man can exert on the cable and maintain the bar horizontal.arrow_forward
- Clutch Mechanism 8. In the clutch mechanism shown, two flat circular disks of radius R are mounted so that they can be brought into contact causing a net frictional force. The contact pressure in general depends on the distance from the center and in one specific case may be modeled buy P(r) = Poe-kr, where k is a constant and r is the distance from the center of the discs. The integral cR F = 2m " P(r)rdr gives the total contact force between the discs. Cross-section a. In your own words explain where this formula comes from.arrow_forwardThe power transmitted between two shafts 3.5 metres apart by a cross belt drive round the two pulleys 600 mm and 300 mm in diameters, is 6 kW. The speed of the larger pulley (driver) is 220 r.p.m. The permissible load on the belt is 25 N/mm width of the belt which is 5 mm thick. The coefficient of friction between the smaller pulley surface and the belt is 0.35. Determine : 1. necessary length of the belt ; 2. width of the belt, and 3. necessary initial tension in the belt. [Ans. 8.472 m; 53 mm ; 888 N] Subject:Theory of Machinesarrow_forwardA flat belt connects pulley A to pulley B. The coefficients of friction are ms = 0.25 and mk = 0.20 between both pulleys and the belt. Knowing that the maximum allowable tension in the belt is 600 N, determine the largest torque (in N.m) which can be exerted by the belt on pulley A. 60° 0.2 m- r 0.025 m B.arrow_forward
- Please solve accurate thanksarrow_forwardA flat belt connects pulley A, which drives a machine tool, to pulley B, which is attached to the shaft of an electric motor. The coefficients of friction are u, = 0.25 and uk = 0.20 between both pulleys and the belt. Knowing that the maximum allowable tension in the belt is 600 Ib, determine the largest torque that the belt can exert on pulley A. 8 in: 1 in.arrow_forwardtheory of machinearrow_forward
- 7. A pulley 610 mm in diameter transmits 37 KW at 600 rpm. The arc of contact between the belt and pulley is 144 degrees, the coefficient of friction between the belt and pulley is 0.35, and the safe working stress of the belt is 2.1 Mpa. Find: A. The tangential force at the rim of the pulley. Ans. 1.93 KN B. The effective belt pull. C. The width of the belt used if its thickness is 6 mm. 200 a wide Ans. 1.93 KN Ans. 261 mmarrow_forward.A belt 200 mm wide and 7 mm thick drives a pulley at belt speed of 25 m/s. The density of the belt is 980 kg/m3 and the coefficient of friction between the belt and pulley is 0.23. Given that the angle of contact of pulley is 2π/3 and the allowable stress of the belt is 1.8 MPa, determine the tension on the slack side of the belt (T2) in Narrow_forwardA leather belt of thickness 6 mm and width 80 mm connects two pulleys of 500 mm diameter and 900 mm diameter, their centres being 2.5 m apart. If speed of the larger pulley is 300 r.p.m, the coefficient of friction between belt and pulley is 0.25 and maximum belt stress is 100 N/cm2, determine the maximum power transmitted and initial belt tension.arrow_forward
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