Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
10th Edition
ISBN: 9780073398204
Author: Richard G Budynas, Keith J Nisbett
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 10, Problem 5P
A helical compression spring is made with oil-tempered wire with wire diameter of 0.2 in, mean coil diameter of 2 in, a total of 12 coils, a free length of 5 in, with squared ends.
- (a) Find the solid length.
- (b) Find the force necessary to deflect the spring to its solid length.
- (c) Find the factor of safety guarding against yielding when the spring is compressed to its solid length.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A helical compression spring is made with oil-tempered wire of diameter 0.2", mean coil
diameter of 2", 12 total coils, 5" free length, and squared ends. (a) Find the solid length. (b) Find
the force required to compress the spring to closure? (c) Find the factor of safety against yield
when compressed to the solid length. (Hint: Uses Say= 0.5 Sut for shear strength.)
Kindy answer correctly. Please show the necessary steps (the template is provided)
Don't give handwritten
Chapter 10 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
Ch. 10 - Within the range of recommended values of the...Ch. 10 - It is instructive to examine the question of the...Ch. 10 - A helical compression spring is wound using...Ch. 10 - The spring in Prob. 10-3 is to be used with a...Ch. 10 - A helical compression spring is made with...Ch. 10 - A helical compression spring is to be made of...Ch. 10 - A helical compression spring is made of hard-drawn...Ch. 10 - The spring of Prob. 107 is to be used with a...Ch. 10 - 109 to 1019 Listed in the tables are six springs...Ch. 10 - 109 to 1019 Listed in the tables are six springs...
Ch. 10 - 10-9 to 10-19 Listed in the tables are six springs...Ch. 10 - Prob. 12PCh. 10 - 10-9 to 10-19 Listed in the tables are six springs...Ch. 10 - 10-9 to 10-19 Listed in the tables are six springs...Ch. 10 - 10-9 to 10-19 Listed in the tables are six springs...Ch. 10 - 10-9 to 10-19 Listed in the tables are six springs...Ch. 10 - Prob. 17PCh. 10 - 10-9 to 10-19 Listed in the tables are six springs...Ch. 10 - 10-9 to 10-19 Listed in the tables are six springs...Ch. 10 - Consider the steel spring in the illustration. (a)...Ch. 10 - A static service music wire helical compression...Ch. 10 - Solve Prob. 1021 by iterating with an initial...Ch. 10 - A holding fixture for a workpiece 37.5 mm thick at...Ch. 10 - Solve Prob. 10-23 by iterating with an initial...Ch. 10 - A compression spring is needed to fit over a...Ch. 10 - A compression spring is needed to fit within a...Ch. 10 - A helical compression spring is to be cycled...Ch. 10 - The figure shows a conical compression helical...Ch. 10 - A helical coil compression spring is needed for...Ch. 10 - Solve Prob. 10-30 using the Goodman-Zimmerli...Ch. 10 - Solve Prob. 10-30 using the Sines-Zimmerli...Ch. 10 - Design the spring of Ex. 10-5 using the...Ch. 10 - Solve Prob. 10-33 using the Goodman-Zimmerli...Ch. 10 - A hard-drawn spring steel extension spring is to...Ch. 10 - The extension spring shown in the figure has...Ch. 10 - Design an infinite-life helical coil extension...Ch. 10 - Prove Eq. (10-40). Hint: Using Castigliunos...Ch. 10 - The figure shows a finger exerciser used by...Ch. 10 - The rat trap shown in the figure uses two...Ch. 10 - Prob. 41PCh. 10 - Prob. 42PCh. 10 - Figure 10-13b shows a spring of constant thickness...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A helical compression spring is wound using 0.12-in-diameter phosphor-bronze B159 wire. The spring index C = 10 and the total number of coils is N = 14. You may assume that the spring has both ends squared and ground and is supported between fixed ends. Also, Sgy = 0.45 · Sut- a. Estimate the spring rate. b. Estimate the static load corresponding to the yield strength. c. What should the free length of the spring be to ensure that when it is compressed solid the torsional stress does not exceed the yield strength? d. Calculate the critical value of the free length of the spring to avoid buckling.arrow_forwardA helical compression spring has a scale of 500 lb/in., an outside diameter of 2.75 in, a free length of 8 inches and with squared and ground ends. The load is 1,000 lbs and the working stress on the wire material is 65000 psi. If the Wahl factor of 1.25 is to be used, calculate the following: A. The standard wire diameter B. The number of active coil if G = 10 800 000 psi C. The solid height D. The stress at solid heightarrow_forwardA helical compression spring is subjected to a maximum force, Fmax of 1250 N. The deflection of the spring corresponding to the maximum force should be approximately 30 mm. The spring index is 6. The allowable shear stress is 350 MPa and the modulus of rigidity is 81 370 N/mm². Design the helical spring by calculating the wire diameter, mean coil diameter, number of active coils and the total number of coils. State all assumptions and decisions in your design.arrow_forward
- Find: spring rate, force at solid length,check for buckling,coil clearance and hole diameterarrow_forwardA helical compression spring is wound using 4 mm-diameter Chrome-vanadium wire. The spring has an outside diameter of 28 mm with squared and ground ends, and 14 total coils: (a) What should the free length be to ensure that when the spring is compressed solid the torsional stress does not exceed the yield strength, that is, that it is solid-safe? (b) What force is needed to compress this spring to closure? (c) Estimate the spring rate. (d ) Is there a possibility that the spring might buckle in service?arrow_forwardProblem 4: A helical compression spring is to be cycled between 150 lbf and 300 lbf with a 1-in stroke. The number of cycles is low, so fatigue is not an issue. The coil must fit in a 2.1-in diameter hole with a 0.1-in clearance all the way around the spring. Use unpeened music wire with squared and ground ends. (a) Determine a suitable wire diameter, using a spring index of C = 7. (b) Determine a suitable mean coil diameter. (c) Determine the necessary spring constant. (d) Determine a suitable total number of coils. (e) Determine the necessary free length so that if the spring were compressed to its solid length, there would be no yieldingarrow_forward
- Design a helical spring to be used in spring balance with a wire diameter of 6mm and the outside diameter should be limited to 66mm. if the permissible shear stress of the spring material is 325 N/mm? and the Modulus of rigidity is 85kN/mm?. a) Compute the deflection of spring per active turn and the axial load on the spring considering the effect of curvature, take Wahl's factor as Kw= 1.1 b) Calculate the value of axial load neglecting the effect of stress factor. **Note: Please upload your handwritten working/solution to the link provided. The value of Mean diameter of the spring in mm . The Spring Index is. Shear stress factor, neglecting curvature effect . Deflection per active turn in mm Axial Load W in N .. Axial Load W in N. considering effect of curvature .arrow_forwardFor Hibiscus and Rose Groups A steel helical spring is wound from No. 14 music wire with a mean helix diameter of 0.6 in. The load varies continuously between 10 and 4 lb. Find the factor of safety.arrow_forwardA helical spring of oil-tempered Class I is subjected to a continuously varying load. The average load is 330 N. The factor of safety is 1.33. The spring is made of No. 7 wire and has a mean helix radius of 13 mm. Find the maximum and minimum external loads (Pmax & Pmin).(1 inch = 25.4 mm, 1 psi = 0.00689476 MPa)arrow_forward
- A spring made from music wire ASTM 228 steel has the following data:Free length=1.75” Outside diameter=0.561”Wire diameter=0.055” Applied load= 14 lbEnds=square and ground both ends hingedNumber of coils=10 G=11.85 x 106psi E= 30 Mpsi Findspring rate, force at solid length,check for buckling,coil clearance and hole diameterarrow_forwardDon't give incorrect solution. Otherwise I'll downvotearrow_forwardGive me right solution with clear calculationsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Mechanical SPRING DESIGN Strategy and Restrictions in Under 15 Minutes!; Author: Less Boring Lectures;https://www.youtube.com/watch?v=dsWQrzfQt3s;License: Standard Youtube License