BIOLOGY
12th Edition
ISBN: 9781260169614
Author: Raven
Publisher: RENT MCG
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Chapter 10, Problem 1S
Regulation of the cell cycle is very complex and involves multiple proteins. In yeast, a complex of cdc2 and a mitotic cyclin is responsible for moving the cell past the G2/M checkpoint. The activity of the cyclin-dependent kinase cdc2 is inhibited when it is phosphorylated by the kinase, Wee-1. What would you predict would be the
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Regulation of the cell cycle is very complex and involves multiple proteins. In yeast, a complex of cdc2 and a mitotic cyclin is responsible for moving the cell past the G2/M checkpoint. The activity of the cyclin-dependent kinase cdc2 is inhibited when it is phosphorylated by the kinase, Wee-1. What would you predict would be the phenotype of a Wee-1 mutant yeast? What other genes could be altered in a Wee-1 deficient mutant strain that would make the cells act normally?
The retinoblastoma protein (RB) suppresses human cell division by
arresting cells in the G₁ phase of the cell cycle and preventing
progression to the next phase. It accomplishes this task by binding
to another protein, E2F, a transcription factor needed for further
progression through the cell cycle. Normal progression through the
cell cycle is accomplished when cyclin-dependent kinases (CDKs)
phosphorylate RB, preventing its binding to E2F.
Many viruses can induce abnormal exit from G, using viral proteins
that bind to RB at a motif at the N-terminal called LXCXE. An
example is the E7 papilloma protein, which causes the excessive
proliferation of cells in warts.
The site at which LXCXE proteins bind is called the pocket domain
and is highly conserved on RB and related proteins in plants and
animals. The configuration of the pocket domain is well established.
Mutant experimental RB proteins are available with alterations in the
conserved amino acids of the pocket domain.
A simple…
The retinoblastoma protein (RB) suppresses human cell division by
arresting cells in the G₁ phase of the cell cycle and preventing
progression to the next phase. It accomplishes this task by binding
to another protein, E2F, a transcription factor needed for further
progression through the cell cycle. Normal progression through the
cell cycle is accomplished when cyclin-dependent kinases (CDKs)
phosphorylate RB, preventing its binding to E2F.
Many viruses can induce abnormal exit from G, using viral proteins
that bind to RB at a motif at the N-terminal called LXCXE. An
example is the E7 papilloma protein, which causes the excessive
proliferation of cells in warts.
The site at which LXCXE proteins bind is called the pocket domain
and is highly conserved on RB and related proteins in plants and
animals. The configuration of the pocket domain is well established.
Mutant experimental RB proteins are available with alterations in the
conserved amino acids of the pocket domain.
A simple…
Chapter 10 Solutions
BIOLOGY
Ch. 10.1 - Prob. 1LOCh. 10.2 - Prob. 1LOCh. 10.2 - Distinguish between homologues and sister...Ch. 10.2 - Prob. 3LOCh. 10.3 - Describe the eukaryotic cell cycle.Ch. 10.4 - Prob. 1LOCh. 10.4 - Prob. 2LOCh. 10.5 - Describe the phases of mitosis.Ch. 10.5 - Explain the importance of metaphase.Ch. 10.5 - Compare cytokinesis in plants and animals.
Ch. 10.6 - Prob. 1LOCh. 10.6 - Prob. 2LOCh. 10.7 - Prob. 1LOCh. 10.7 - Prob. 2LOCh. 10 - Binary fission in prokaryotes does not require the...Ch. 10 - Chromatin is composed of a. RNA and protein. b....Ch. 10 - What is a nucleosome? a. A region in the cells...Ch. 10 - What is the role of cohesin proteins in cell...Ch. 10 - The kinetochore is a structure that functions to...Ch. 10 - Separation of the sister chromatids occurs during...Ch. 10 - Why is cytokinesis an important part of cell...Ch. 10 - What steps in the cell cycle represent...Ch. 10 - Cyclin-dependent kinases (Cdks) are regulated by...Ch. 10 - Prob. 2ACh. 10 - Genetically, proto-oncogenes act in a dominant...Ch. 10 - The metaphase to anaphase transition involves a....Ch. 10 - The main difference between bacterial cell...Ch. 10 - In animal cells, cytokinesis is accomplished by a...Ch. 10 - Regulation of the cell cycle is very complex and...Ch. 10 - Review you knowledge of signaling pathways...Ch. 10 - Compare and contrast how mutations in cellular...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Which of the following statements is a lie?Select one: a. If damaged DNA is detected during the cell cycle, negative regulation is responsible in stopping the cell cycle. b. There are four cyclin proteins involved in the positive regulation of the cell cycle and they have fluctuating levels. c. To activate cyclin-dependent kinases (Cdks), they must bind to another kinase.arrow_forwardYou are studying Protein X which plays a role in promoting the G1/S phase transition in eukaryotic cells. You design an experiment using wild-type yeast cells to measure the amount of Gene X MRNA and activity levels of Protein X during the cell cycle. The results from your experiment are shown in the graph below. From the data, which of the following could Protein X be? Protein X activity levels Gene X MRNA levels Relative Units G1 G2 M cyclin inhibitor protein O cyclin dependent kinase O Helicase Cyclinarrow_forwardWhen regulating the cell cycle of eukaryotic cells, a critical protein we discussed was cyclin. Cyclin is Select one: a. Always present in all stages of the cell cycle, but only active during the G1 - R transition b. Produced in response to signals for the cell to divide c. Produced only when retinoblastoma protein is inactivated d. Produced in response to the presence of cyclin-dependent kinasearrow_forward
- During cell division cycle, cells need to monitor the process of DNA replication and segregation of replicated DNA so that these processes are error-free. Some potential errors that could occur include incomplete DNA replication, DNA damage in genome, and uneven separation of replicated genome. These mechanisms that cells used to monitor these processes are referred as the "cell cycle checkpoint, which can control specific Cdk activity to regulate the progression of cell cycle. For the following checkpoint mechanisms, indicate which Cdk activity is attenuated? Also indicate one of the key proteins or protein complexes involved in the following checkpoints. a) DNA damage checkpoint during S-phase b) Mitotic checkpoint during M-phasearrow_forwardWhat do you think would happen to the cell cycle of cells that contain a point mutation in the S- Cdk gene that causes S-Cdk to lose its kinase activity? Explain. You genetically engineer a cell line so that the S-Cyclin gene promoter is replaced with the promoter of S-Cdk. How do you think the cell cycle would be affected by this change? Explain.arrow_forwardImagine that there are mutations in the CDK genes such that their gene products are nonfunctional. What effect would this mutation have on an immature unspecialized blood cell precursor found in the bone marrow? The cell would not be able to reproduce itself. The cell would complete the cell cycle using cyclins in the absence of CDKS. The cell would be able to replicate its DNA but not translate DNA into RNA. The cell would be able to enter mitosis but not complete it. The cell would still phosphorylate the CDK-associated target proteins, and would do so more quickly.arrow_forward
- After DNA damage (e.g. caused by X-ray exposure) in eukaryotic cells, the cell cycle can be arrested by the stabilisation of the protein which drives the transcription of the gene, whose protein product interacts with the G1/S-Cdk and S-Cdk complexes. O PDGF, acetyltransferase O phenylalanine hydraxylase, PDGF O p53, acetyltransferase O p53, p21 O p21. p53arrow_forwardIn Xenopus, one of the substrates of mitotic CDKs is the phosphatase Cdc25. When phosphorylated by mitotic CDKs, Cdc25 is activated. What is the substrate of Cdc25? How does this information help to explain the rapid rise in mitotic CDK activity as cells enter mitosis?arrow_forwardTo identify genes controlling the cell cycle in budding yeast, a genetic screen was carried out. In this screen, haploid yeast cells were exposed to a DNA damaging agent to introduce random mutations in the genome. By culturing cells at an elevated temperature (e.g. 37 degrees), where many mutated genes lose their function, scientists identified yeast mutants that showed growth defects and arrest at specific stages of the cell cycle (e.g. in mitosis with large buds). In this screen, mutants of the cyclin-dependent kinase were identified, but not mutants of cyclins. Explain the reason for this outcome.arrow_forward
- A cell inherits a mutation in a gene that results in a transcription factor, called NF-kB, constantly being in its active conformation. When active, NF-kB stimulates the expression of cyclins that promote progression of the cell cycle, regardless of other conditions. As a result of this mutation, how would this cell's phenotype be affected by this mutation? A) This cell would have a cancer phenotype B) This cell would grow larger in size, but would never divide C) This cell would likely undergo apoptosis D) This cell would not duplicate its chromosomes .arrow_forwardYou are studying three proteins that you think are important Yor progression through the cell cycle. You know that one of them is a phosphatase (P1) and the other two are kinases ( K1 and K2). You add these enzymes in different combinations as shown below, and find that they have different effects on the activity of a cyclin dependent kinase, cdk2p. cdk2p Inactive Active cdk2p + K1 cdk2p + K2 Inactive cdk2p + K1 + K2 Inactive cdk2p + P1 cdk2p + P1 + K2 cdk2p + P1 + K1 Inactive Inactive Active cdk2p + P1 + K1 + K2 Activearrow_forwardDescribe how Ras and p53 can alter the simplified genetic pathway controlling cell division shown below. For each of the two genes, would uncontrolled cell division result from a loss-of-function or a gain-of-function mutation? growth factors - receptors - cyclins - cyclin-dependent kinases - cell divisionarrow_forward
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