Big Java, Binder Ready Version: Early Objects
Big Java, Binder Ready Version: Early Objects
6th Edition
ISBN: 9781119056447
Author: Cay S. Horstmann
Publisher: WILEY
Expert Solution & Answer
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Chapter 10, Problem 1RE

Explanation of Solution

Computation of (a-b):

  • It is given that the value assigned to a is “2000000000” and the value assigned to b is “-a”, which is “-2000000000”.
  • Whenever the result of an arithmetic operation is out of range, it returns an overflow, which can be stored in the result variable.
  • In order to store the result, the value is wrapped around and is assigned to the result variable. This wrapping will result in loss of data.
  • Here, the value of b is negative. So when the computation a-b is done, they both add up.
  • The result is out of range of int value. Hence, the wrapping up takes place.

Therefore, the result of a-b is “-294967296”.

Explanation of Solution

Computation of (b-a):

  • It is given that the value assigned to a is “2000000000” and the value assigned to b is “-a”, which is “-2000000000”.
  • Whenever the result of an arithmetic operation is out of range, it returns an overflow, which can be stored in the result variable.
  • In order to store the result, the value is wrapped around and is assigned to the result variable. This wrapping will result in loss of data.
  • Here, the value of b is negative. So when the computation b-a is done, they both add up.
  • The result is out of range of int value. Hence, the wrapping up takes place.

Therefore, the result of b-a is “294967296”.

Explanation of Solution

Result of Integer.compare(a, b):

  • The method Integer.compare(a, b) compares two test values for the order in which they must come.
  • If the variable on the left side is less than the right side, then “-1” is returned.
  • Otherwise, if the variable on the left side is greater than the right side, then “1” is returned.
  • In case, both are equal, then “0” is returned.
  • Here, the value of a is greater than the value of b. It means that the value on the left side is greater than the value on the right side.

Therefore, the result of Integer.compare(a, b) is “1”.

Explanation of Solution

Result of Integer.compare(b, a):

  • The method Integer.compare(b, a) compares two test values for the order in which they must come.
  • If the variable on the left side is less than the right side, then “-1” is returned.
  • Otherwise, if the variable on the left side is greater than the right side, then “1” is returned.
  • In case, both are equal, then “0” is returned.
  • Here, the value of a is greater than the value of b. It means that the value on the left side is less than the value on the right side.

Therefore, the result of Integer.compare(b, a) is “-1”.

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Chapter 10 Solutions

Big Java, Binder Ready Version: Early Objects

Ch. 10.3 - Prob. 11SCCh. 10.3 - Prob. 12SCCh. 10.3 - Prob. 13SCCh. 10.3 - Write a method max that finds the larger of any...Ch. 10.3 - Write a call to the method of Self Check 14 that...Ch. 10.4 - Suppose you want to use the average method of...Ch. 10.4 - Prob. 17SCCh. 10.4 - Prob. 18SCCh. 10.4 - Write a method max with three arguments that finds...Ch. 10.4 - Write a call to the method of Self Check 19 that...Ch. 10.5 - Why would you use an inner class instead of a...Ch. 10.5 - When would you place an inner class inside a class...Ch. 10.5 - How many class files are produced when you compile...Ch. 10.6 - Why is it necessary that the real class and the...Ch. 10.6 - Why is the technique of mock objects particularly...Ch. 10.7 - Prob. 26SCCh. 10.7 - Prob. 27SCCh. 10.7 - Prob. 28SCCh. 10.7 - Prob. 29SCCh. 10.7 - If an inner class accesses a local variable from a...Ch. 10.8 - Prob. 31SCCh. 10.8 - Prob. 32SCCh. 10.9 - Prob. 33SCCh. 10.9 - Prob. 34SCCh. 10.10 - Prob. 35SCCh. 10.10 - Why must the MousePressListener class supply five...Ch. 10 - Prob. 1RECh. 10 - Prob. 2RECh. 10 - Prob. 3RECh. 10 - Prob. 4RECh. 10 - Prob. 5RECh. 10 - The classes Rectangle2D.Double, Ellipse2D.Double,...Ch. 10 - Suppose r contains a reference to a new...Ch. 10 - Classes such as Rectangle2D. Double,...Ch. 10 - Prob. 9RECh. 10 - What happens if you try to use an array of String...Ch. 10 - Prob. 11RECh. 10 - What happens if you pass an array of strings and...Ch. 10 - Consider this top-level and inner class. Which...Ch. 10 - What happens when an inner class tries to access a...Ch. 10 - Prob. 15RECh. 10 - Prob. 16RECh. 10 - Prob. 17RECh. 10 - What is the difference between an ActionEvent and...Ch. 10 - Prob. 19RECh. 10 - Prob. 20RECh. 10 - Prob. 21RECh. 10 - Prob. 22RECh. 10 - Prob. 23RECh. 10 - Prob. 24RECh. 10 - Add a method public static Measurable...Ch. 10 - Prob. 2PECh. 10 - A person has a name and a height in centimeters....Ch. 10 - Add static methods largest and smallest to the...Ch. 10 - In the Sequence interface of Worked Example 10.1,...Ch. 10 - In Worked Example 10.1, add a default...Ch. 10 - In Worked Example 10.1, make the process method a...Ch. 10 - Add a method to the Data class that returns the...Ch. 10 - Prob. 9PECh. 10 - Modify the Coin class from Chapter 8 to have it...Ch. 10 - Repeat Exercise E10.9, making the Measurer into an...Ch. 10 - Repeat Exercise E10.9, making the Measurer an...Ch. 10 - Implement a class Bag that stores items...Ch. 10 - Prob. 14PECh. 10 - Reimplement Exercise E10.14 where the grid is...Ch. 10 - Prob. 16PECh. 10 - Enhance the ButtonViewer program so that it prints...Ch. 10 - Prob. 18PECh. 10 - Prob. 19PECh. 10 - Prob. 20PECh. 10 - Prob. 21PECh. 10 - Prob. 22PECh. 10 - Prob. 23PECh. 10 - Reimplement the program in Section 10.7.2,...Ch. 10 - Prob. 25PECh. 10 - Prob. 26PECh. 10 - Prob. 27PECh. 10 - Prob. 28PECh. 10 - Prob. 29PECh. 10 - Prob. 30PECh. 10 - Prob. 1PPCh. 10 - Write a class PrimeSequence that implements the...Ch. 10 - Prob. 3PPCh. 10 - Prob. 4PPCh. 10 - Prob. 5PPCh. 10 - Prob. 6PPCh. 10 - Prob. 7PPCh. 10 - Prob. 8PPCh. 10 - Prob. 9PPCh. 10 - Prob. 10PPCh. 10 - Prob. 11PPCh. 10 - Prob. 12PPCh. 10 - Prob. 13PPCh. 10 - Prob. 14PPCh. 10 - Prob. 15PPCh. 10 - Prob. 16PPCh. 10 - Prob. 17PPCh. 10 - Prob. 18PPCh. 10 - Prob. 19PPCh. 10 - Prob. 20PPCh. 10 - Prob. 21PPCh. 10 - Prob. 22PPCh. 10 - Prob. 23PPCh. 10 - Prob. 24PPCh. 10 - Prob. 25PPCh. 10 - Prob. 26PPCh. 10 - Prob. 27PP
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