Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Question
Chapter 10, Problem 10.6.2P
To determine
(a)
Maximum factored concentrated load that can be supported by using LRFD method.
To determine
(b)
Maximum factored concentrated load that can be supported by using ASD method.
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Determine the maximum service load, P, that can be applied if the live load-to-dead load ratio is 2.0. Each component is a PL 3⁄4 x 7 of A242 steel. The weld is a 1⁄2-inch fillet weld, E70 electrode. a. Use LRFD. b. Use ASD.
The details of an end bearing stiffener are shown in Figure . The stiffener plates are 9⁄16-inch thick, and the web is 3⁄16-inch thick. The stiffeners are clipped 1⁄2 inch to provide clearance for the flange-to-web welds. All steel is A572 Grade 50. a. Use LRFD and determine the maximum factored concentrated load that can be supported. b. Use ASD and determine the maximum service concentrated load that can be supported.
Situation 5. The angular section shown below is welded to a 12 mm gusset plate.
Both materials are A36 steel with Fy = 250 MPa. The allowable tensile
stress is 0.6Fy. The weld is E80 Electrode and 12 mm
thickness.
INNOVATIONS
Properties of L 150x90x12:
y = 50
shear stress of weld = 0.3Fu
A = 2750
Allowable
REVIEW INNOVATIE
a
K ➜
www
A. 234 KN
B. 349 KN
b
13. What is the value of P without exceeding the allowable tensile
the angle?
C. 382 kN
p. 413 kN
14. Find required length of the weld based on shear?
A. 280 mm
C. 300 mm
D. 380 mm
B. 320 mm
15. Find the required value of a?
A. 108 mm
B. 97.9 mm
D. 185 mm
NEW INNOVATIONS
REVIEW INNOVATIOf
REVIEW
NEW INNOVATIONS
Chapter 10 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
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