Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
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Chapter 10, Problem 10.59P
Interpretation Introduction
Interpretation:
It is to be explained why a terminal
Concept introduction:
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When 4-penten-2-one is reacted with aqueous NaBH4 (sodium
borohydride), the major substrate product will contain the following
functional groups:
alcohol only.
alkene only.
ketone only.
alkene & alcohol.
alkene & ketone, since no reaction occurs under these conditions.
What are the reagents used to convert 2-butyne to C4H8? What are the products when that C4H8 is mixed with OsO4, and H2O (the formula will be C4H10O2 racemic)? What is the product when C4H8 is mixed with RCO3H, and H2O (the formula will be C4H10O2 meso)?
Alkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov
regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called
an enol. The enol immediately rearranges to a more stable ketone via tautomerization.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
-X티
Hö:
H-O
-CH3
-CH3
H30*
Chapter 10 Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
Ch. 10 - Prob. 10.1PCh. 10 - Prob. 10.2PCh. 10 - Prob. 10.3PCh. 10 - Prob. 10.4PCh. 10 - Prob. 10.5PCh. 10 - Prob. 10.6PCh. 10 - Prob. 10.7PCh. 10 - Prob. 10.8PCh. 10 - Prob. 10.9PCh. 10 - Prob. 10.10P
Ch. 10 - Prob. 10.11PCh. 10 - Prob. 10.12PCh. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24PCh. 10 - Prob. 10.25PCh. 10 - Prob. 10.26PCh. 10 - Prob. 10.27PCh. 10 - Prob. 10.28PCh. 10 - Prob. 10.29PCh. 10 - Prob. 10.30PCh. 10 - Prob. 10.31PCh. 10 - Prob. 10.32PCh. 10 - Prob. 10.33PCh. 10 - Prob. 10.34PCh. 10 - Prob. 10.35PCh. 10 - Prob. 10.36PCh. 10 - Prob. 10.37PCh. 10 - Prob. 10.38PCh. 10 - Prob. 10.39PCh. 10 - Prob. 10.40PCh. 10 - Prob. 10.41PCh. 10 - Prob. 10.42PCh. 10 - Prob. 10.43PCh. 10 - Prob. 10.44PCh. 10 - Prob. 10.45PCh. 10 - Prob. 10.46PCh. 10 - Prob. 10.47PCh. 10 - Prob. 10.48PCh. 10 - Prob. 10.49PCh. 10 - Prob. 10.50PCh. 10 - Prob. 10.51PCh. 10 - Prob. 10.52PCh. 10 - Prob. 10.53PCh. 10 - Prob. 10.54PCh. 10 - Prob. 10.55PCh. 10 - Prob. 10.56PCh. 10 - Prob. 10.57PCh. 10 - Prob. 10.58PCh. 10 - Prob. 10.59PCh. 10 - Prob. 10.60PCh. 10 - Prob. 10.61PCh. 10 - Prob. 10.62PCh. 10 - Prob. 10.63PCh. 10 - Prob. 10.64PCh. 10 - Prob. 10.65PCh. 10 - Prob. 10.66PCh. 10 - Prob. 10.67PCh. 10 - Prob. 10.68PCh. 10 - Prob. 10.69PCh. 10 - Prob. 10.70PCh. 10 - Prob. 10.71PCh. 10 - Prob. 10.72PCh. 10 - Prob. 10.73PCh. 10 - Prob. 10.74PCh. 10 - Prob. 10.1YTCh. 10 - Prob. 10.2YTCh. 10 - Prob. 10.3YTCh. 10 - Prob. 10.4YTCh. 10 - Prob. 10.5YTCh. 10 - Prob. 10.6YTCh. 10 - Prob. 10.7YTCh. 10 - Prob. 10.8YTCh. 10 - Prob. 10.9YTCh. 10 - Prob. 10.10YTCh. 10 - Prob. 10.11YTCh. 10 - Prob. 10.12YTCh. 10 - Prob. 10.13YTCh. 10 - Prob. 10.14YTCh. 10 - Prob. 10.15YTCh. 10 - Prob. 10.16YTCh. 10 - Prob. 10.17YTCh. 10 - Prob. 10.18YTCh. 10 - Prob. 10.19YT
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- Draw all possible products formed when 2-methylbut-2-ene undergoes addition with HCl. Label them as being either the major or the minor product.arrow_forwardCan the following alkanes (A and B) be synthesized from the same alkene via a hydrogenation reaction? If this is possible, explain your rationale for why and draw the required alkene. If this is not possible, explain your rationale for why and draw the alkenes required to make each product. Clearly label which alkene would provide which alkane product. CI H3C Is it possible? YES or NO CH3 H3C- H- Rationale: H;C- CH2CH3 CI CH2CH3 A В Alkene(s) Structures:arrow_forwardOH H₂SO4 HỌC–CH2–CH2CH3 H,C=CH—CH,—CH3 + H₂O Acid-catalyzed dehydration of 1-butanol yields 1-butene as the major product. Draw curved arrows to show the movement of electrons in this step of the reaction mechanism. Arrow-pushing Instructions H2C=CH=CH2CH3 NOC XT + OH₂ HỌC–CH—CH, CH3 I H H-O-Harrow_forward
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