Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 10, Problem 10.12E
Interpretation Introduction

(a)

Interpretation:

The balanced equation for the decay reaction of the given isotope is to be stated.

Concept introduction:

The type of radioactive decay in which an alpha particle is emitted by the nucleus of an atom such that an atom of another element is produced after decay is known as alpha decay. An alpha particle is a helium nucleus. The radioactive decay in which a positron or an electron is emitted is known as beta decay.

Expert Solution
Check Mark

Answer to Problem 10.12E

The balanced equation for the decay reaction of the given isotope is,

157 63Eu01β+157 64Gd

Explanation of Solution

The given parent nucleus is 157 63Eu. The given decay process is beta emission, that is 01β particle is emitted.

The net mass is obtained by subtracting the mass of the emitted particle from the mass of the parent nucleus. Therefore, the net mass is,

Netmass=1570=157

The net charge is obtained by subtracting the charge on the emitted particle from the charge on the parent nucleus. Therefore, the net charge is,

Netcharge=63(1)=64

The nucleus that has +64 charge and mass equal to 157 is 157 64Gd. Therefore, the daughter nucleus is 157 64Gd. The balanced equation for the decay reaction of the given isotope is,

157 63Eu01β+157 64Gd

Conclusion

The balanced equation for the decay reaction of the given isotope is,

157 63Eu01β+157 64Gd

Interpretation Introduction

(b)

Interpretation:

The balanced equation for the decay reaction of the given isotope is to be stated.

Concept introduction:

The type of radioactive decay in which an alpha particle is emitted by the nucleus of an atom such that an atom of another element is produced after decay is known as alpha decay. An alpha particle is a helium nucleus. The radioactive decay in which a positron or an electron is emitted is known as beta decay.

Expert Solution
Check Mark

Answer to Problem 10.12E

The balanced equation for the decay reaction of the given isotope is,

190 78Pt42α+186 76Os

Explanation of Solution

The given parent nucleus is 190 78Pt. The given daughter nucleus is osmium-186, that is 186 76Os.

The net mass is obtained by subtracting the mass of the daughter nucleus from the mass of the parent nucleus. Therefore, the net mass is,

Netmass=190186=4

The net charge is obtained by subtracting the charge on the daughter nucleus from the charge on the parent nucleus. Therefore, the net charge is,

Netcharge=7876=2

The nucleus that has +2 charge and mass equal to 4 is an alpha particle, that is, 42α. Therefore, the emitted particle is 42α. The balanced equation for the decay reaction of the given isotope is,

190 78Pt42α+186 76Os

Conclusion

The balanced equation for the decay reaction of the given isotope is,

190 78Pt42α+186 76Os

Interpretation Introduction

(c)

Interpretation:

The balanced equation for the decay reaction of the given isotope is to be stated.

Concept introduction:

The type of radioactive decay in which an alpha particle is emitted by the nucleus of an atom such that an atom of another element is produced after decay is known as alpha decay. An alpha particle is a helium nucleus. The radioactive decay in which a positron or an electron is emitted is known as beta decay.

Expert Solution
Check Mark

Answer to Problem 10.12E

The balanced equation for the decay reaction of the given isotope is,

138 62Sm+01e138 61Pm

Explanation of Solution

The given parent nucleus is 138 62Sm. The given decay process is electron capture, that is 01e particle is captured.

The net mass is obtained by adding the mass of the captured particle and the mass of the parent nucleus. Therefore, the net mass is,

Netmass=138+0=138

The net charge is obtained by adding the charge on the emitted particle and the charge on the parent nucleus. Therefore, the net charge is,

Netcharge=62+(1)=61

The nucleus that has +61 charge and mass equal to 138 is 138 61Pm. Therefore, the daughter nucleus is 138 61Pm. The balanced equation for the decay reaction of the given isotope is,

138 62Sm+01e138 61Pm

Conclusion

The balanced equation for the decay reaction of the given isotope is,

138 62Sm+01e138 61Pm

Interpretation Introduction

(d)

Interpretation:

The balanced equation for the decay reaction of the given isotope is to be stated.

Concept introduction:

The type of radioactive decay in which an alpha particle is emitted by the nucleus of an atom such that an atom of another element is produced after decay is known as alpha decay. An alpha particle is a helium nucleus. The radioactive decay in which a positron or an electron is emitted is known as beta decay.

Expert Solution
Check Mark

Answer to Problem 10.12E

The balanced equation for the decay reaction of the given isotope is,

188 80Hg0+1β+188 79Au

Explanation of Solution

The given parent nucleus is 188 80Hg. The given daughter nucleus is Au-188, that is 188 79Au.

The net mass is obtained by subtracting the mass of the daughter nucleus from the mass of the parent nucleus. Therefore, the net mass is,

Netmass=188188=0

The net charge is obtained by subtracting the charge on the daughter nucleus from the charge on the parent nucleus. Therefore, the net charge is,

Netcharge=8079=1

The nucleus that has +1 charge and mass equal to 0 is a positron, that is, 0+1β. Therefore, the emitted particle is 0+1β. The balanced equation for the decay reaction of the given isotope is,

188 80Hg0+1β+188 79Au

Conclusion

The balanced equation for the decay reaction of the given isotope is,

188 80Hg0+1β+188 79Au

Interpretation Introduction

(e)

Interpretation:

The balanced equation for the decay reaction of the given isotope is to be stated.

Concept introduction:

The type of radioactive decay in which an alpha particle is emitted by the nucleus of an atom such that an atom of another element is produced after decay is known as alpha decay. An alpha particle is a helium nucleus. The radioactive decay in which a positron or an electron is emitted is known as beta decay.

Expert Solution
Check Mark

Answer to Problem 10.12E

The balanced equation for the decay reaction of the given isotope is,

234 90Th01β+234 91Pa

Explanation of Solution

The given parent nucleus is 234 90Th. The given decay process is beta emission, that is 01β particle is emitted.

The net mass is obtained by subtracting the mass of the emitted particle from the mass of the parent nucleus. Therefore, the net mass is,

Netmass=2340=234

The net charge is obtained by subtracting the charge on the emitted particle from the charge on the parent nucleus. Therefore, the net charge is,

Netcharge=90(1)=91

The nucleus that has +91 charge and mass equal to 234 is 234 91Pa. Therefore, the daughter nucleus is 234 91Pa. The balanced equation for the decay reaction of the given isotope is,

234 90Th01β+234 91Pa

Conclusion

The balanced equation for the decay reaction of the given isotope is,

234 90Th01β+234 91Pa

Interpretation Introduction

(f)

Interpretation:

The balanced equation for the decay reaction of the given isotope is to be stated.

Concept introduction:

The type of radioactive decay in which an alpha particle is emitted by the nucleus of an atom such that an atom of another element is produced after decay is known as alpha decay. An alpha particle is a helium nucleus. The radioactive decay in which a positron or an electron is emitted is known as beta decay.

Expert Solution
Check Mark

Answer to Problem 10.12E

The balanced equation for the decay reaction of the given isotope is,

218 85At42α+214 83Bi

Explanation of Solution

The given parent nucleus is 218 85At. The given decay process is alpha emission, that is 42α particle is emitted.

The net mass is obtained by subtracting the mass of the emitted particle from the mass of the parent nucleus. Therefore, the net mass is,

Netmass=2184=214

The net charge is obtained by subtracting the charge on the emitted particle from the charge on the parent nucleus. Therefore, the net charge is,

Netcharge=852=83

The nucleus that has +83 charge and mass equal to 214 is 214 83Bi. Therefore, the daughter nucleus is 214 83Bi. The balanced equation for the decay reaction of the given isotope is,

218 85At42α+214 83Bi

Conclusion

The balanced equation for the decay reaction of the given isotope is,

218 85At42α+214 83Bi

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Chapter 10 Solutions

Chemistry for Today: General, Organic, and Biochemistry

Ch. 10 - Prob. 10.11ECh. 10 - Prob. 10.12ECh. 10 - Prob. 10.13ECh. 10 - Prob. 10.14ECh. 10 - Prob. 10.15ECh. 10 - Prob. 10.16ECh. 10 - Prob. 10.17ECh. 10 - Prob. 10.18ECh. 10 - Prob. 10.19ECh. 10 - Prob. 10.20ECh. 10 - Prob. 10.21ECh. 10 - Prob. 10.22ECh. 10 - Prob. 10.23ECh. 10 - Prob. 10.24ECh. 10 - Prob. 10.25ECh. 10 - Prob. 10.26ECh. 10 - Prob. 10.27ECh. 10 - Prob. 10.28ECh. 10 - Prob. 10.29ECh. 10 - Prob. 10.30ECh. 10 - Prob. 10.31ECh. 10 - Prob. 10.32ECh. 10 - Prob. 10.33ECh. 10 - Prob. 10.34ECh. 10 - Prob. 10.35ECh. 10 - Prob. 10.36ECh. 10 - Prob. 10.37ECh. 10 - Prob. 10.38ECh. 10 - Prob. 10.39ECh. 10 - Prob. 10.40ECh. 10 - Prob. 10.41ECh. 10 - Prob. 10.42ECh. 10 - Prob. 10.43ECh. 10 - Prob. 10.44ECh. 10 - Prob. 10.45ECh. 10 - Prob. 10.46ECh. 10 - Prob. 10.47ECh. 10 - Prob. 10.48ECh. 10 - Prob. 10.49ECh. 10 - Prob. 10.50ECh. 10 - Prob. 10.51ECh. 10 - Prob. 10.52ECh. 10 - Prob. 10.53ECh. 10 - Prob. 10.54ECh. 10 - Prob. 10.55ECh. 10 - Prob. 10.56ECh. 10 - Prob. 10.57ECh. 10 - Prob. 10.58ECh. 10 - Prob. 10.59ECh. 10 - Prob. 10.60ECh. 10 - Prob. 10.61ECh. 10 - Prob. 10.62ECh. 10 - Prob. 10.63ECh. 10 - Prob. 10.64ECh. 10 - Prob. 10.65ECh. 10 - Prob. 10.66ECh. 10 - Prob. 10.67ECh. 10 - Prob. 10.68ECh. 10 - Prob. 10.69ECh. 10 - Prob. 10.70ECh. 10 - Prob. 10.71ECh. 10 - Prob. 10.72ECh. 10 - Prob. 10.73ECh. 10 - Prob. 10.74ECh. 10 - Prob. 10.75ECh. 10 - Prob. 10.76ECh. 10 - Prob. 10.77ECh. 10 - Prob. 10.78ECh. 10 - Prob. 10.79ECh. 10 - Prob. 10.80ECh. 10 - Prob. 10.81ECh. 10 - Prob. 10.82ECh. 10 - Prob. 10.83ECh. 10 - Prob. 10.84ECh. 10 - Prob. 10.85ECh. 10 - Prob. 10.86E
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