GENERAL,ORGANIC,+BIOCHEMISTRY
GENERAL,ORGANIC,+BIOCHEMISTRY
10th Edition
ISBN: 9781260148954
Author: Denniston
Publisher: RENT MCG
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Chapter 10, Problem 10.104QP

(a)

Interpretation Introduction

Interpretation:

Balanced equation for the complete combustion of pentane has to be written.

Concept Introduction:

Combustion reaction in general is said to be burning in presence of oxygen.  Alkanes undergo combustion to produce carbon dioxide and water along with a large amount of energy being released.  The general reaction scheme can be represented as,

  Alkane+O2CO2+H2O+heatenergy

(a)

Expert Solution
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Explanation of Solution

Given hydrocarbon is pentane.  Molecular formula of pentane is C5H12.  Alkanes and cycloalkanes on complete combustion produce carbon dioxide, water, and heat energy.  The chemical equation for the combustion of pentane can be given as,

    C5H12+O2CO2+H2O+heatenergy

Balancing carbon atom:  In the product side, only one mol of carbon atom is present while in the reactant side, five mol of carbon atoms are present.  This can be balanced by adding coefficient 5 before CO2 in the product side.  The chemical equation obtained after adding coefficient is,

    C5H12+O25CO2+H2O+heatenergy

Balancing hydrogen atoms:  In the product side, there are two mol of hydrogen atoms, while in the reactant side, there are twelve mol hydrogen atoms.  Adding coefficient 6 before water in the product side balances out hydrogen atoms on both sides of equation.  The chemical equation obtained is,

    C5H12+O25CO2+6H2O+heatenergy

Balancing oxygen atoms:  In the product side, there are sixteen mol oxygen atoms, while in the reactant side, there are only two mol oxygen atoms.  Adding coefficient 8 before O2 in the reactant side balances out the oxygen atom on both sides of equation.  This step results in balanced chemical equation.  Therefore, the balanced chemical equation can be given as,

    C5H12+8O25CO2+6H2O+heatenergy

(b)

Interpretation Introduction

Interpretation:

Balanced equation for the complete combustion of hexane has to be written.

Concept Introduction:

Refer part (a).

(b)

Expert Solution
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Explanation of Solution

Given hydrocarbon is hexane.  Molecular formula of hexane is C6H14.  Alkanes and cycloalkanes on complete combustion produce carbon dioxide, water, and heat energy.  The chemical equation for the combustion of hexane can be given as,

    C6H14+O2CO2+H2O+heatenergy

Balancing carbon atom:  In the product side, only one mol of carbon atom is present while in the reactant side, six mol of carbon atoms are present.  This can be balanced by adding coefficient 6 before CO2 in the product side.  The chemical equation obtained after adding coefficient is,

    C6H14+O26CO2+H2O+heatenergy

Balancing hydrogen atoms:  In the product side, there are two mol of hydrogen atoms, while in the reactant side, there are fourteen mol hydrogen atoms.  Adding coefficient 7 before water in the product side balances out hydrogen atoms on both sides of equation.  The chemical equation obtained is,

    C6H14+O26CO2+7H2O+heatenergy

Balancing oxygen atoms:  In the product side, there are nineteen mol oxygen atoms, while in the reactant side, there are only two mol oxygen atoms.  Adding coefficient 9.5 before O2 in the reactant side balances out the oxygen atom on both sides of equation.  This step results in balanced chemical equation.  Therefore, the balanced chemical equation can be given as,

    C6H14+9.5O26CO2+7H2O+heatenergy

Multiplying the above equation by 2 gives whole numbers for all the compounds.  This can be given as,

    2C6H14+19O212CO2+14H2O+heatenergy

(c)

Interpretation Introduction

Interpretation:

Balanced equation for the complete combustion of octane has to be written.

Concept Introduction:

Refer part (a).

(c)

Expert Solution
Check Mark

Explanation of Solution

Given hydrocarbon is octane.  Molecular formula of octane is C8H18.  Alkanes and cycloalkanes on complete combustion produce carbon dioxide, water, and heat energy.  The chemical equation for the combustion of octane can be given as,

    C8H18+O2CO2+H2O+heatenergy

Balancing carbon atom:  In the product side, only one mol of carbon atom is present while in the reactant side, eight mol of carbon atoms are present.  This can be balanced by adding coefficient 8 before CO2 in the product side.  The chemical equation obtained after adding coefficient is,

    C8H18+O28CO2+H2O+heatenergy

Balancing hydrogen atoms:  In the product side, there are two mol of hydrogen atoms, while in the reactant side, there are eighteen mol hydrogen atoms.  Adding coefficient 9 before water in the product side balances out hydrogen atoms on both sides of equation.  The chemical equation obtained is,

    C8H18+O28CO2+9H2O+heatenergy

Balancing oxygen atoms:  In the product side, there are twenty five mol oxygen atoms, while in the reactant side, there are only two mol oxygen atoms.  Adding coefficient 12.5 before O2 in the reactant side balances out the oxygen atom on both sides of equation.  This step results in balanced chemical equation.  Therefore, the balanced chemical equation can be given as,

    C8H18+12.5O28CO2+9H2O+heatenergy

Multiplying the above equation by 2 gives whole numbers for all the compounds.  This can be given as,

    2C8H18+25O216CO2+18H2O+heatenergy

(d)

Interpretation Introduction

Interpretation:

Balanced equation for the complete combustion of ethane has to be written.

Concept Introduction:

Refer part (a).

(d)

Expert Solution
Check Mark

Explanation of Solution

Given hydrocarbon is ethane.  Molecular formula of ethane is C2H6.  Alkanes and cycloalkanes on complete combustion produce carbon dioxide, water, and heat energy.  The chemical equation for the combustion of ethane can be given as,

    C2H6+O2CO2+H2O+heatenergy

Balancing carbon atom:  In the product side, only one mol of carbon atom is present while in the reactant side, two mol of carbon atoms are present.  This can be balanced by adding coefficient 2 before CO2 in the product side.  The chemical equation obtained after adding coefficient is,

    C2H6+O22CO2+H2O+heatenergy

Balancing hydrogen atoms:  In the product side, there are two mol of hydrogen atoms, while in the reactant side, there are six mol hydrogen atoms.  Adding coefficient 3 before water in the product side balances out hydrogen atoms on both sides of equation.  The chemical equation obtained is,

    C2H6+O22CO2+3H2O+heatenergy

Balancing oxygen atoms:  In the product side, there are seven mol oxygen atoms, while in the reactant side, there are only two mol oxygen atoms.  Adding coefficient 3.5 before O2 in the reactant side balances out the oxygen atom on both sides of equation.  This step results in balanced chemical equation.  Therefore, the balanced chemical equation can be given as,

    C2H6+3.5O22CO2+3H2O+heatenergy

Multiplying the above equation by 2 gives whole numbers for all the compounds.  This can be given as,

    2C2H6+7O24CO2+6H2O+heatenergy

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Chapter 10 Solutions

GENERAL,ORGANIC,+BIOCHEMISTRY

Ch. 10.4 - Name each of the following cycloalkanes using...Ch. 10.4 - Prob. 10.6PPCh. 10.4 - Prob. 10.7PPCh. 10.6 - Write a balanced equation for the complete...Ch. 10.6 - Write a balanced equation for each of the...Ch. 10.6 - Prob. 10.8QCh. 10 - Prob. 10.9QPCh. 10 - Prob. 10.10QPCh. 10 - Prob. 10.12QPCh. 10 - Prob. 10.13QPCh. 10 - Prob. 10.14QPCh. 10 - Prob. 10.15QPCh. 10 - Prob. 10.16QPCh. 10 - Prob. 10.17QPCh. 10 - Prob. 10.18QPCh. 10 - Prob. 10.19QPCh. 10 - Prob. 10.20QPCh. 10 - Prob. 10.21QPCh. 10 - Describe the major differences between ionic and...Ch. 10 - For centuries, fishermen have used shark liver oil...Ch. 10 - Prob. 10.24QPCh. 10 - Prob. 10.25QPCh. 10 - Prob. 10.26QPCh. 10 - Prob. 10.27QPCh. 10 - Prob. 10.28QPCh. 10 - Prob. 10.29QPCh. 10 - Prob. 10.30QPCh. 10 - Prob. 10.31QPCh. 10 - Prob. 10.32QPCh. 10 - Prob. 10.33QPCh. 10 - Prob. 10.34QPCh. 10 - Prob. 10.35QPCh. 10 - Prob. 10.36QPCh. 10 - Prob. 10.37QPCh. 10 - Prob. 10.38QPCh. 10 - Prob. 10.39QPCh. 10 - Prob. 10.40QPCh. 10 - Prob. 10.41QPCh. 10 - Prob. 10.42QPCh. 10 - Prob. 10.43QPCh. 10 - Prob. 10.44QPCh. 10 - Prob. 10.45QPCh. 10 - Prob. 10.46QPCh. 10 - Prob. 10.47QPCh. 10 - Prob. 10.48QPCh. 10 - Prob. 10.49QPCh. 10 - Prob. 10.50QPCh. 10 - Prob. 10.51QPCh. 10 - Prob. 10.52QPCh. 10 - Prob. 10.53QPCh. 10 - Prob. 10.54QPCh. 10 - Prob. 10.55QPCh. 10 - Prob. 10.56QPCh. 10 - Prob. 10.57QPCh. 10 - Prob. 10.58QPCh. 10 - Prob. 10.59QPCh. 10 - Prob. 10.60QPCh. 10 - Prob. 10.61QPCh. 10 - Prob. 10.62QPCh. 10 - Prob. 10.63QPCh. 10 - Prob. 10.64QPCh. 10 - Prob. 10.65QPCh. 10 - Prob. 10.66QPCh. 10 - Prob. 10.67QPCh. 10 - Prob. 10.68QPCh. 10 - Prob. 10.69QPCh. 10 - Prob. 10.70QPCh. 10 - Prob. 10.71QPCh. 10 - Prob. 10.72QPCh. 10 - Prob. 10.73QPCh. 10 - Prob. 10.74QPCh. 10 - Prob. 10.75QPCh. 10 - Prob. 10.76QPCh. 10 - Are the following names correct or incorrect? If...Ch. 10 - In your own words, describe the steps used to name...Ch. 10 - Draw the structures of the following compounds....Ch. 10 - Prob. 10.80QPCh. 10 - Prob. 10.81QPCh. 10 - Prob. 10.82QPCh. 10 - Prob. 10.83QPCh. 10 - Prob. 10.84QPCh. 10 - Prob. 10.85QPCh. 10 - Prob. 10.86QPCh. 10 - Prob. 10.87QPCh. 10 - Draw each of the following...Ch. 10 - Prob. 10.89QPCh. 10 - Prob. 10.90QPCh. 10 - Which of the following names are correct and which...Ch. 10 - Which of the following names are correct and which...Ch. 10 - Prob. 10.93QPCh. 10 - Prob. 10.94QPCh. 10 - Prob. 10.95QPCh. 10 - Prob. 10.96QPCh. 10 - What are conformational isomers? Ch. 10 - Prob. 10.98QPCh. 10 - Make a model of cyclohexane and compare the boat...Ch. 10 - Prob. 10.100QPCh. 10 - Prob. 10.101QPCh. 10 - Prob. 10.102QPCh. 10 - Prob. 10.103QPCh. 10 - Prob. 10.104QPCh. 10 - Prob. 10.105QPCh. 10 - Prob. 10.106QPCh. 10 - Prob. 10.107QPCh. 10 - Prob. 10.108QPCh. 10 - Prob. 10.109QPCh. 10 - Prob. 10.110QPCh. 10 - Prob. 10.111QPCh. 10 - Prob. 10.112QPCh. 10 - Prob. 1MCPCh. 10 - Prob. 2MCPCh. 10 - Prob. 3MCPCh. 10 - Indicate which of the following are true of...Ch. 10 - Prob. 7MCPCh. 10 - Prob. 8MCPCh. 10 - Prob. 9MCPCh. 10 - Prob. 10MCP
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