Physics Fundamentals
2nd Edition
ISBN: 9780971313453
Author: Vincent P. Coletta
Publisher: PHYSICS CURRICULUM+INSTRUCT.INC.
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 1, Problem 43P
To determine
The average velocity of particle.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A particle starts from the origin at t=0 with a
velocity of 7.8 and moves in the xy plane with a
constant acceleration of (4.4î + 3.0)) m/s² .At
the instant the particle's x coordinate is 29 m, what
are (a) its y coordinate and (b) its speed?
(a) Number
(b) Number
48
IM
Units m
Units m/s
The position of a particle moving along the x axis is given by x(t) = (4.99 m) - (3.83 m/s)t.
What is the displacement (in m) of the particle between t = 3.00 s and t = 6.00 s?
A particle is moving along a straight path with a velocity v=2x(m/s). Here x is the path taken as m. At the first instant of t=0, x=0.5 m. How long does it take for the particle to reach the position where x=3 m?
Chapter 1 Solutions
Physics Fundamentals
Ch. 1 - Prob. 1QCh. 1 - Prob. 2QCh. 1 - Prob. 3QCh. 1 - Prob. 4QCh. 1 - Prob. 5QCh. 1 - Prob. 6QCh. 1 - Prob. 7QCh. 1 - Prob. 8QCh. 1 - Prob. 9QCh. 1 - Prob. 10Q
Ch. 1 - Prob. 11QCh. 1 - Prob. 12QCh. 1 - Prob. 13QCh. 1 - Prob. 1PCh. 1 - Prob. 2PCh. 1 - Prob. 3PCh. 1 - Prob. 4PCh. 1 - Prob. 5PCh. 1 - Prob. 6PCh. 1 - Prob. 7PCh. 1 - Prob. 8PCh. 1 - Prob. 9PCh. 1 - Prob. 10PCh. 1 - Prob. 11PCh. 1 - Prob. 12PCh. 1 - Prob. 13PCh. 1 - Prob. 14PCh. 1 - Prob. 15PCh. 1 - Prob. 16PCh. 1 - Prob. 17PCh. 1 - Prob. 18PCh. 1 - Prob. 19PCh. 1 - Prob. 20PCh. 1 - Prob. 21PCh. 1 - Prob. 22PCh. 1 - Prob. 23PCh. 1 - Prob. 24PCh. 1 - Prob. 25PCh. 1 - Prob. 26PCh. 1 - Prob. 27PCh. 1 - Prob. 28PCh. 1 - Prob. 29PCh. 1 - Prob. 30PCh. 1 - Prob. 31PCh. 1 - Prob. 32PCh. 1 - Prob. 33PCh. 1 - Prob. 34PCh. 1 - Prob. 35PCh. 1 - Prob. 36PCh. 1 - Prob. 37PCh. 1 - Prob. 38PCh. 1 - Prob. 39PCh. 1 - Prob. 40PCh. 1 - Prob. 41PCh. 1 - Prob. 42PCh. 1 - Prob. 43PCh. 1 - Prob. 44PCh. 1 - Prob. 45PCh. 1 - Prob. 46PCh. 1 - Prob. 47PCh. 1 - Prob. 48PCh. 1 - Prob. 49PCh. 1 - Prob. 50PCh. 1 - Prob. 51PCh. 1 - Prob. 52PCh. 1 - Prob. 53PCh. 1 - Prob. 54PCh. 1 - Prob. 55PCh. 1 - Prob. 56PCh. 1 - Prob. 57P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Starting from the front door of a ranch house, you walk 60.0 m due east to a windmill, turn around, and then slowly walk 40.0 m west to a bench, where you sit and watch the sunrise. It takes you 28.0 s to walk from the house to the windmill and then 36.0 s to walk from the windmill to the bench. For the entire trip from the front door to the bench, what are your (a) average velocity and (b) average speed?arrow_forwardA particle starts from the origin at t 0 with a velocity of 8.0 m/s and moves in the xy plane with constant acceleration (4.0 2.0 ) m/s2.When the particle’s x coordinate is 29 m, what are its (a) y coordinate and (b) speed?arrow_forwardA particle moves along an x axis from point A to point B with average velocity v1 = 4.00 m/s through displacement Δx1 = 20.0 m. Then it moves at average velocity v2 through displacement Δx2 = 30.0 m from point B to point C. If the total time is 7.00 s, what is the value of v2?arrow_forward
- Suppose the position vector for a particle is given as a function of time by r(t)=x(t)i^+y(t)j^, with x(t)=at+b and y(t)=ct2+d, where a=1.00m/s,b=1.00m,c=0.125m/s2, and d=1.00m. (a) Calculate the average velocity during the time interval from t=2.00s to t=4.00s. (b) Determine the velocity and the speed at t=2.00sarrow_forwardThe position vector of a particle is given as r = (t^2-6t+8)i + (t^2-9)j Find the magnitude and direction of the particle’s position, velocity, and acceleration at ? = 2?. Find the magnitude and direction of the particle’s displacement, average velocity and average acceleration for the time period ? = 2? to ? = 3?.arrow_forwardDuring a 4.65 s interval, a particles coordinates change from x = 10.9m, y = 5.25m to x = 29.7m, y = - 5.25 m. Assuming the particle's velocity is constant, what will its coordinates be at the end of the next 4.65 s interval?arrow_forward
- Suppose the position vector for a particle is given as a function of time by r(t) = x(t)î + y(t)j, with x(t) = at + b and y(t) = ct2 + d, where a = 2.00 m/s, b = 1.50 m, c = 0.132 m/s?, and d = 1.02 m. (a) Calculate the average velocity during the time interval from t = 2.25 s to t = 4.25 s. v = m/s (b) Determine the velocity at t = 2.25 s. v = m/s Determine the speed at t = 2.25 s. m/sarrow_forwardA particle moves from an initial position with coordinates x = -2.0 m, y = +3.0 m, to a final position with coordinates x = +5.0 m, y = +7.0 m in a time interval of 10 s. What is the magnitude of the average velocity for this displacement?arrow_forwardAn ion's position vector is initially 7 = (-3,9 m )i + (-8.6 m )j + (-3.4 m )k, and 9.3 s later it is 7 = (-2.6 m )i + (7.3 m )ĵ + (1.0 m )R. In unit-vector notation, what is its average velocity during the 9.3 s? Number i k Units m/sarrow_forward
- Determine the particle’s position and velocity at t = 1.00 s.arrow_forwardSuppose the position vector for a particle is given as a function of time by r(t) = x(t)î + y(t)j, with x(t) = at + b and y(t) = ct + d, where a = 2.00 m/s, b = 1.15 m, c = 0.116 m/s2, and d = 1.08 m. (a) Calculate the average velocity during the time interval from t = 2.25 s to t= 3.80 s. m/s (b) Determine the velocity at t = 2.25 s. v = m/s Determine the speed at t = 2.25 s. m/sarrow_forwardA baseball is hit at a height h = 1.00 m and caught at the same height. It travels along side a wall moving up past the top of the wall 1.00 s after it is hit and then down past the top of the wall 4.00 s later at distance D = 62 m further along the wall. Use g = 9.8 m/s/s. What is the magnitude of the initial velocity?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
University Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSON
Introduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Lecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY