Holt Mcdougal Larson Algebra 2: Student Edition 2012
Holt Mcdougal Larson Algebra 2: Student Edition 2012
1st Edition
ISBN: 9780547647159
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
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Concept explainers

Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…
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Expert Solution & Answer
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Chapter 1, Problem 41REAE
Solution

To determine the time for which the ball remained in the air.

The ball remained in the air for 34−54 seconds.

Given:

Given the initial vertical velocity of the ball:

  v0=−40 ft/s .

Given the initial height of the ball:

  h0=9 ft .

Concept Used:

Equation modelling vertical motion:

The equation modelling the height ht of a vertically moving object, which had an initial velocity of v0 ft/s and initial height of h0 ft , after t seconds:

  ht=−16t2+v0t+h0 .

Quadratic formula:

Given a quadratic equation at2+bt+c=0 .

Then, the solutions of the equation:

  t=−b±b2−4ac2a .

Calculation:

Substitute v0=−40  and h0=9 in the equation ht=−16t2+v0t+h0 modelling the vertical motion:

  ht=−16t2+−40t+9ht=−16t2−40t+9 .

It is asked to determine the time for which the ball remained in air.

It is the value of t for which the height ht is nullified.

That is, it is the value of t for which ht=0 .

Substitute ht=0 in the equation ht=−16t2−40t+9 :

  0=−16t2−40t+9 .

Solve the equation 0=−16t2−40t+9 for t :

  t=−−40±−402−4−1692−16t=40±2176−32t=40±834−32t=−5+344,34−54 .

Now, t represents the time.

Hence, t must be positive.

Then, it follows that, t=34−54 .

Thus, the ball remained in the air for 34−54 seconds.

Conclusion:

The ball remained in the air for 34−54 seconds.

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Chapter 1, Problem 40REAE
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Chapter 1, Problem 42REAE

Chapter 1 Solutions

Holt Mcdougal Larson Algebra 2: Student Edition 2012

Ch. 1.1 - Prob. 1GPCh. 1.1 - Prob. 2GPCh. 1.1 - Prob. 3GPCh. 1.1 - Prob. 4GPCh. 1.1 - Prob. 5GPCh. 1.1 - Prob. 6GPCh. 1.1 - Prob. 7GPCh. 1.1 - Prob. 8GPCh. 1.1 - Prob. 1ECh. 1.1 - Prob. 2E
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Prob. 1ECh. 1.6 - Prob. 2ECh. 1.6 - Prob. 3ECh. 1.6 - Prob. 4ECh. 1.6 - Prob. 5ECh. 1.6 - Prob. 6ECh. 1.6 - Prob. 7ECh. 1.6 - Prob. 8ECh. 1.6 - Prob. 9ECh. 1.6 - Prob. 10ECh. 1.6 - Prob. 11ECh. 1.6 - Prob. 12ECh. 1.6 - Prob. 13ECh. 1.6 - Prob. 14ECh. 1.6 - Prob. 15ECh. 1.6 - Prob. 16ECh. 1.6 - Prob. 17ECh. 1.6 - Prob. 18ECh. 1.6 - Prob. 19ECh. 1.6 - Prob. 20ECh. 1.6 - Prob. 21ECh. 1.6 - Prob. 22ECh. 1.6 - Prob. 23ECh. 1.6 - Prob. 24ECh. 1.6 - Prob. 25ECh. 1.6 - Prob. 26ECh. 1.6 - Prob. 27ECh. 1.6 - Prob. 28ECh. 1.6 - Prob. 29ECh. 1.6 - Prob. 30ECh. 1.6 - Prob. 31ECh. 1.6 - Prob. 32ECh. 1.6 - Prob. 33ECh. 1.6 - Prob. 34ECh. 1.6 - Prob. 35ECh. 1.6 - Prob. 36ECh. 1.6 - Prob. 37ECh. 1.6 - Prob. 38ECh. 1.6 - Prob. 39ECh. 1.6 - Prob. 40ECh. 1.6 - Prob. 41ECh. 1.6 - Prob. 42ECh. 1.6 - Prob. 43ECh. 1.6 - Prob. 44ECh. 1.6 - Prob. 45ECh. 1.6 - Prob. 46ECh. 1.6 - Prob. 47ECh. 1.6 - Prob. 48ECh. 1.6 - Prob. 49ECh. 1.6 - Prob. 50ECh. 1.6 - Prob. 51ECh. 1.6 - Prob. 52ECh. 1.6 - Prob. 53ECh. 1.6 - Prob. 54ECh. 1.6 - 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Prob. 67PSCh. 1.7 - Prob. 68PSCh. 1.7 - Prob. 1QCh. 1.7 - Prob. 2QCh. 1.7 - Prob. 3QCh. 1.7 - Prob. 4QCh. 1.7 - Prob. 5QCh. 1.7 - Prob. 6QCh. 1.7 - Prob. 7QCh. 1.7 - Prob. 8QCh. 1.7 - Prob. 9QCh. 1.7 - Prob. 10QCh. 1.7 - Prob. 11QCh. 1.7 - Prob. 12QCh. 1.7 - Prob. 13QCh. 1.7 - Prob. 14QCh. 1.7 - Prob. 15QCh. 1.7 - Prob. 16QCh. 1.7 - Prob. 17QCh. 1.7 - Prob. 18QCh. 1.7 - Prob. 19QCh. 1.8 - Prob. 1GPCh. 1.8 - Prob. 2GPCh. 1.8 - Prob. 3GPCh. 1.8 - Prob. 4GPCh. 1.8 - Prob. 5GPCh. 1.8 - Prob. 6GPCh. 1.8 - Prob. 7GPCh. 1.8 - Prob. 8GPCh. 1.8 - Prob. 9GPCh. 1.8 - Prob. 10GPCh. 1.8 - Prob. 1ECh. 1.8 - Prob. 2ECh. 1.8 - Prob. 3ECh. 1.8 - Prob. 4ECh. 1.8 - Prob. 5ECh. 1.8 - Prob. 6ECh. 1.8 - Prob. 7ECh. 1.8 - Prob. 8ECh. 1.8 - Prob. 9ECh. 1.8 - Prob. 10ECh. 1.8 - Prob. 11ECh. 1.8 - Prob. 12ECh. 1.8 - Prob. 13ECh. 1.8 - Prob. 14ECh. 1.8 - Prob. 15ECh. 1.8 - Prob. 16ECh. 1.8 - Prob. 17ECh. 1.8 - Prob. 18ECh. 1.8 - Prob. 19ECh. 1.8 - Prob. 20ECh. 1.8 - Prob. 21ECh. 1.8 - Prob. 22ECh. 1.8 - Prob. 23ECh. 1.8 - Prob. 24ECh. 1.8 - Prob. 25ECh. 1.8 - Prob. 26ECh. 1.8 - Prob. 27ECh. 1.8 - Prob. 28ECh. 1.8 - Prob. 29ECh. 1.8 - Prob. 30ECh. 1.8 - Prob. 31ECh. 1.8 - Prob. 32ECh. 1.8 - Prob. 33ECh. 1.8 - Prob. 34ECh. 1.8 - Prob. 35ECh. 1.8 - Prob. 36ECh. 1.8 - Prob. 37ECh. 1.8 - Prob. 38ECh. 1.8 - Prob. 39ECh. 1.8 - Prob. 40ECh. 1.8 - Prob. 41ECh. 1.8 - Prob. 42ECh. 1.8 - Prob. 43ECh. 1.8 - Prob. 44ECh. 1.8 - Prob. 45ECh. 1.8 - Prob. 46ECh. 1.8 - Prob. 47ECh. 1.8 - Prob. 48ECh. 1.8 - Prob. 49ECh. 1.8 - Prob. 50ECh. 1.8 - Prob. 51ECh. 1.8 - Prob. 52ECh. 1.8 - Prob. 53ECh. 1.8 - Prob. 54ECh. 1.8 - Prob. 55ECh. 1.8 - Prob. 56ECh. 1.8 - Prob. 57ECh. 1.8 - Prob. 58ECh. 1.8 - Prob. 59ECh. 1.8 - Prob. 60ECh. 1.8 - Prob. 61ECh. 1.8 - Prob. 62ECh. 1.8 - Prob. 63ECh. 1.8 - Prob. 64ECh. 1.8 - Prob. 65ECh. 1.8 - Prob. 66ECh. 1.8 - Prob. 67ECh. 1.8 - Prob. 68PSCh. 1.8 - Prob. 69PSCh. 1.8 - Prob. 70PSCh. 1.8 - Prob. 71PSCh. 1.8 - Prob. 72PSCh. 1.8 - Prob. 73PSCh. 1.8 - Prob. 74PSCh. 1.9 - Prob. 1GPCh. 1.9 - Prob. 2GPCh. 1.9 - Prob. 3GPCh. 1.9 - Prob. 4GPCh. 1.9 - Prob. 5GPCh. 1.9 - Prob. 6GPCh. 1.9 - Prob. 7GPCh. 1.9 - Prob. 1ECh. 1.9 - Prob. 2ECh. 1.9 - Prob. 3ECh. 1.9 - Prob. 4ECh. 1.9 - Prob. 5ECh. 1.9 - Prob. 6ECh. 1.9 - Prob. 7ECh. 1.9 - Prob. 8ECh. 1.9 - Prob. 9ECh. 1.9 - Prob. 10ECh. 1.9 - Prob. 11ECh. 1.9 - Prob. 12ECh. 1.9 - Prob. 13ECh. 1.9 - Prob. 14ECh. 1.9 - Prob. 15ECh. 1.9 - Prob. 16ECh. 1.9 - Prob. 17ECh. 1.9 - Prob. 18ECh. 1.9 - Prob. 19ECh. 1.9 - Prob. 20ECh. 1.9 - Prob. 21ECh. 1.9 - Prob. 22ECh. 1.9 - Prob. 23ECh. 1.9 - Prob. 24ECh. 1.9 - Prob. 25ECh. 1.9 - Prob. 26ECh. 1.9 - Prob. 27ECh. 1.9 - Prob. 28ECh. 1.9 - Prob. 29ECh. 1.9 - Prob. 30ECh. 1.9 - Prob. 31ECh. 1.9 - Prob. 32ECh. 1.9 - Prob. 33ECh. 1.9 - Prob. 34ECh. 1.9 - Prob. 35ECh. 1.9 - Prob. 36ECh. 1.9 - Prob. 37ECh. 1.9 - Prob. 38ECh. 1.9 - Prob. 39ECh. 1.9 - Prob. 40ECh. 1.9 - Prob. 41ECh. 1.9 - Prob. 42ECh. 1.9 - Prob. 43ECh. 1.9 - Prob. 44ECh. 1.9 - Prob. 45ECh. 1.9 - Prob. 46ECh. 1.9 - Prob. 47ECh. 1.9 - Prob. 48ECh. 1.9 - Prob. 49ECh. 1.9 - Prob. 50ECh. 1.9 - Prob. 51ECh. 1.9 - Prob. 52ECh. 1.9 - Prob. 53ECh. 1.9 - Prob. 54ECh. 1.9 - Prob. 55ECh. 1.9 - Prob. 56ECh. 1.9 - Prob. 57ECh. 1.9 - Prob. 58ECh. 1.9 - Prob. 59ECh. 1.9 - Prob. 60ECh. 1.9 - Prob. 61ECh. 1.9 - Prob. 62ECh. 1.9 - Prob. 63ECh. 1.9 - Prob. 64ECh. 1.9 - Prob. 65ECh. 1.9 - Prob. 66ECh. 1.9 - Prob. 67ECh. 1.9 - Prob. 68ECh. 1.9 - Prob. 69ECh. 1.9 - Prob. 70PSCh. 1.9 - Prob. 71PSCh. 1.9 - Prob. 72PSCh. 1.9 - Prob. 73PSCh. 1.9 - Prob. 74PSCh. 1.9 - Prob. 75PSCh. 1.9 - Prob. 76PSCh. 1.9 - Prob. 77PSCh. 1.9 - Prob. 1QCh. 1.9 - Prob. 2QCh. 1.9 - Prob. 3QCh. 1.9 - Prob. 4QCh. 1.9 - Prob. 5QCh. 1.9 - Prob. 6QCh. 1.9 - Prob. 7QCh. 1.9 - Prob. 8QCh. 1.9 - Prob. 9QCh. 1.9 - Prob. 10QCh. 1.9 - Prob. 11QCh. 1.9 - Prob. 12QCh. 1.9 - Prob. 13QCh. 1.9 - Prob. 1MRPSCh. 1.9 - Prob. 2MRPSCh. 1.9 - Prob. 3MRPSCh. 1.9 - Prob. 4MRPSCh. 1.9 - Prob. 5MRPSCh. 1.9 - Prob. 6MRPSCh. 1.9 - Prob. 7MRPSCh. 1.9 - Prob. 8MRPSCh. 1.9 - Prob. 9MRPSCh. 1 - Prob. 1VECh. 1 - Prob. 2VECh. 1 - Prob. 3VECh. 1 - Prob. 4VECh. 1 - Prob. 5REAECh. 1 - Prob. 6REAECh. 1 - Prob. 7REAECh. 1 - Prob. 8REAECh. 1 - Prob. 9REAECh. 1 - Prob. 10REAECh. 1 - Prob. 11REAECh. 1 - Prob. 12REAECh. 1 - Prob. 13REAECh. 1 - Prob. 14REAECh. 1 - Prob. 15REAECh. 1 - Prob. 16REAECh. 1 - Prob. 17REAECh. 1 - Prob. 18REAECh. 1 - Prob. 19REAECh. 1 - Prob. 20REAECh. 1 - Prob. 21REAECh. 1 - Prob. 22REAECh. 1 - Prob. 23REAECh. 1 - Prob. 24REAECh. 1 - Prob. 25REAECh. 1 - Prob. 26REAECh. 1 - Prob. 27REAECh. 1 - Prob. 28REAECh. 1 - Prob. 29REAECh. 1 - Prob. 30REAECh. 1 - Prob. 31REAECh. 1 - Prob. 32REAECh. 1 - Prob. 33REAECh. 1 - Prob. 34REAECh. 1 - Prob. 35REAECh. 1 - Prob. 36REAECh. 1 - Prob. 37REAECh. 1 - Prob. 38REAECh. 1 - Prob. 39REAECh. 1 - Prob. 40REAECh. 1 - Prob. 41REAECh. 1 - Prob. 42REAECh. 1 - Prob. 43REAECh. 1 - Prob. 44REAECh. 1 - Prob. 1TCh. 1 - Prob. 2TCh. 1 - Prob. 3TCh. 1 - Prob. 4TCh. 1 - Prob. 5TCh. 1 - Prob. 6TCh. 1 - Prob. 7TCh. 1 - Prob. 8TCh. 1 - Prob. 9TCh. 1 - Prob. 10TCh. 1 - Prob. 11TCh. 1 - Prob. 12TCh. 1 - Prob. 13TCh. 1 - Prob. 14TCh. 1 - Prob. 15TCh. 1 - Prob. 16TCh. 1 - Prob. 17TCh. 1 - Prob. 18TCh. 1 - Prob. 19TCh. 1 - Prob. 20TCh. 1 - Prob. 21TCh. 1 - Prob. 22TCh. 1 - Prob. 23TCh. 1 - Prob. 24TCh. 1 - Prob. 25TCh. 1 - Prob. 26TCh. 1 - Prob. 27TCh. 1 - Prob. 28TCh. 1 - Prob. 29TCh. 1 - Prob. 30TCh. 1 - Prob. 31TCh. 1 - Prob. 1PCh. 1 - Prob. 2PCh. 1 - Prob. 1TPCh. 1 - Prob. 2TPCh. 1 - Prob. 3TPCh. 1 - Prob. 4TPCh. 1 - Prob. 5TPCh. 1 - Prob. 6TPCh. 1 - Prob. 7TPCh. 1 - Prob. 8TPCh. 1 - Prob. 9TPCh. 1 - Prob. 10TPCh. 1 - Prob. 11TPCh. 1 - Prob. 12TPCh. 1 - Prob. 13TPCh. 1 - Prob. 14TPCh. 1 - Prob. 15TPCh. 1 - Prob. 16TPCh. 1 - Prob. 17TPCh. 1 - Prob. 18TPCh. 1 - Prob. 19TPCh. 1 - Prob. 20TPCh. 1 - Prob. 21TPCh. 1 - Prob. 22TP
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