Chapter 1, Problem 1C

Explanation of Solution

Pseudo code:

//define a function reverse()

Procedure reverse()

//declare required variables

INT a[20],b[20],n.

//prompt the user to enter the number of elements

PRINT Enter the no: of elements:

//get the number of elements

GET n

//iterate a FOR loop

FOR i=0 to i<n

//prompt the use to enter the elements

PRINT Enter the elements

//get the values

GET a[i]

//iterate a FOR loop

FOR i=0 to i<n

//reverse the element

b[n-1-i]=a[i]

//iterate a FOR loop

FOR i=0 to i<n

//prompt the reversed elements

PRINT b[i]

Explanation:

The above pseudo code is used to create a function that takes an array of integers and reverse its order. In the procedure,

• Declare the procedure “reverse()”.
• Declare the variables and arrays.
• Print the user to enter the number of elements.
• Get the number of elements.
• Iterate a “for” loop up to “i<n”.
• Print to the user to enter the elements.
• Get the values to “a[i]”.
• Iterate a “for” loop up to “i<n”.
• Reverse the elements.
• Iterate a “for” loop up to “i<n”.
• Print the elements.

C++ function:

void reverse()

{

//declare the required variables

int a[20],b[20],n;

//prompt the user to enter the number of elements

cout<<"Enter the no: of elements:";

//scan for the value

cin>>n;

//iterate a for loop

for(int i=0;i<n;i++)

{

//prompt the user to enter the elements

cout<<"Enter the"<<i<<" element:";

//scan for the values

cin>>a[i];

}

//iterate a for loop

for(int i=0;i<n;i++)

{

//Reversing the elements

b[n-1-i]=a[i];

}

//iterate a for loop

for(int i=0;i<n;i++)

{

//Display of reversed elements

cout<<b[i]<<"\n";

}

}

Explanation:

The above program code is used to create a function that takes an array of integers and reverse its order. In the procedure,

• Declare the function “reverse()”.
• Declare the variables and arrays.
• Print the user to enter the number of elements.
• Get the number of elements.
• Iterate a “for” loop up to “i<n”.
  • Print to the user to enter the elements.
  • Get the values to “a[i]”...