ATKINS' PHYSICAL CHEMISTRY-ACCESS
ATKINS' PHYSICAL CHEMISTRY-ACCESS
11th Edition
ISBN: 9780198834700
Author: ATKINS
Publisher: OXF
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Chapter 1, Problem 1A.11AE

(i)

Interpretation Introduction

Interpretation: The mole fraction H2 and N2 in the given mixture at 273.15K has to be calculated.

Concept introduction: The partial pressure of any gas in a mixture of gases is calculated using the total pressure of the mixture and the mole fraction of the gas in the mixture.  This is represented by the formula given below as,

  ptotal=paxa

The mole fraction of a component is calculated using the formula given below as,

    xa=nanTotal

(ii)

Interpretation Introduction

Interpretation: The partial pressure of H2 and N2 in the given mixture at 273.15K has to be calculated.

Concept introduction: The partial pressure of any gas in a mixture of gases is calculated using the total pressure of the mixture and the mole fraction of the gas in the mixture.  This is represented by the formula given below as,

ptotal=paxa

The mole fraction of a component is calculated using the formula given below as,

    xa=nanTotal

(iii)

Interpretation Introduction

Interpretation: The total pressure of H2 and N2 in the given mixture at 273.15K has to be calculated.

Concept introduction: The partial pressure of any gas in a mixture of gases is calculated using the total pressure of the mixture and the mole fraction of the gas in the mixture.  This is represented by the formula given below as,

ptotal=paxa

The mole fraction of a component is calculated using the formula given below as,

    xa=nanTotal

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Chapter 1 Solutions

ATKINS' PHYSICAL CHEMISTRY-ACCESS

Ch. 1 - Prob. 1A.3BECh. 1 - Prob. 1A.4AECh. 1 - Prob. 1A.4BECh. 1 - Prob. 1A.5AECh. 1 - Prob. 1A.5BECh. 1 - Prob. 1A.6AECh. 1 - Prob. 1A.6BECh. 1 - Prob. 1A.7AECh. 1 - Prob. 1A.7BECh. 1 - Prob. 1A.8AECh. 1 - Prob. 1A.8BECh. 1 - Prob. 1A.9AECh. 1 - Prob. 1A.9BECh. 1 - Prob. 1A.10AECh. 1 - Prob. 1A.10BECh. 1 - Prob. 1A.11AECh. 1 - Prob. 1A.11BECh. 1 - Prob. 1A.1PCh. 1 - Prob. 1A.2PCh. 1 - Prob. 1A.3PCh. 1 - Prob. 1A.4PCh. 1 - Prob. 1A.5PCh. 1 - Prob. 1A.6PCh. 1 - Prob. 1A.7PCh. 1 - Prob. 1A.8PCh. 1 - Prob. 1A.9PCh. 1 - Prob. 1A.10PCh. 1 - Prob. 1A.11PCh. 1 - Prob. 1A.12PCh. 1 - Prob. 1A.13PCh. 1 - Prob. 1A.14PCh. 1 - Prob. 1B.1DQCh. 1 - Prob. 1B.2DQCh. 1 - Prob. 1B.3DQCh. 1 - Prob. 1B.1AECh. 1 - Prob. 1B.1BECh. 1 - Prob. 1B.2AECh. 1 - Prob. 1B.2BECh. 1 - Prob. 1B.3AECh. 1 - Prob. 1B.3BECh. 1 - Prob. 1B.4AECh. 1 - Prob. 1B.4BECh. 1 - Prob. 1B.5AECh. 1 - Prob. 1B.5BECh. 1 - Prob. 1B.6AECh. 1 - Prob. 1B.6BECh. 1 - Prob. 1B.7AECh. 1 - Prob. 1B.7BECh. 1 - Prob. 1B.8AECh. 1 - Prob. 1B.8BECh. 1 - Prob. 1B.9AECh. 1 - Prob. 1B.9BECh. 1 - Prob. 1B.1PCh. 1 - Prob. 1B.2PCh. 1 - Prob. 1B.3PCh. 1 - Prob. 1B.4PCh. 1 - Prob. 1B.5PCh. 1 - Prob. 1B.6PCh. 1 - Prob. 1B.7PCh. 1 - Prob. 1B.8PCh. 1 - Prob. 1B.9PCh. 1 - Prob. 1B.10PCh. 1 - Prob. 1B.11PCh. 1 - Prob. 1C.1DQCh. 1 - Prob. 1C.2DQCh. 1 - Prob. 1C.3DQCh. 1 - Prob. 1C.4DQCh. 1 - Prob. 1C.1AECh. 1 - Prob. 1C.1BECh. 1 - Prob. 1C.2AECh. 1 - Prob. 1C.2BECh. 1 - Prob. 1C.3AECh. 1 - Prob. 1C.3BECh. 1 - Prob. 1C.4AECh. 1 - Prob. 1C.4BECh. 1 - Prob. 1C.5AECh. 1 - Prob. 1C.5BECh. 1 - Prob. 1C.6AECh. 1 - Prob. 1C.6BECh. 1 - Prob. 1C.7AECh. 1 - Prob. 1C.7BECh. 1 - Prob. 1C.8AECh. 1 - Prob. 1C.8BECh. 1 - Prob. 1C.9AECh. 1 - Prob. 1C.9BECh. 1 - Prob. 1C.1PCh. 1 - Prob. 1C.2PCh. 1 - Prob. 1C.3PCh. 1 - Prob. 1C.4PCh. 1 - Prob. 1C.5PCh. 1 - Prob. 1C.6PCh. 1 - Prob. 1C.7PCh. 1 - Prob. 1C.8PCh. 1 - Prob. 1C.9PCh. 1 - Prob. 1C.10PCh. 1 - Prob. 1C.11PCh. 1 - Prob. 1C.12PCh. 1 - Prob. 1C.13PCh. 1 - Prob. 1C.14PCh. 1 - Prob. 1C.15PCh. 1 - Prob. 1C.16PCh. 1 - Prob. 1C.17PCh. 1 - Prob. 1C.18PCh. 1 - Prob. 1C.19PCh. 1 - Prob. 1C.20PCh. 1 - Prob. 1C.22PCh. 1 - Prob. 1C.23PCh. 1 - Prob. 1C.24PCh. 1 - Prob. 1.1IACh. 1 - Prob. 1.2IACh. 1 - Prob. 1.3IA
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY