Custom eBook for Organic Chemistry
2nd Edition
ISBN: 9798214171104
Author: Straumanis
Publisher: Cengage Custom
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Chapter 1, Problem 18CTQ
Explain how there can be two kinds of bent: “bent-109.5o” and bent-120o,” and give an exampleof each from the previous question. (Note that “bent-109.5°’ is more common than “bent-120°.”)
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Students have asked these similar questions
If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom,
the structure Y-X-Y could be abbreviated as XY,Z,.
Classify each molecule according to its shape.
Linear
Bent (x 120°) Bent (x 109°)
Trigonal
T-shaped
See-saw
Square planar
Square
pyramidal
pyramidal
Answer Bank
XY;Z2
XY,Z
XY,Z
XY,Z3
XY;Z
XY,Z,
XY,Z
XY,Z2
NOTICE THAT BOND 2 IS AN INCORRECT ANSWER.
4. Valence Bond Theory. Consider formaldehyde, H₂CO. (
a) Draw a Lewis structure of formaldehyde.
b) Draw a picture using valence bond theory showing the bonding of
formaldehyde using appropriate hybrid orbitals. (Include electrons)
c) Describe the bonding of the C-O bond and C-H bond by listing the bond
type (σ, π) and the orbitals contributing to the bonding.
C-O:
C-H:
Chapter 1 Solutions
Custom eBook for Organic Chemistry
Ch. 1 - (E) What does the number (+Z) at the center of...Ch. 1 - Prob. 2CTQCh. 1 - Prob. 3CTQCh. 1 - Prob. 4CTQCh. 1 - Prob. 5CTQCh. 1 - Prob. 6CTQCh. 1 - Prob. 7CTQCh. 1 - You hear a student from a nearby group say that...Ch. 1 - Use VSEPR to explain why the HBH bond angle of BH3...Ch. 1 - Both the HCH and HCO bond angles of H2CO...
Ch. 1 - Prob. 11CTQCh. 1 - Consider the following flat drawing of methane...Ch. 1 - Use VSEPR to assign a value of (close to) 109.5,...Ch. 1 - A student draws the picture of ammonia (NH3) in...Ch. 1 - Prob. 15CTQCh. 1 - How many central atoms does the molecule H2NCH3...Ch. 1 - Indicate the bond angle and shape about each...Ch. 1 - Explain how there can be two kinds of bent:...Ch. 1 - A student makes the following statement: “The...Ch. 1 - A student who missed this class needs to know how...Ch. 1 - Prob. 1ECh. 1 - Prob. 2ECh. 1 - Consider the incomplete valence shell...Ch. 1 - How many valence electrons does a neutral a. K...Ch. 1 - Consider the molecules AlCl3 (aluminum chloride)...Ch. 1 - Draw an example of a bent molecule with a bond...Ch. 1 - Label each atom marked with an arrow with the...Ch. 1 - a model of each of the following molecules: a....
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- Draw an example of a bent molecule with a bond angle of near 109.5°; then draw a different bentmolecule with a bond angle of about 120°.arrow_forwardMaltol contains σ bond(s) and π bond(s). (Hint: Don't forget about the bonds involved in the CH, OH, and CH3 structures) OH * HC HC CH3 O15, 3 9.3 10, 2 O 16, 2 18, 3 O 16, 2 Barrow_forwardBond Angles in an Organic Molecule II The random letter labels in this diagram of allylcyanide are to be associated with the corresponding bond angle (or other property of the nearest atom). H H H dc H- a H b C=N Match the following (but do not select any individual letter more than once): CCC angle ~109.5° HCH angle ~120º CCC angle ~120° HCH angle ~109.5° bond angle ~180° 3. 3 3 •arrow_forward
- The carbon atoms in the molecule below are labeled 1-8. Which C-C-C bond angle in the molecule would be approximately 120?arrow_forwardCompare these two structures. [0=C=N] [0=C—N: Determine whether the two represent resonance contributors of a single species or depict different substances. If two structures are not resonance contributors, explain why. Select the single best answer. O The two structures are resonance contributors of the same species. The two structures are not resonance contributors because they contain different numbers of electrons. The two structures are not resonance contributors because they contain different bond orders. O The two structures are not resonance contributors because they contain bond orders having integer values. The two structures are not resonance contributors because each structure is present in its most stable (lowest energy) configuration. The two structures are not resonance contributors because they have different arrangements of atoms. X Śarrow_forwardCH3OCH3 and CH3C(O)CH3 have similar formulas and molar masses, but their dipole moments are quite different. Predict which compound has the higher boiling point and explain why.arrow_forward
- What are all of the types of orbital overlaps that occur in the above structure. p-p overlap sp²-sp overlap s-sp² overlap sp²-sp² overlap s-sp overlap sp-sp overlap s-s overlap ---------- In cumulene, what are the C=C=C and H−C−H ideal bond angles, respectively?Enter the C=C=C bond angle followed by the H−C−H bond angle separated by a comma (no spaces, no º symbol required).arrow_forward2. Indicate which of the following molecules are polar. For those that are, indicate the direction of the molecular dipole using the formalism used in the Karty text. Br CI C-Br NH2 NH H.arrow_forwardWhich is a correct statement about the three planar aromatic ring compounds, C4H42, C5H5, C6H6? O They are all incorrect. O They are all correct. O C4H42 has a quadruply degenerate second energy level. O C5H5 has a 5-degenerate second energy level. O CoHo has a 6-fold degenerate second energy level.arrow_forward
- For each of the carbon-carbon double bonds below, state which of the following terms appropriately describes the configuration of the bond: cis, trans, E, Z. If none of the terms are appropriate, write "none". You do not have to name the compounds. Note: More than one term may be appropriate for a particular bond. ): a) b) c) H HO OHarrow_forward3. Predict (a) the approximate bond angle, (b) the hybridization around the indicated atoms (the atoms to which the arrows are drawn in the structures below). Write your answers near the corresponding labels (1 to 5) in the drawings. (Note: the lone pairs on the F atoms are omitted for clarity.) H. 1 F 2 4 F Br -F С -о-н F F 'N : 1: 2: 3: 4: 5:arrow_forwarda Use the VSEPR model to predict the bond angles and geometry about each highlighted atom: HH H-C-C-O-H II HH b C about C 109.5°, tetrahedral; about O 109.5°, bent about C 109.5°, tetrahedral; about O 180°, linear about C 120°, planar; about O 109.5°, tetrahedral about C 109.5°, bent; about O 180°, linear HH H-C-C-H I HH 109.5°, tetrahedral 120°, planar 180°, linear 109.5°, bent HO H-C-C-C-H H 120°, planar 109.5°, tetrahedral 109.5°, bentarrow_forward
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