Microelectronic Circuits (the Oxford Series In Electrical And Computer Engineering)
Microelectronic Circuits (the Oxford Series In Electrical And Computer Engineering)
8th Edition
ISBN: 9780190853464
Author: Adel S. Sedra, Kenneth C. (kc) Smith, Tony Chan Carusone, Vincent Gaudet
Publisher: Oxford University Press
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Chapter 1, Problem 1.49P
To determine

The voltage and power gain with the connected load, rms value of the largest sine wave input and the output power corresponding it.

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2. The amplifier in the figure has a resistive input and is fed with a sine wave AC signal with peak voltage v,peak= 0.5 V, and peak current i,„peak= 0.02 mA. The resulting output voltage has a RMS value v,-RMS = 4 V rms- Find the following: a) The input resistance of the amplifier b) The output power c) The supply power V, +10V d) Amplifier dissipation. Assume input AC power is negligible e) Amplifier efficiency · 10 mA Vo i, R. 10 mA 100 2 Vi V,' -10V +1
1. In a common-source amplifier, the output voltage is (a) 180° out of phase with the input (b) in phase with the input (c) taken at the source (d) taken at the drain (e) answers (a) and (c) (f) answers (a) and (d) 2. In a certain common-source (CS) amplifier, Vas = 3.2 V rms and Veg = 280 mV rms. The voltage gain is (a) 1 (b) 11.4 (c) 8.75 (d) 3.2 3. In a certain CS amplifier, Rp = 1.0 kN, Rs = 560 2, VpD = 10 V, and gm = 4500 µS. If the source resistor is completely bypassed, the voltage gain is %3! (a) 450 (b) 45 (c) 4.5 (d) 2.52 4. Ideally, the equivalent circuit of a FET contains (a) a current source in series with a resistance (b) a resistance between drain and source terminals (c) a current source between gate and source terminals (d) a current source between drain and source terminals
Using your own words and without any formula, explain: a- How we deal with the capacitors and DC voltage source when we conduct the AC analysis of an amplifier b- What is the meaning of having a negative voltage gain (for example Av= -20 )[

Chapter 1 Solutions

Microelectronic Circuits (the Oxford Series In Electrical And Computer Engineering)

Ch. 1.4 - Prob. 1.11ECh. 1.5 - Prob. 1.12ECh. 1.5 - Prob. 1.13ECh. 1.5 - Prob. 1.14ECh. 1.5 - Prob. 1.15ECh. 1.5 - Prob. 1.16ECh. 1.5 - Prob. 1.17ECh. 1.5 - Prob. 1.18ECh. 1.5 - Prob. 1.19ECh. 1.5 - Prob. 1.20ECh. 1.5 - Prob. 1.21ECh. 1.6 - Prob. 1.22ECh. 1.6 - Prob. D1.23ECh. 1.6 - Prob. D1.24ECh. 1 - Prob. 1.1PCh. 1 - Prob. 1.2PCh. 1 - Prob. 1.3PCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. D1.8PCh. 1 - Prob. D1.9PCh. 1 - Prob. 1.10PCh. 1 - Prob. 1.11PCh. 1 - Prob. D1.12PCh. 1 - Prob. D1.13PCh. 1 - Prob. D1.14PCh. 1 - Prob. 1.15PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. 1.49PCh. 1 - Prob. 1.50PCh. 1 - Prob. 1.51PCh. 1 - Prob. 1.52PCh. 1 - Prob. 1.53PCh. 1 - Prob. D1.54PCh. 1 - Prob. D1.55PCh. 1 - Prob. D1.56PCh. 1 - Prob. D1.57PCh. 1 - Prob. 1.58PCh. 1 - Prob. 1.59PCh. 1 - Prob. 1.60PCh. 1 - Prob. D1.61PCh. 1 - Prob. 1.62PCh. 1 - Prob. D1.63PCh. 1 - Prob. D1.64PCh. 1 - Prob. 1.65PCh. 1 - Prob. 1.66PCh. 1 - Prob. 1.67PCh. 1 - Prob. 1.68PCh. 1 - Prob. 1.69PCh. 1 - Prob. 1.70PCh. 1 - Prob. 1.71PCh. 1 - Prob. D1.72PCh. 1 - Prob. 1.75PCh. 1 - Prob. 1.76PCh. 1 - Prob. D1.77PCh. 1 - Prob. D1.78PCh. 1 - Prob. 1.79PCh. 1 - Prob. 1.80PCh. 1 - Prob. D1.81PCh. 1 - Prob. 1.82PCh. 1 - Prob. 1.83P
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