Fundamentals Of Engineering Thermodynamics
9th Edition
ISBN: 9781119391388
Author: MORAN, Michael J., SHAPIRO, Howard N., Boettner, Daisie D., Bailey, Margaret B.
Publisher: Wiley,
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Chapter 1, Problem 1.31P
To determine
Pressure of water at a given depth.
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The density of mercury changes approximately linearly with temperature as ρ=851.5-0.086T in lbm/ft^3 (T in degrees F), so the same pressure difference will result in a manometer reading that is influenced by temperature. If a pressure difference of 14.7 lbf/in^2 is measured in the summer at 95F and in the winter at 5F, what is the difference in height between the two measurements?
The density of mercury changes approximately linearly with temperature as ρ=851.5-0.086T in lbm/ft^3 (T in degrees F), so the same pressure difference will result in a manometer reading that is influenced by temperature. If a pressure difference of 14.7 lbf/in^2 is measured in the summer at 95F and in the winter at 5F, what is the difference in column height between the two measurements?
Consider a column of a planet's atmosphere. The planet's atmosphere is a
compressible ideal gas at rest that obeys the polytropic relation
Po
%3D
3/2
Po
3/2
where pis pressure and pis density. Here, p, and P, are the values of pressure and density,
respectively, at the planet's surface. Take z (altitude) to be positive upward with z=0 at the
surface, take R to be the gas constant for the planet's atmosphere, and take g to be the
downward acceleration due to gravity.
a)
Starting from hydrostatic balance and the polytropic relation above, derive an
expression for the pressure field, p(z), in terms of the given parameters. Leave all
parameters except the polytropic index as algebraic.
b)
Derive an expression for the density field, p(z), in terms of the given parameters.
Leave all parameters except the polytropic index as algebraic.
c)
Derive an expression for the temperature field, T(z), in terms of the given
parameters. Leave all parameters except the polytropic index as algebraic.
Chapter 1 Solutions
Fundamentals Of Engineering Thermodynamics
Ch. 1 - Prob. 1.2ECh. 1 - Prob. 1.3ECh. 1 - Prob. 1.4ECh. 1 - Prob. 1.5ECh. 1 - Prob. 1.6ECh. 1 - Prob. 1.7ECh. 1 - Prob. 1.8ECh. 1 - Prob. 1.9ECh. 1 - Prob. 1.10ECh. 1 - Prob. 1.11E
Ch. 1 - Prob. 1.12ECh. 1 - Prob. 1.13ECh. 1 - Prob. 1.14ECh. 1 - Prob. 1.1CUCh. 1 - Prob. 1.2CUCh. 1 - Prob. 1.3CUCh. 1 - Prob. 1.4CUCh. 1 - Prob. 1.5CUCh. 1 - Prob. 1.6CUCh. 1 - Prob. 1.7CUCh. 1 - Prob. 1.8CUCh. 1 - Prob. 1.9CUCh. 1 - Prob. 1.10CUCh. 1 - Prob. 1.11CUCh. 1 - Prob. 1.12CUCh. 1 - Prob. 1.13CUCh. 1 - Prob. 1.14CUCh. 1 - Prob. 1.15CUCh. 1 - Prob. 1.16CUCh. 1 - Prob. 1.17CUCh. 1 - Prob. 1.18CUCh. 1 - Prob. 1.19CUCh. 1 - Prob. 1.20CUCh. 1 - Prob. 1.21CUCh. 1 - Prob. 1.22CUCh. 1 - Prob. 1.23CUCh. 1 - Prob. 1.24CUCh. 1 - Prob. 1.25CUCh. 1 - Prob. 1.26CUCh. 1 - Prob. 1.27CUCh. 1 - Prob. 1.28CUCh. 1 - Prob. 1.29CUCh. 1 - Prob. 1.30CUCh. 1 - Prob. 1.31CUCh. 1 - Prob. 1.32CUCh. 1 - Prob. 1.33CUCh. 1 - Prob. 1.34CUCh. 1 - Prob. 1.35CUCh. 1 - Prob. 1.36CUCh. 1 - Prob. 1.37CUCh. 1 - Prob. 1.38CUCh. 1 - Prob. 1.39CUCh. 1 - Prob. 1.40CUCh. 1 - Prob. 1.41CUCh. 1 - Prob. 1.42CUCh. 1 - Prob. 1.43CUCh. 1 - Prob. 1.44CUCh. 1 - Prob. 1.45CUCh. 1 - Prob. 1.46CUCh. 1 - Prob. 1.47CUCh. 1 - Prob. 1.48CUCh. 1 - Prob. 1.49CUCh. 1 - Prob. 1.50CUCh. 1 - Prob. 1.51CUCh. 1 - Prob. 1.52CUCh. 1 - Prob. 1.53CUCh. 1 - Prob. 1.54CUCh. 1 - Prob. 1.55CUCh. 1 - Prob. 1.56CUCh. 1 - Prob. 1.57CUCh. 1 - Prob. 1.58CUCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. 1.8PCh. 1 - Prob. 1.9PCh. 1 - Prob. 1.10PCh. 1 - Prob. 1.11PCh. 1 - Prob. 1.12PCh. 1 - Prob. 1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. 1.49P
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- The density of mercury changes approximately linearly with temperature as ρ=851.5-0.086T in lbm/ft^3 (T in degrees F), so the same pressure difference will result in a manometer reading that is influenced by temperature. If a pressure difference of 14.7 lbf/in^2 is measured in the summer at 95F and in the winter at 5F, what is the difference in column height between the two measurements? what is the answer? a. 273.488 in b. 8.493 ft c. 1.899 ft d. 273.488 ftarrow_forwardThe pressure at 9.85m depth in a fluid is 102,482Pa. Calculate the density of the fluid and present the answer in Pascal with accuracy up to one decimal place. Consider 1 atm = 101325 Pa. Assume the value of gravity to be 9.8 m/s2.arrow_forwardWhat pressure force (in kN) exists on an 80-cm-diameter horizontal area at a depth 100 feet below the surface of a lake? Assume the density of the water is constant at 1000 kg/m³, and atmospheric pressure is 1.00 atm.arrow_forward
- T F The specific weight of a fluid is the product of the fluid's density and the acceleration due to gravity. Stronger surface tension leads to higher capillary rise. Absolute pressures are frequently negative. If the pressure of fluid drops below the vapor pressure of that fluid at that temperature, the fluid will cavitate. F F T F F Density can be measured in lb;/ft° in the English system of units. For a hydrostatic incompressible fluid, pressure is independent of depth. A fluid with a high bulk modulus of elasticity is more difficult to compress than one with a low bulk modulus of elasticity. Viscosity is caused, in part, by the surface tension within a fluid. A fluid can resist an applied shear stress by deforming. Pressure increases faster with depth in less dense fluids than in more dense fluids. T F F F F Farrow_forwardA manometer attached to a gas tank indicates that the pressure within is greater than the surrounding atmosphere. The manometric fluid is mercury, which has a density of 13.6 g/cm3. The manometer shows a reading of 54 cm. The atmospheric. pressure is 101 kPa, and the acceleration due to gravity is 9.8 m/s2arrow_forwardA vessel of cylindrical shape is 70 cm in diameter and 90 cm high. It contains 7 kg of a gas. The pressure measured with manometer indicates 620 mm of Hg above atmosphere when barometer reads 765 mm of Hg. Determine : (a)The absolute pressure of the gas in the vessel in bar. (b)Specific volume (c) density of the gas.arrow_forward
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- Liquid kerosene flows through a Venturi meter. The pressure of the kerosene in the pipe supports columns of kerosene that differ in height by 12 cm. Determine the difference in pressure between points a and b, in kPa. Does the pressure increase or decrease as the kerosene flows from point a to point b as the pipe diameter decreases? The atmospheric pressure is 101 kPa, Kerosene the specific volume of kerosene is 0.00122 m³/kg, and the acceleration of gravity is g = 9.81 m/s². v=0.00122 kg/m³ Pa 101 kPa g=9.81 m/s² L=12 cmarrow_forwardProve that 69.0 kPa, 7 m of water, 52 cm of mercury (SG = 13.55) are equivalent.arrow_forwardA tank contains oil (s=0.80), gasoline (s=0.90) and water (s=1). What is the pressure at a depth of 1.6, if the depths of the liquids are respectively, 0.50 m,0.60 m, and 0.80 m? Give your answer in kg/m2.arrow_forward
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