Introductory Chemistry For Today
Introductory Chemistry For Today
8th Edition
ISBN: 9781285644561
Author: Seager
Publisher: Cengage
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Convert 59.0 m359.0⁢ m3 to liters. Note that 1 mL=1 cm3.1 mL=1⁢ cm3. 59.0 m3=59.0⁢ m3=   L=
Convert 92.0 m392.0⁢ m3 to liters. Note that 1 mL=1 cm3.
Units: Include units in your answer when instructed Use SI units only in your answers For example, use Pascals not atmospheres. Numbers: Use either the normal form, such as 132 or 132.5, or the exponential form, which represents 132 as 1.32E+2, represents 5 x 104 as 5E+4 or 5E4, or represents 52 x 10-3 as 5 2E-2, unless instructed otherwise. Do not use the form 5 x 104 If your answer is positive, do not place a "+" sign before your answer. QUESTION 2 Calculate u of 1 mole of helium gas at the top of a mountain (7000 m) under the assumption that the air is just He gas with p = 1 atm at 0m and T= 300 K from 0 m to 7000 m. Calculate your answer in eV, but do not include units in your answer. Write your answer in normal form with 2 decimal places (such as X.XX or XX.XX, etc.). QUESTION 3 A gas and liquid coexist in equilibrium. The mass density pliquid = 1000 pgas Choose the correct relationship between the chemical potentials. a. Pliquid = 1000 µgas O b.Mliquid < Hgas C. Pliquid = Hgas…
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