Chapter 0, Problem 70POT

To determine

To find: the probability of odds of a value less than $0.25 of the given conditions. Write its simplest form.

Answer to Problem 70POT

  $P\left(\text{odds of greater than than 0}\text{.10}\right)=19:6$ .

Explanation of Solution

Given:

The given condition is “a value greater than

  $\$0.10$ ”.

Calculation:

Total number of jars containing pennies, nickels, dimes, and quarters is $20+15+12+3=50$ .

Total number of odd outcomes “a value greater than

  $\$0.10$ ”is $\frac{10}{100}=\frac{1}{10}$

As total number of possible outcomes is 50. Therefore, the ratio is $40:10$ .

Also, the value is less than $40 then the favorable outcomes is $20+15+3=38$

Therefore, unfavorable outcomes are

  $50-38=12$

Thus, the probability of odds of a greater than

  $\$0.10$ is

  $P\left(\text{odds of greater than than 0}\text{.10}\right)=\frac{38}{12}=\frac{19}{6}=19:6$ .

Hence, the probability of odds of a value less than $0.25 is $P\left(\text{odds of greater than than 0}\text{.10}\right)=19:6$ .