Chapter 0, Problem 54POT

To determine

To find:the volume and the surface area of the given rectangular prism.

Answer to Problem 54POT

  $V=9m^3,S.A.=27m^2$ .

Explanation of Solution

Given:

The given measurement is $\mathcal{l}=1.5m,\omega =3m,h=2m$

Concept used:

volume and the surface area of the rectangular prism is given by

  $V=\mathcal{l}\omega h;S.A.=2\mathcal{l}\omega +2\omega h+2\mathcal{l}h$

Calculation:

As it is known that volume and the surface area of the rectangular prism is

  $V=\mathcal{l}\omega h;S.A.=2\mathcal{l}\omega +2\omega h+2\mathcal{l}h$ .

Therefore,

  $\begin{array}{l}V=\mathcal{l}\omega h\\ \Rightarrow V=1.5m\times 3m\times 2m\\ \Rightarrow V=9m^3\end{array}$

And

  $\begin{array}{l}S.A.=2\mathcal{l}\omega +2\omega h+2\mathcal{l}h\\ =2\times 1.5m\times 3m+2\times 3m\times 2m+2\times 1.5m\times 2m\\ =9m^2+12m^2+6m^2=27m^2\end{array}$

Hence, the volume and the surface area of the given rectangular prism is $V=9m^3,S.A.=27m^2$ .