Complete and balance the following redox reaction in basic solution. Be sure to include the proper phases for all species within the reaction. 2- MnO4 (aq) + C₂O4² (aq) → MnO₂(s) + CO₂(g)

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Solution

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Answer 23

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Follow-up Question

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Solution

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Answer 24

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Answer 25

Follow-up Question

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Solution

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Answer 26

Follow-up Question

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Solution

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Answer 27

Follow-up Question

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Answer 28

Follow-up Question

Answer 29

Follow-up Question

Answer 30

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Answer 31

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Answer 32

Solution

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Answer 33

Solution

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Answer 34

Solution

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Answer 35

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Answer 36

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Answer 37

Follow-up Questions

Read through expert solutions to related follow-up questions below.

Follow-up Question

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Solution

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Answer 38

Read through expert solutions to related follow-up questions below.

Follow-up Question

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Solution

by Bartleby Expert

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Answer 39

Read through expert solutions to related follow-up questions below.

Answer 40

Follow-up Question

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Solution

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Answer 41

Follow-up Question

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Solution

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Answer 42

Follow-up Question

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Answer 43

Follow-up Question

Answer 44

Follow-up Question

Answer 45

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.

Answer 46

Your submitted reaction is unbalanced. In your reaction, there are 20 oxygen, 1

manganese atoms in the reactants but 24 oxygen, 2 manganese atoms in the products. Reconsider the coefficients in front of your reactants and/or products and try again. The following steps may help you balance this redox reaction in basic solution:

Split the given equation into two half-reactions: one for oxidation and one for reduction
For each half-reaction, balance all atoms except H and O on both sides of the equation by altering the coefficients.
1. Balance O by adding H2O to the appropriate side of the equations as needed
2. After adding H2O, balance H by adding
H+ to the appropriate side of the equation as needed
1. Determine the number of electrons (e) lost or gained in each half-reaction and add e to the appropriate side of the equations to balance charge.
2. Add OH to both sides of the equation to neutralize all of the H* by forming H2O
3. Cancel out water molecules that appear as both reactants and products
4. Multiply each half-reaction by whole numbers as needed to make the same number of electrons appear in both half-reactions
5. Add the two half-reactions and ensure that electrons completely cancel out.
6. Simplify the equation by cancelling out species that appear on both sides.