You have a linked list with two numbers as nodes, each of which is represented by a single digit. The digits are kept in reverse order, with the digit representing 1 at the top of the list. The two values should be added, and the function should return the total as a linked list. EXAMPLE Input: (7-> 1 -> 6) + (5 -> 9 -> 2).That is,617 + 295. Output: 2 -> 1 -> 9. That is, 912. FOLLOW UP Let's say the digits are kept in ascending order. Replicate the earlier issue. EXAMPLE lnput:(6 -> 1 -> 7) + (2 -> 9 -> 5).That is,617 + 295. Output: 9 -> 1 -> 2. That is, 912

We need a linked list to hold information about penguins in a zoo. You will need the following integers for your IntNode (see below).  I have included sample values for one of the penguins: penguin ID: 45821 penguin weight (kg): 11 penguin height (cm): 90 We now need to track the number of penguins in the zoo. I would like to propose a better way to track the size of the list.  Rather than traversing the list every time you need to know its size, why not keep a variable called listSize that increments every time you add a node to the list and decrements anytime you remove an item from the list? public class penguinList { //nested class IntNode goes here private IntNode first; private int listSize; //...the methods of penguinList class go here } Now, you just need to increment the listSize instance variable in every method that adds a node to the list. If you have any methods that removes a node from the list, decrement the listSize instance variable in those methods instead.…

You have two numbers represented by a linked list, where each node contains a singledigit. The digits are stored in reverse order, such that the 1 's digit is at the head of the list. Write afunction that adds the two numbers and returns the sum as a linked list.EXAMPLEInput: (7-> 1 -> 6) + (5 -> 9 -> 2).That is,617 + 295.Output: 2 -> 1 -> 9. That is, 912.FOLLOW UPSuppose the digits are stored in forward order. Repeat the above problem.Input: (6 -> 1 -> 7) + (2 -> 9 -> 5).That is,617 + 295.Output: 9 -> 1 -> 2. That is, 912

Java

You have two numbers represented by a linked list, where each node contains a singledigit. The digits are stored in reverse order, such that the 1 's digit is at the head of the list. Write afunction that adds the two numbers and returns the sum as a linked list.EXAMPLEInput: (7-> 1 -> 6) + (5 -> 9 -> 2).That is,617 + 295.Output: 2 -> 1 -> 9. That is, 912.FOLLOW UPSuppose the digits are stored in forward order. Repeat the above problem.Input: (6 -> 1 -> 7) + (2 -> 9 -> 5).That is,617 + 295.Output: 9 -> 1 -> 2. That is, 912.

You have two numbers represented by a linked list, where each node contains a singledigit. The digits are stored in reverse order, such that the 1 's digit is at the head of the list. Write afunction that adds the two numbers and returns the sum as a linked list.EXAMPLEInput: (7-> 1 -> 6) + (5 -> 9 -> 2).That is,617 + 295.Output: 2 -> 1 -> 9. That is, 912.FOLLOW UPSuppose the digits are stored in forward order. Repeat the above problem.Input: (6 -> 1 -> 7) + (2 -> 9 -> 5).That is,617 + 295.Output: 9 -> 1 -> 2. That is, 912.

You have two numbers represented by a linked list, where each node contains a singledigit. The digits are stored in reverse order, such that the 1 's digit is at the head of the list. Write afunction that adds the two numbers and returns the sum as a linked list.EXAMPLEInput: (7-> 1 -> 6) + (5 -> 9 -> 2).That is,617 + 295.Output: 2 -> 1 -> 9. That is, 912.FOLLOW UPSuppose the digits are stored in forward order. Repeat the above problem.Input: (6 -> 1 -> 7) + (2 -> 9 -> 5).That is,617 + 295.Output: 9 -> 1 -> 2. That is, 912.

You have two numbers represented by a linked list, where each node contains a singledigit. The digits are stored in reverse order, such that the 1 's digit is at the head of the list. Write afunction that adds the two numbers and returns the sum as a linked list.EXAMPLEInput: (7-> 1 -> 6) + (5 -> 9 -> 2).That is,617 + 295.Output: 2 -> 1 -> 9. That is, 912.FOLLOW UPSuppose the digits are stored in forward order. Repeat the above problem.Input: (6 -> 1 -> 7) + (2 -> 9 -> 5).That is,617 + 295.Output: 9 -> 1 -> 2. That is, 912

Write a program that implements a sorted list using dynamic  allocated arrays.  DataFile.txt contains the information of poker cards. C: clubs(lowest),D: diamonds, H: hearts, S:spades(highest) 2 (lowest), 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A No Joker cards Any C cards are lower than any D cards. DataFile Content(You can write the file specification into your program.): H4,C8,HJ,C9,D10,D5,DK,D2,S7,DJ,H3,H6,S10,HK,DQ,C2,CJ,C4,CQ,D8,C3,SA,S2,HQ,S8,C6,D9,S3,SQ ,C5,S4,H5,SJ,D3,H8,CK,S6,D7,S9,H2,CA,C7,H7,DA,D4,H9,D6,HA,H10,S5,C10 H4, D5, HK, D2 H4, HK, SK C9,C10 For examples, DJ means J of Diamonds;H7 means 7 of hearts. Your job Create a list by dynamic allocated array and set the size to 20 Read the first 20 cards in the first line of the file, the put them one by one into the list by implementing and using putItem(). The list must be kept sorted in ascending order. Then print out all the cards in the list in one line separating by commas. Then delete the cards indicated in the second…