x=3001 +252 8.t. 21 +2 1 + x2 #1 1, 2 Decide if this is a normal max LP (but I decided not to ask) Consider the Max LP: min w (₁20) 31 (Y/2 ≥ 0) Y₂ > (9/30) 23 2. Here is a the table form for finding the dual, but there is a couple of missing or incorrect entries that you are asked to identify below it: the value of a is max z (2₁0) (₂0) cis 21 2 1 1 b Ca 1 1 a 82 100 <80 40 20 the missing value(s) in position b is (are) no extra spaces though) 3. The objective function for the dual min is w = cy1 + dy2 + e y3 where and dis <100 80 40 and e is (as we usually write things

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Consider the Max LP:
min w
I1, I2
Decide if this is a normal max LP (but I decided not to ask)
(y₁ ≥ 0) Y₁
(Y/2 ≥ 0) Y2
(Y3 > 0) Y3
x = 3x1 + 201
8.t. 21 +2
X1 + X2
I1
2. Here is a the table form for finding the dual, but there is a couple of missing or
incorrect entries that you are asked to identify below it:
the value of a is
cis
max z
(*₁ ≥ 0) (*₂ > 0)
Ta
1
1
21
2
1
100
≤80
≤40
>0
a
2
the missing value(s) in position b is (are)
no extra spaces though)
3. The objective function for the dual min is
w = cy1 + dy2 + e y3 where
and d is
<100
<80
<40
and e is
(as we usually write things
Transcribed Image Text:Consider the Max LP: min w I1, I2 Decide if this is a normal max LP (but I decided not to ask) (y₁ ≥ 0) Y₁ (Y/2 ≥ 0) Y2 (Y3 > 0) Y3 x = 3x1 + 201 8.t. 21 +2 X1 + X2 I1 2. Here is a the table form for finding the dual, but there is a couple of missing or incorrect entries that you are asked to identify below it: the value of a is cis max z (*₁ ≥ 0) (*₂ > 0) Ta 1 1 21 2 1 100 ≤80 ≤40 >0 a 2 the missing value(s) in position b is (are) no extra spaces though) 3. The objective function for the dual min is w = cy1 + dy2 + e y3 where and d is <100 <80 <40 and e is (as we usually write things
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