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- 1-86 The specific heats of some elements at 25oC are as follows: aluminum = 0.215 cal/g · oC; carbon (graphite) = 0.170 caI/g oC; iron = 0.107 cal/g mercury = 0.033 1 caI/g oC. (a) Which element would require the smallest amount of heat to raise the temperature of 100 g of the element by 10oC? (b) If the same amount of heat needed to raise the temperature of 1 g of aluminum by 25oC were applied to 1 g of mercury, by how many degrees would its temperature be raised? (c) If a certain amount of heat is used to raise the temperature of 1.6 g of iron by 10oC, the temperature of 1 g of which element would also be raised by 10oC, using the same amount of heat?FO & H H3O+ N + H₂O, heat H3N Opleaseee helpppop
- O NH₂OH H₂of O HO-N DatenHMAC%3Def41415d9158412623399163083b2ede#10001 Spr. 2021 8 Gu HI, Leira v Sign Out Item 4 I Review | Constants | Periodic Table Alexandra decides to climb Mt. Krumpett, which is 5000 m high. She determines that this will require a total of 2250 kcal of energy for the trip. For her food supply, she decides to take nutrition bars. The label states that each bar contains 50 g of carbohydrates, 10 g of fat, and 40 g of protein. Part A How many nutrition bars should Alexandra pack? Express the number of bars numerically. > View Available Hint(s) ν ΑΣφ bars Submit Previous Answers 0V 12:333 2 1 5. 1Н + 1Н — On+. -- 4Be 4 O 2He 2Не 3 Ön 1H
- 2ev HHO H2S04 H HO leg + 2 ea O LDA/-78°Cm hw q 8Chemistry 5’G-G-C-T-A-T-T-G-A-G•G-A-T-C-C-T-G-G-A-T-G-C-C3’3’C-C-G-A-T-A-A-C-T-C-C-T-A-G•G-A-C-C-T-A-C-G-G5’ a. Give the two DNA fragments generated by the enzyme, and then calculate the binding free energy for re-association of the two, resulting fragments.b. Calculate the equilibrium constant for the formation of the uncleaved complex at 25°C in 1M NaCl.c. Calculate the equilibrium constant for association of the ‘sticky ended DNA’ fragments at 25°C in 1M NaCl.d. Determine the concentration of ds DNA (in part c) after enzyme digestion, if the starting dsDNA concentration was 10-8M.