Homework Help is Here – Start Your Trial Now!
Science
Chemistry
Ws the molecular structüre öf állicin, a pungent substance found in garlic that inhíbits the occus aureus. нн \2/ S. :0: нн yze this substance by determining the electronic and molecular geometry of each numbered atom. Yegor Larin/Shutterstock; Revell, IntroductoniCi エー 2CIH

Ws the molecular structüre öf állicin, a pungent substance found in garlic that inhíbits the occus aureus. нн \2/ S. :0: нн yze this substance by determining the electronic and molecular geometry of each numbered atom. Yegor Larin/Shutterstock; Revell, IntroductoniCi エー 2CIH

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question
Ahalyze this substance by determining the electronic and molecular geometry of each numbered atom. Atom Electronic geometry Molecular geometry 1 . 6. 7 8. 2. 4.
Transcribed Image Text:Ahalyze this substance by determining the electronic and molecular geometry of each numbered atom. Atom Electronic geometry Molecular geometry 1 . 6. 7 8. 2. 4.
MOUS SHOWS the mölecular structure of allicin, a pungent substance found in garlic that inhibits the gi occus aureus. H. нн \3, C. C. 1| 8. H. :O: нн yze this substance by determining the electronic and molecular geometry of each numbered atom. Yegor Larin/Shutterstock; Revell, Introductory Chemistry, 2e, 2021
Transcribed Image Text:MOUS SHOWS the mölecular structure of allicin, a pungent substance found in garlic that inhibits the gi occus aureus. H. нн \3, C. C. 1| 8. H. :O: нн yze this substance by determining the electronic and molecular geometry of each numbered atom. Yegor Larin/Shutterstock; Revell, Introductory Chemistry, 2e, 2021
Expert Solution
Step 1

If l.p. + sigma bonds around an atom are 4, 3, 2 then hybridization will be sp3, sp2 and sp respectively. 

Also, if no. of π-bonds around an atom are 0, 1 and 2 respectively then hybridization will be sp3, sp2 and sp respectively.

For sp3, sp2 and sp hybridization the electronic geometry will be tetrahedral, trigonal planar and linear respectively.

But, if 1 and 2 no. of l.p. are present in electronic tetrahedral geometry then molecular geometry will be pyramidal and V-shaped.

steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS