Don't use chartgpt and add explanation Write the Haskell function for the Quicksort sorting algorithm, specifying its functiontype. The function should be able to sort numbers, characters, or strings within lists. The firstelement of the list will be selected as the pivot.Add screenshots of the screen showing your script and tests.Example:sort [4, 6, 2, 5] =-[-5,2,4,6]sort "merhaba" = "aabehmr"sort ["ka", "ra", "an"]=["an", "ka", "ra"]

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Answered: Write the Haskell function for the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The mapped list pattern Our second pattern is the mapped list pattern, described in video 4 3 mapped list pattern. Often we need to write a function that takes a list as a parameter and returns a new list in which each item in the original list is "mapped" to a new item in the result list. For example, the following function takes a list of numbers as a parameter and returns a list of all the numbers squared, e.g. squares ( [1, 3, 7]) returns [1, 9, 49]. def squares (nums): "Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result Although this is just a special case of the accumulator pattern, it is so common that we give it its own name: the mapped list pattern. Consider the following function: def squares(nums): ""Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result If the main program calls print(squares ( [5, -3, 2, 7]) what is the state table for the function…
The function that will a single items to the list is Oextend (...) Oadd(...) Oappend(...) Olengthen(...)
Write a function in c++ which takes an array and a number, say item, to search and returns how many times the number (item) exists in the list. If the item does not exist, it returns 0.
Code in python Given a list, L, the function front_two creates a new list of length 2 out of the first two items in L as follows: In the new list, the second item becomes the first item, and the first item becomes the second. If L contains only one item, the first item in the new list should be the value None. If L is empty, both items in the new list should be value None. The function returns the new list. For example: Test Result L = ['a', 'b', 'c', 'd'] print(front_two(L)) ['b', 'a'] L = [] print(front_two(L)) [None, None] L = [5, 2] print(front_two(L)) [2, 5] L = [7] print(front_two(L)) [None, 7]
python help, please show all steps and include comments Write a function largerLst() that takes a list of numbers (i.e., int or float values) as a parameter and returns a new list constructed out of it. The list returned has all the values in the parameter list that are larger than the element immediately to their right, that is, larger than their right neighbor. If the parameter list is empty or there are no values larger than their right neighbor, then the function returns an empty list. Note that the last element in the list will never be included in the list returned since it does not have a right neighbor. The function should not change the parameter list in any way. Note that a correct solution to this problem must use an indexed loop That is, one that makes a call to the range() function to generate indices into the list which are used to solve the problem (Review lecture notes 8-1). A solution that does not use an indexed loop will not be accepted. Note in particular that you…
Write a function with below starting function: public static void printFirstAnd Last(ArrayList list) The approach should accomplish the following: Print "no elements" if the list is empty. Print the single element in the list if there is only one. Print the first entry in a list with more than one element, followed by a space, and then the last element.
The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…
Write a function that accepts two lists as it's only arguments. The function should return a new list containing all the elements of the two list arguments. For example, if the function was passed the lists [1, 2, 3] and [4, 5, 6], it would return a new list containing [1, 2, 3, 4, 5, 6]
Write a program with two functions: addToList(food): printList(food): Print the entire list food is used to pass a list to the function. Ask the user to input another food item. The main program will create a list: myList["apple", "oralge", "grapes] Call the function printList, using myList Call the function addToList, using myList Call the function printList, using myList
Create a function that determines the elements in a list that can be rearranged to create a sequence of numbers where each number appears exactly once. Examples Evil ([5, 1, 4, 3, 2]) - true // It can be rearranged to have a form [1, 2, 3, 4, 5] evil ([5, 1, 4, 3, 2, 8]) false IN java programming language
Complete the reverse_list() function that returns a new string list containing all contents in the parameter but in reverse order. Ex: If the input list is: ['a', 'b', 'c'] then the returned list will be: ['c', 'b', 'a'] Note: Use a for loop. DO NOT use reverse() or reversed(). This is my code so far: def reverse_list(letters): for x in (letters): letters.sort(reverse=True) return lettersif __name__ == '__main__': ch = ['a', 'b', 'c'] print(reverse_list(ch)) # Should print ['c', 'b', 'a'] When submitting I get 4/10 and it says: Test input list ['a', 'b', 'c'] returns ['c', 'b', 'a'] Your output reverse_list() function reversed array incorrectly: ['c', 'b', 'a'] reverse_list() function should have returned: ['a', 'b', 'c'] Test input list ['a', 'b', 'c', 'd'], first element of returned list is ['d'] Your output First character of returned array should be a instead of d Test empty input array TypeError: object of type 'NoneType' has no len()
Old MathJax webview Old MathJax webview In Java Some methods of the singly linked list listed below can be implemented efficiently (in different respects) (as opposed to an array or a doubly linked list), others not necessarily which are they and why? b. Implement a function to add an element before the first element. c. Implement a function to add an item after the last one element. d. Implement a function to output an element of the list. e. Implement a function to output the entire list. f. Implement a function to output the number of elements. G. Implement a function to delete an item. H. Implement a function to clear the entire list. I. Implement functionality to search for one or more students by first name, last name, matriculation number or course of study. J. Implement functionality to sort the records of the student, matriculation number and course according to two self-selected sorting methods.

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