Write code so that you take three integers a,b, and c display a^b - c.

C++

Q1: complete the function that will return the multipication of 3 given numbers - a,b,c. In [ ]: def multiply_numbers(a,b,c): II II || """insert the code that performs the operation. Use the variable 'number' to hold and return the value II || || # your code here return number

A C-string variable is an array, so we can use index operator [ ] to access individual character. True or false?

Problem Description - JAVA PROGRAMMING Use a Two-dimensional (3x3) array to solve the following problem: Write an application that inputs nine numbers, each of which is between 1 and 10, inclusive.  Display the array after the user inputs each value. Rotate/flip the array by changing places. Make the rows columns and vice versa. You have to move the elements to their new locations.   Remember to validate the input and display an error message if the user inputs invalid data.  Documentation and the screenshot(s) of the results.  Example:  1  2  3 4  5  6 7  8  9 the result will be :  1  4  7 2  5  8 3  6  9

C++   I am lost, can you help me find my way please   Finding values in vectors.   Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 2, 1, 2} and matchValue is 2 , then numMatches should be 3.Your code will be tested with the following values:* matchValue: 2, userValues: {2, 2, 1, 2} (as in the example program above)* matchValue: 0, userValues: {0, 0, 0, 0}* matchValue: 50, userValues: {10, 20, 30, 40} #include <iostream>#include <vector>using namespace std; int main() {   const int NUM_VALS = 4;   int matchValue;   unsigned int i;   int numMatches = -99; // Assign numMatches with 0 before your for loop   vector<int> userValues(NUM_VALS);    cin >> matchValue;    for (i = 0; i < userValues.size(); ++i) {      cin >> userValues.at(i);   }      cin >> numMatches;   numMatches = userVals.at(0);   for (i = 0; i < userVals.size(); ++i) {      if…