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There are two static lists A and B containing the following data:
A: 2,5,9,14,15,7,20,17,30
B: 14,2,9,13,37,8,7,28
1. Write an
2. Write an algorithm that create a list D that contains all elements of A as well as B ensuring that there is no repetition of elements
3. For Question 1, calculate the running time to create and fill the list C
Note: Only use operations of List A and List B for designing algorithms in part (a) and (b)
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- Write a function list2DigitOdd() that creates and returns a list that contain all positive 2-digit odd numbers. The function call list2DigitOdd() will return a list containing 11, 13, 15, ..., 99.in phython language Create a list that consists of all the numbers between 5 and 15. Use a for or while loop. (Create an empty list first, then append the numbers to the list in each iteration of a loop.) Insert the number -5 in index position 4 Delete the number at index 9 Append the number -7 to the list Sort the list Create another list that contains the first 5 elements of the first list, deleting this elements from the first list. Print the listsWrite a program that implements the doubly linked list clearly explain the steps for the following functions: a) Insert an element to doubly linked b) Delete an element from doubly linked list
- Python: Given the lists, Ist1 and Ist2, create a new sorted list consisting of all the elements of Ist1 that also appears in Ist2. For example, if Ist1 is 4, 3, 2, 6, 2] and Ist2 is [1, 2, 4]; then the new list. would be [2, 2, 4]. Note that duplicate elements in Ist1 that appear in Ist2 are also duplicated in the new list. Associate the new list with the variable new_list, and don't forget to. sort the new list.Q2: a. Write an algorithm that searches a sorted list of n items by dividing it into three sublists of almost n/3 items. This algorithm finds the sublist that might contain the given item and divides it into three smaller sublists of almost equal size. The algorithm repeats this process until it finds the item or concludes that the item is not in the list. Dry run the above algorithm to find the value 240. A[] = {10,15,20,60,65,110,150,220,240,245,260,290,300,460,470,501}Old MathJax webview Old MathJax webview In Java Some methods of the singly linked list listed below can be implemented efficiently (in different respects) (as opposed to an array or a doubly linked list), others not necessarily which are they and why? b. Implement a function to add an element before the first element. c. Implement a function to add an item after the last one element. d. Implement a function to output an element of the list. e. Implement a function to output the entire list. f. Implement a function to output the number of elements. G. Implement a function to delete an item. H. Implement a function to clear the entire list. I. Implement functionality to search for one or more students by first name, last name, matriculation number or course of study. J. Implement functionality to sort the records of the student, matriculation number and course according to two self-selected sorting methods.
- The function that will a single items to the list is Oextend (...) Oadd(...) Oappend(...) Olengthen(...)The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…The mapped list pattern Our second pattern is the mapped list pattern, described in video 4 3 mapped list pattern. Often we need to write a function that takes a list as a parameter and returns a new list in which each item in the original list is "mapped" to a new item in the result list. For example, the following function takes a list of numbers as a parameter and returns a list of all the numbers squared, e.g. squares ( [1, 3, 7]) returns [1, 9, 49]. def squares (nums): "Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result Although this is just a special case of the accumulator pattern, it is so common that we give it its own name: the mapped list pattern. Consider the following function: def squares(nums): ""Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result If the main program calls print(squares ( [5, -3, 2, 7]) what is the state table for the function…
- IN PYTHON: DO NOT USE ENUMERATE OR NUMPY Write the following function that returns the location of the largest element in a two-dimensional list: def locateLargest(a): The return value is a one-dimensional list that contains two elements. These two elements indicate the row and column indexes of the largest element in the two-dimensional list. Write a test program that prompts the user to enter a two dimensional list and displays the location of the largest element in the list. Sample Run: Enter the number of rows in the list: 3 Enter a row: 20.6 40 1 4 Enter a row: 5.5 3 42 4.5 Enter a row: 46 32 4.4 12.1 The loacation of the largest element is at (0,2)Several of the programming exercises in this section ask you to find the mean and median value in a list. Recall that the mean is the arithmetic average and that that median is the middle value in an ordered list. When a list contains an odd number of values, the median is the value in the middle position. When a list contains an even number of values, the median is the mean of the values in the two middle positions. Chapter 2 described the remainder operator which you can use to determine whether a number is even or odd. When a number is divided by 2, the remainder is 0 if the number is even. Design an application that accepts 10 numbers and displays them in descending order.Write the following function that tests whether a two-dimensional list has four consecutive numbers of the same value, either horizontally, vertically, or diagonally. public static boolean is ConsecutiveFour(int[][] values) Write a test program that prompts the user to enter the number of rows and columns of a two-dimensional list and then the values in the list and displays True if the list contains four consecutive numbers with the same value. Otherwise, display False. Here are some examples of the true cases: Note: You can use random generate to fill the TwoD.