We have a list. For example [2,4,6,6,8,2,12,54,15]. Without repeating the elements in the list a new list that does not repeat its elements by creating and using the function that writes Create.
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We have a list. For example [2,4,6,6,8,2,12,54,15]. Without repeating the elements in the list a new list that does not repeat its elements by creating and using the function that writes Create.
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- Write a function that accepts two lists as it's only arguments. The function should return a new list containing all the elements of the two list arguments. For example, if the function was passed the lists [1, 2, 3] and [4, 5, 6], it would return a new list containing [1, 2, 3, 4, 5, 6]Imagine we have a linked list as shown below. The ListNodehas two fields: num, an integer, and next, a pointer to the next node. The list is not sorted. Write the definition of a function that calculates and returns the sum of the numbers in the list.The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…
- Write a function with below starting function: public static void printFirstAnd Last(ArrayList list) The approach should accomplish the following: Print "no elements" if the list is empty. Print the single element in the list if there is only one. Print the first entry in a list with more than one element, followed by a space, and then the last element.You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Function Description Complete the insertNodeAtTail function in the editor below. insertNodeAtTail has the following parameters: SinglyLinkedListNode pointer head: a reference to the head of a list int data: the data value for the node to insert Returns SinglyLinkedListNode pointer: reference to the head of the modified linked list Input Format The first line contains an integer , the number of elements in the linked list.The next lines contain an integer each, the value that needs to be inserted at tail. Constraints Sample Input STDIN Function ----- -------- 5 size of linked list n = 5 141 linked list data values…Old MathJax webview Old MathJax webview In Java Some methods of the singly linked list listed below can be implemented efficiently (in different respects) (as opposed to an array or a doubly linked list), others not necessarily which are they and why? b. Implement a function to add an element before the first element. c. Implement a function to add an item after the last one element. d. Implement a function to output an element of the list. e. Implement a function to output the entire list. f. Implement a function to output the number of elements. G. Implement a function to delete an item. H. Implement a function to clear the entire list. I. Implement functionality to search for one or more students by first name, last name, matriculation number or course of study. J. Implement functionality to sort the records of the student, matriculation number and course according to two self-selected sorting methods.
- Code in python Given a list, L, the function front_two creates a new list of length 2 out of the first two items in L as follows: In the new list, the second item becomes the first item, and the first item becomes the second. If L contains only one item, the first item in the new list should be the value None. If L is empty, both items in the new list should be value None. The function returns the new list. For example: Test Result L = ['a', 'b', 'c', 'd'] print(front_two(L)) ['b', 'a'] L = [] print(front_two(L)) [None, None] L = [5, 2] print(front_two(L)) [2, 5] L = [7] print(front_two(L)) [None, 7]Write a function multiply_ends (nums) that takes a non-empty list of integers and returns the first integer multiplied by the last integer. For example, if nums is the list [5, 4, 6, 2], the function would return 5 * 2 = 10. If the list has only 1 element, the first and last elements are the same so the function should return the square of the element. For example: Test Result print(multiply_ends( [5, 4, 6, 2])) 10 Answer: (penalty regime: 0, 10, 20, ... %) 1 | Precheck CheckWrite a program that implements the doubly linked list clearly explain the steps for the following functions: a) Insert an element to doubly linked b) Delete an element from doubly linked list
- Write the following function that partitions the list using the first element, called a pivot:def partition(lst): After the partition, the elements in the list are rearranged so that all the elements before the pivot are less than or equal to the pivot and the element after the pivot are greater than the pivot. The function also returns the index where the pivot is located in the new list. For example, suppose the list is [5, 2, 9, 3, 6, 8]. After the partition, the list becomes [3, 2, 5, 9, 6, 8]. Implement the function in a way that takes len(lst) comparisons. Write a test program that prompts the user to enter a list and displays the list after the partition.5. The following function indexCounter aims to find and return all the indices of the element x in a list L. if x is not in the list L, return an empty list. However, the implementation has a flaw, so that many times it will return error message. Can you fix the flaw? def indexCounter(L, x): indexList [] startIndex = 0 while startIndex < len(L): indexList.append (L.index (x, startIndex)) startIndex = L.index (x, startIndex) + 1 return indexListWrite a function list2DigitOdd() that creates and returns a list that contain all positive 2-digit odd numbers. The function call list2DigitOdd() will return a list containing 11, 13, 15, ..., 99.