Exercise 2Write a program that works out whether if a given year is a leap year. A normal year has 365 days, leapyears have 366, with an extra day in February. The reason why we have leap years is really fascinating,this video does it more justice:https://www.youtube.com/watch?v=xX96xng7sAEThis is how you work out whether if a particular year is a leap year.on every year that is evenly divisible by 4 **except** every year that is evenly divisible by 100**unless** the year is also evenly divisible by 400e.g.Theyear2000:2000 ÷ 4 = 500 (Leap)2000 ÷ 100 = 20 (Not Leap)2000 ÷ 400 = 5 (Leap!)So theyear 2000 is a leap year.But the year 2100 is not a leap year because:2100 ÷ 4 = 525 (Leap)2100 ÷ 100 = 21 (Not Leap)2100 ÷ 400 = 5.25 (Not Leap)Example Input 12400Example Output 1Leap year.Example Input 21989Example Output 2Not leap year.

As no programming language is mentioned, it is solved using basic C++

Write a program that works out whether if a given year is a leap year. A normal year has 365 days, leap years have 366, with an extra day in February. The reason why we have leap years is really fascinating, this video does it more justice:

Write a program that works out whether if a given year is a leap year. A normal year has 365 days, leap years have 366, with an extra day in February. The reason why we have leap years is really fascinating, this video does it more justice:

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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