Why does naphthalene undergo electrophilic substitution at C1 instead of C2? Could you draw a structure for the intermediate that helps explain this?
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Why does naphthalene undergo electrophilic substitution at C1 instead of C2? Could you draw a structure for the intermediate that helps explain this?
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- Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CI H₂N OH • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na+, I, in your answer. • In cases where there is more than one answer, just draw one. Sn [FExplain why methyl trifluoroacetate, CF3CO2CH3, is more reactive than methyl acetate, CH3CO2CH3, in nucleophilic acyl substitution reactions.Explain why α-pyrone reacts with Br2 to yield a substitution product (like benzene does), rather than an addition product to one of its C–C bonds.
- Explain why α-pyrone reacts with Br2 to yield a substitution product (like benzene does), rather than an addition product to one of its C=C bonds.Explain why pentane-2,4-dione forms two alkylation products (A and B) when the number ofequivalents of base is increased from one to two.A graduate student was studying enzymatic reductions of cyclohexanones when she encountered some interesting chemistry. When she used an enzyme and NADPH to reduce the following ketone, she was surprised to find that the product was optically active. She carefully repurified the product so that no enzyme, NADPH, or other contaminants were present. Still, the product was optically active. Does the product have any asymmetric carbon atoms or other stereocenters?
- A graduate student was studying enzymatic reductions of cyclohexanones when she encountered some interesting chemistry. When she used an enzyme and NADPH to reduce the following ketone, she was surprised to find that the product was optically active. She carefully repurified the product so that no enzyme, NADPH, or other contaminants were present. Still, the product was optically active. If this reaction could be accomplished using H2 and a nickel catalyst, would the product be optically active? Explain.A certain hydrocarbon had the molecular formula C16H26 and contained two triple bonds. Ozonolysis gave CH3(CH2), CO₂H and HO₂CCH2CH2CH2CH2CO₂H as the only products. Draw a reasonable structure for this hydrocarbon. Click and drag to start drawing a structure. D:Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. 0 OH CI + H₂N • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na+, I, in your answer. In cases where there is more than one answer, just draw one. A ChemDoodle Activate Windows
- Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. CH3 CH3 H3PO4 HO, + H3C CH3 HO HO First stage in synthesis of the epoxy and polycarbonate ingredient bisphenol-A You do not have to consider stereochemistry. Include all valence lone pairs in your answer. In cases where there is more than one answer, just draw one.Explain the mechanism of the Suzuki reaction ?A graduate student was studying enzymatic reductions of cyclohexanones when she encountered some interesting chemistry. When she used an enzyme and NADPH to reduce the following ketone, she was surprised to find that the product was optically active. She carefully repurified the product so that no enzyme, NADPH, or other contaminants were present. Still, the product was optically active. Is the product capable of showing optical activity? If it is, explain how.
