Which of the following setups would you use to obtain the total number of ions in 15g of K₂Cr₂O7? 15 g K₂Cr₂07 6.022x1023 formula units K₂Cr₂07 207)x(6.07 ²) × ( ₁ 1 1n K₂Cr₂07 15 g K₂Cr₂07 1 O 1n K₂Cr₂07 294.185 g K₂Cr ₂07, x (2 0 x( 1n K₂Cr₂07 294.185 g K₂Cr₂07. 187.444 g K₂Cr₂07 1 07)×(1571 (6.022x1023 6.022x1023 formula units K₂Cr₂07 In K₂Cr₂07 1n K₂Cr₂07 15 g K₂Cr₂07, 3ions c²₂0₁). 1 formula unit K₂Cr₂07, formula units K₂ Cr ₂07 1n K₂Cr₂07 ²)x( ²) × ( ₁ 3ions 1 formula unit K ₂ Cr ₂07, 3ions 1 formula unit K ₂ Cr ₂07, 6.022x1023 formula units K₂Cr₂07 1n K₂Cr₂07 3ions 1 formula unit K ₂ Cr ₂07,

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter4: Chemical Reactions
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Which of the following setups would you use to obtain the total number of ions in 15g of K₂Cr₂O7?
(15 g K₂Cr ₂07) x
15 g K₂Cr₂07
1
(6.022 × 1023 formula units K₂Cr₂207)x(
1n K₂Cr₂07
294.185 g K₂Cr ₂07,
1n K₂Cr₂07
(29411853 (2007) (
187.444 g K₂Cr₂07
1
3ions
1 formula unit K₂Cr₂07,
1n K₂Cr₂07
15 g K₂Cr₂07)
6.022x1023 formula units K₂Cr₂07
1n K₂Cr₂07
6.022 x 1023 formula units K₂Cr ₂07
1n K₂Cr₂07
²)x(
0z) x (
3ions
1 formula unit K₂Cr₂07,
3ions
1 formula unit K₂Cr₂07)
6.022x1023 formula units K₂Cr ₂07
1n K₂Cr₂07
3ions
1 formula unit K₂ Cr ₂07,
Transcribed Image Text:Which of the following setups would you use to obtain the total number of ions in 15g of K₂Cr₂O7? (15 g K₂Cr ₂07) x 15 g K₂Cr₂07 1 (6.022 × 1023 formula units K₂Cr₂207)x( 1n K₂Cr₂07 294.185 g K₂Cr ₂07, 1n K₂Cr₂07 (29411853 (2007) ( 187.444 g K₂Cr₂07 1 3ions 1 formula unit K₂Cr₂07, 1n K₂Cr₂07 15 g K₂Cr₂07) 6.022x1023 formula units K₂Cr₂07 1n K₂Cr₂07 6.022 x 1023 formula units K₂Cr ₂07 1n K₂Cr₂07 ²)x( 0z) x ( 3ions 1 formula unit K₂Cr₂07, 3ions 1 formula unit K₂Cr₂07) 6.022x1023 formula units K₂Cr ₂07 1n K₂Cr₂07 3ions 1 formula unit K₂ Cr ₂07,
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