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- The trait represented by the colored circles and squares below is inherited as a dominant allele. This is not a sex-linked trait. Shaded individuals show the dominant trait. What is the probably genotype of each individual? 3 7 4 8 1 2 DTO 9 (10 Are there any homozygous dominant individuals in the pedigree above? How do you know? What is the probability of the trait appearing in offspring if 7 should marry 9? What is the probability of the trait appearing in offspring if 8 should marry 10?In humans, there are three alleles for blood type: A, B, and O. A and B are codominant over O. A male with type AB blood and a female with type A blood have a child. The male’s parents both had type AB blood. The female’s mother had type A blood and her father had type B blood. What is the potential phenotype of the child? A. type A (25%), type B (25%), type AB (25%), type O (25%) B. type A (25%), type B (50%), type AB (25%) C. type A (25%), type B (25%), type AB (50%) D. type A (50%), type B (25%), type AB (25%)In the following pedigree of an autosomal recessive trait, which individuals in generation III cannot be carriers? I 1 2 || 2 III 1 2 none of them can be carriers individuals III-3 and III-4 they can all potentially be carriers not enough information to determine individuals III-1 and III-2 1 3 3 4 4 5
- Picture yourself sitting at the dinner table with your family. You start comparing everyone's toes (we've all been there...). A longer second toe is dominant over having a longer first toe, which is a recessive trait. It is observed that both of your parents have longer second toes. Create one or more Punnett Squares to demonstrate the possible phenotypic and genotypic ratios of you and your siblings (the first filial generation). Using one or more Punnett Squares compare the possible phenotypic and genotypic ratios if the long second toe trait followed Mendelian inheritance. (Include ALL the steps of a Genetics problem)In humans, having extra fingers or toes is caused by a dominant allele (E). People with two recessive alleles have 5 fingers and toes on each hand or foot. What is the genotype of someone who has 5 fingers and toes on each hand or foot? What are the two different genotypes that someone with extra fingers or toes could have? If two people both had the normal number of fingers and toes, is there any chance that their children could inherit the allele for extra fingers and toes? Do a Punnett square and show your work. If a man who was heterozygous for this gene married someone who was homozygous for the recessive allele, what fraction of their children would you expect to have extra fingers or toes? Do a Punnett square and show your work.Picture yourself sitting at the dinner table with your family. You start comparing everyone's toes (we've all been there…). A longer second toe is dominant over having a longer first toe, which is a recessive trait. It is observed that both of your parents have longer second toes. Create one or more Punnett Squares to demonstrate the possible phenotypic and genotypic ratios of you and your siblings (the first filial generation). Using one or more Punnett Squares compare the possible phenotypic and genotypic ratios if the long second toe trait followed Non-Mendelian inheritance.
- Consider the following cross examining four gene in two parental line: Parent 1: A/a; B/B; D/d; E/e Parent 2: A/a; B/b; d/d; e/e Assuming independent assortment for the four genes, what fraction of progeny will be phenotypically identical to either parent 1 or parent 2? (Hint: first figure out the fraction of progeny that resembles parent 1 and parent 2 separately, then get the overall fraction.) 9/16 1/16 3/4 3/8 3/16A set of true breeding white cows were crossed with true breeding black cows to produce all brown colored offspring. If the F2 generation yielded 113 brown, 47 black and 50 white what type of inheritance would that reflect? Full credit will only be awarded when you show your work and explain your reasoning. The type of inheritance reflected is Codominant since 50% of the offsprings doesn’t reflect the color of either parent. A single new phenotype is presented when one allele of dominance and one allele for recessive trait is paired heterozygous. This shows that for a specified gene, there are three possible phenotypes that can arise from pairing, a phenotype for homozygous dominant, homozygous recessive. For heterozygous, the allele that is dominant, W, is codominant to the allele that is recessive, w, and when paired together neither is expressed but a blended, or mixed phenotype is expressed.Wooly, curly hair is due to a rare dominant allele (H) and its recessive allele (h) produces straight hair. Another gene has 2 alleles: (B) dark hair is dominant over (b) blonde. A woman with wooly, blonde hair marries a man with straight, dark hair. Their daughter has straight, blonde hair. What phenotypes and in what proportions can they expect among future children?
- An individual with a form of red-green color blindness processes a genetically inherited trait that makes it difficult to distinguish red and green color hues. Red-green color blindness tends to skin generations and it is found much more often in men than in women. If a man who was normal and a woman who is a carrier for this form of colorblindness have a child, when the probability that the child will be red-green colorbind is: -0% -25% -50% -75% -100%You are given two data sets that provide counts of F1 and F2 offspring with given genders and disease phenotypes. The data are generated from an initial parental cross. One parent displays the disease phenotype and one displays the wild-type (WT) phenotype.The WT parent always has a homozygous genotype. There are three possible modes of inheritance that underlie the generation of the data. All are monogenic. They are: (i) Autosomal Recessive. (ii) Homozygous Lethal Dominant. (iii) Autosomal Dominant. One's phenotype is determined by their genotype at the disease locus and the mode of inheritance, as we have seen with the Punnett Square. In this file you are provided with the true mode of inheritance. Your assignment is to perform a chi-square goodness of fit test on each of two F2 data sets, and make a decision, based on your statistical analyses as to which F2 data set provides greater evidence for indicating the correct mode of inheritance. Evidence is measured in the following…You are given two data sets that provide counts of F1 and F2 offspring with given genders and disease phenotypes. The data are generated from an initial parental cross. One parent displays the disease phenotype and one displays the wild-type (WT) phenotype.The WT parent always has a homozygous genotype. There are three possible modes of inheritance that underlie the generation of the data. All are monogenic. They are: (i) Autosomal Recessive. (ii) Homozygous Lethal Dominant. (iii) Autosomal Dominant. One's phenotype is determined by their genotype at the disease locus and the mode of inheritance, as we have seen with the Punnett Square. In this file you are provided with the true mode of inheritance. is to perform a chi-square goodness of fit test on each of two F2 data sets, and make a decision, based on your statistical analyses as to which F2 data set provides greater evidence for indicating the correct mode of inheritance. Evidence is measured in the following ways: the…