Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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Tay-Sachs is a recessive lethal disease in which there is neurological deterioration early in life. This
disease is rare in the population overall but is found at relatively high frequency in Ashkenazi Jews
from Eastern Europe. A woman has a maternal uncle who had the disease. Her father does not come
from a high-risk population. Her husband’s sister died of the disease at an early age. Draw the
pedigree of the individuals described. Include the genotypes where possible.
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- Based on the information shown (picture) draw the pedigree for this family in the space provided below. Make sure to indicate Lee, the proband, with an arrow and use the proper svmbol for individuals who have died from cancer. Remember to also label each generation with roman numerals.arrow_forwardClara has polydactyly, an autosomal dominant that is 80% penetrant. Clara inherited her polydactyly from her mother, her father had no polydactyly in his family. She has an extra toe on her left foot. Her husband Ralph has no polydactyly in his family. A) What is the chance that Clara will have a child that will inherit polydactyly? B) What is the chance that the child will express polydactyly. You can leave these as un-calculated equations.arrow_forwardThe pedigree below shows that inheritance of a disease that is caused by a late onset, dominant, autosomal mutation that is rare, but only 50% penetrant. The gene that is mutated in the disease is linked at a distance of 10 cm to a microsatellite marker that has alleles numbered 1, 2, and 3. The marker alleles detected in each individual are indicated below. What is the probability that individual A will develop the disease? Explain using an illustration of this occurs.arrow_forward
- Albinism, lack of pigmentation in humans, results from an autosomal recessive gene designated a. Two parents with normal pigmentation have an albino child. What is the probability that their next child will be albino? What is the probability that the next child will be an albino girl? If the child is normal, what is the probability that it will be a carrier (heterozygous) for the albino gene?arrow_forwardThe following pedigree illustrates the inheritance of a rare neurologicaldisease. What is the most likely mode of inheritance for this disorder?Explain your reasoning.arrow_forwardAlbinism in humans is autosomal and fully recessive to normal color. A couple, who are both normal, have a daughter who is albino and a son who is normal. What is the probability that their normal son is a carrier of the albinism gene?arrow_forward
- Duchenne’s muscular dystrophy (DMD) is an X-linked disease that causes progressive muscle weakness and is often fatal. “XD” represents the wild type allele, and “Xd,” the mutant allele. Jonah is XDXd Y and his brother Pete is Xd Y. Jonah and Pete BOTH have DMD of equal severity and phenotypes. You might have thought Jonah’s DMD would be less severe given his genotype. To better understand the situation, you investigate Jonah’s Xist chromosome region in his defective muscle cells. Which of the following is consistent with his phenotype? (Select all that apply.) The Xd-containing chromosome is inactive in defective muscle cells. The XD-containing chromosome has a methylated Xist promoter. The XD-containing chromosome has an unmethylated Xist promoter. The Xd-containing chromosome is active in defective muscle cells.arrow_forwardPeople with polydactyly have more than five fingers or toes on their hands or feet. Polydactyly results from an autosomal dominant genetic disorder. Draw a pedigree for a family with polydactyly, using the following information: Zack has polydactyly but his wife, Zoe does not. Zack and Zoe’s daughter Yolanda has polydactyly but their son Yogi does not. Yolanda has two children with her husband, Xavier, who does not have polydactyly: Wilma, who is normal and Wade, who has polydactyly. Use your pedigree to determine what is Zoe's genotype. A) DD B)dd C)Ddarrow_forwardIn this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…arrow_forward
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