Wooly, curly hair is due to a rare dominant allele (H) and its recessive allele (h) produces straight hair. Another gene has 2 alleles: (B) dark hair is dominant over (b) blonde. A woman with wooly, blonde hair marries a man with straight, dark hair. Their daughter has straight, blonde hair. What phenotypes and in what proportions can they expect among future children?

A1) The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and is heterozygous for hitchhikers thumb. What fraction of this couples children should have a widow's peak and a hitchhiker's thumb? 3/8 1/4 1/2 3/4 0 A2)The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and has no hitchhikers thumb. What fraction of this couple's children should have no widow's peak and a hitchhiker's thumb? 3/8 0 1/4 1/2 1/8

Red-green colorblindness is inherited in an X-linked recessive pattern in humans.  A colorblind man and a woman with normal vision have four children, and one of them is a colorblind male.   Does the mother have to be a carrier in this case?  (Yes or No) What is the probability of the next child in this family being both colorblind and male?   No, 25% Yes, 25% No, 50% Yes, 50%

Brown eyes are dominant over blue eyes. This is NOT a sex linked trait. Cross a brown eyed Color blind male (whose mother had blue eyes) with a normal blue eyed female (whose father was colorblind)

A sex-influenced trait in humans is one that affects the length of the index finger. A "short" allele is dominant in males and recessive in females. Heterozygous males have an index finger that is significantly shorter than the ring finger. By comparison, the "long" allele is dominant in females and recessive in males. The gene affecting index finger length is located on an autosome. A woman with short index fingers has children with a man who has long index fingers. What are the following probabilities? (Assume that 50% of the offspring are male and 50% are female.) A. A daughter with long index fingers B. A daughter with short index fingers C. A son with sort index fingers

In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f).  A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non‑freckled, normal visioned girl or a non-freckled, normal visioned boy?   What is the probability that the first four children born to the couple will be freckled and normal visioned girls?

Color blindness occurs in about 8% of North American men of European descent, but only about 4% of North American men of African descent. Assuming X-linked recessive inheritance for color blindness, what frequencies of color blindness would you expect in each of these populations?

The Hulk wants to have children with Black Widow. However, the Hulk is worried that his super genes will pass down to their child. Black Widow is a normal human with a genotype (Nn) and The Hulk has a mutated genotype of (nn). The green gene is recessive. Will their child have super powers?

Colorblindness is an X-linked recessive trait. The an has normal vision and the woman is colorblind. What is the probability that their daughters will be colorblind? 75%, 25%, 100%, 0%, or 50%?