Which of the following human populations are in Hardy-Weinberg Equilibrium for the MN blood type? Assume M is dominant to N. To receive full credit, you must indicate which populations are in Hardy-Weinberg Equilibrium, and show your work (including observed and expected genotypic frequencies).     Genotype Population MM MN NN 1 25 50 25 2 30 0 70 3 2 120 80 4 96 144 48

b. a. in a population. Hardy-Weinberg p+q=1 (Rr), and 16% white (rr). This population is in a Hardy-Weinberg equilibrium. 42. In a population of cattle, the following color distribution was noted: 36% red (RR), 48% roan baith p²+2pq+q² =1 Determine the frequencies of the R alleles and the r alleles? assumptions are met? What will be the distribution of genotypes in the next generation if the Hardy-Weinberg a. 36% red; 48% roan; 16% white b. 30% red; 50% roan; 20% white c. 30% red; 60% roan; 10% white d. 40% red; 40% roan; 20% white 10 u ti- sor

In a population of 265 individuals, a locus has two alleles: E and e. If 59 individuals have the ee genotype, and the locus is at Hardy-Weinberg equilibrium, what is the frequency of the EE genotype?

The absolute fitnesses of the three genotypes in a two-allele system are given as follows: Genotype Absolute Fitness AA 0.08654 Aa 0.32143 aa 0.01662 What is the strength of selection against (i.e., the selection coefficient of) the Aa genotype? (Numerical answer; please do you all your work with at least 5 digits of precision)

A population is made up of individuals where 77 have the A1A1 genotype, 65 have the A1 A2 genotype, and 123 have the A2A2 genotype. What is the allele frequency of A1? Answer to 2 decimal places.

Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…

Consider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33

List the genotypic frequencies of each genotype assuming the population is in Hardy Weinberg Equilibrium and p=0.5