A population of sea cucumbers from the maldives has the following allele frequencies for the tentacle colour gene; A= 0.7 and a=0.3. Using Hardy Weinberg equations and these allele frequencies, what are the expected genotype frequencies in the population?
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A population of sea cucumbers from the maldives has the following allele frequencies for the tentacle colour gene; A= 0.7 and a=0.3. Using Hardy Weinberg equations and these allele frequencies, what are the expected genotype frequencies in the population?
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- Consider a population in which the D locus has two alleles, D and d, with f(D) = 0.6 and f(d) = 0.4. What are the genotypic frequencies expected under Hardy-Weinberg equilibrium?In a population of 200 people, an allele F has a frequency of 84%. What is the frequency of allele f? Using the Hardy-Weinberg equation, estimate the numbers of homozygous dominant, heterozygous, and homozygous recessive genotypes. (Remember that the formula is: p2 + 2pq + q2 = 1, where p represents the dominant allele and q represents the recessive allele.) *Be sure to account for all 200 people in the population.Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So you hypothesize that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out chi-square goodness of fit test and calculate a total chi-square value of 0.03 with 1 degree of freedom (see table), what does this mean?
- Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…Consider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33If a population is in Hardy-Weinberg equilibrium for the multiple alleles A+, A and a, whose frequencies are p= 0.60 for A+, q= 0.20 for A, and r = 0.20 for a, what percentage of the population is expected to be heterozygous?
- Clines in body size have been observed in many species, such as the latitudinal cline in moose shown in Figure 8.2 (shown in the previous question). How might you determine whether a cline in body size was caused by clines in allele frequencies? Which of the following is NOT one of the strategies to test this? Group of answer choices A.) Measure and assess the morphological character in multiple individuals along the cline and statistically compare them for significant differences. B.) Swap individuals or seeds from one end of the cline with those at the other end of the cline, and vice-versa, and then measure and assess how they grow. C.) Grow or raise individuals from different parts of the cline under the same conditions, in a common garden experiment, and then measure and assess how they grow. D.) Identify the genes coding for that morphological character, sequence them in multiple individuals across the cline, and then compare them for variation in sequence, structure,…The following data were obtained from a Ghanaian population of 152 people. Blood Type Number of Individuals M 61 MN 64 N 27 Calculate the frequencies of the M and N alleles in this population. What are the expected numbers of individuals of each genotypic class in this population? Assume Hardy-Weinberg conditions. Use the chi-squared test to determine if these data fit the Hardy-Weinberg equilibrium model. The degrees of freedom for this test should be 1. Why is this appropriate?What is the expected genotype frequency of the heterozygous genotype under the Hardy-Weinberg equation P = 0.7?
- A sample of 100 individuals from a population that is dimorphic at the A locus has genotype counts as follows. AA: 30 Aa: 60 aa: 10 a) What are the allele frequencies in the population? b) What are the expected genotype frequencies, if the population were at HardyWeinberg equilibrium? c) Is the proportion of heterozygotes lower or higher than expected at Hardy-Weinberg equilibrium? What deviations from the assumptions of the model would best explain the observed difference?If the Hardy-Weinberg equation enables us to use information on genotype and allele frequencies to predict the genotype frequencies of the next generation. In a population of 100,000 people carrying the recessive allele a for albinism, there are: 100 aa albinos and 1800 Aa heterozygous carriers. What is a frequency of heterozygous carriers in the next generation? Calculate the frequency for the A allele and a allele. How this will chance the frequency of alleles in a population for the following generation?Assume that the frequency of gene B in a hypothetical population Is 0.63, that there are only two alleles (B and b) of the gee in the population, that allele B is dominant over allele b, that neither allele has a selective advantage over the other, and that the population is at equilibrium with regard to this particular gene. And how many individuals in this population are expected to be of genotype BB according to the Hardy-Weinberg formula? (Assume that the total population size is 150) 71 52 118 60 131